Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

davian

  • 4 years ago

is someone willing to work through thesse three problems with me?

  • This Question is Closed
  1. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1 Attachment
  2. moneybird
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    answer or how to do it?

  3. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    both if your willing?..

  4. moneybird
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1324500309657:dw|

  5. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    which one is that?

  6. moneybird
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    question#8 the answer is 15/sqrt(2) = 15 sqrt(2) /2

  7. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok thank you

  8. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how do you do number 9?

  9. moneybird
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1324500519869:dw|

  10. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thank you number 10?

  11. moneybird
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    x = 6 sqrt(2) y = 4 sqrt(3) z = 8 sqrt(3)

  12. davian
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks so much

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy