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jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^6{3(2)^k1}\] The 1 is up with the k. Find the indicated sum of the geometric series.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^6{3(2)^{k1}}\]

jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0Find the indicated sum of the geometric series.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0with so few terms i would just add them

jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0How so? And I messed up. It is 3(2). Sorry

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^6{3(2)^{k1}}=3\sum_{k=1}^6{(2)^{k1}}\] \[=3(12+48+1632)\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^63(2)^{k1}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^63(2)^{k1}=3\sum_{k=1}^6(2)^{k1}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0\[3\sum_{k=1}^6(2)^{k1}=3(1+2+4+8+16+32)=3(63)\] if my arithmetic is correct

jesusfreak
 3 years ago
Best ResponseYou've already chosen the best response.0Yes! Thank you so much satellite73!!!! :)
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