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anonymous
 4 years ago
PLEASE SOMEONE HELP ME.
if you were to use substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 2x+5y2z=1 x+3y+z=2 3x2y+3x=17
A. y4x=3
11y=11
B.11y=3
7y+6x=11
C.4x+11y=5
11=11
D.y=5
6x+7y=11
anonymous
 4 years ago
PLEASE SOMEONE HELP ME. if you were to use substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 2x+5y2z=1 x+3y+z=2 3x2y+3x=17 A. y4x=3 11y=11 B.11y=3 7y+6x=11 C.4x+11y=5 11=11 D.y=5 6x+7y=11

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so x from second equation will be x=23yz 2x+5y2z=1 3x2y+3z=17 hope that this is hence right,correct with 3z not with 3x before = so when x=23yz will get 2(23yz)+5y2z=1 3(23yz)2y+3z=17 46y2z+5y2z=1 69y3z2y+3z=17 y4z=3 11y=11 so from this result that y=1 so than 14z=3 so 4z=4 so z=4/(4)=1 so z=1 so than x=23(1)(1)=23+1=5+1=4 so x=4 x=4 y=1 z=1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just choose the correct answer choice A,B,C OR D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A but there need to be 4z

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0robtobey how do you say ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i typed it wrong.. let me see !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x5y2z=1 x+3y+z=2 3x2y+3x=17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Correction 3x2y+3z=17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A Mathematica solution with comments is attached.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you for the medal.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Any time... Im not a hater..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and medal for my work ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you and good luck
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