So a graph had points that are not connected and the question is "Describe and correct the error in classifying the domain". The points are: (1,5)(2,10)(3,15)(4,20)

- Anikate

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- chestercat

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- Mertsj

Would have to see the graph.

- Anikate

can you graph it on a paper near u plz, I really need help

- anonymous

what are you not understanding? looks to me y=5x

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## More answers

- Mertsj

The question is to describe and correct the error in classifying the domain. So what is the description and classification of the domain?

- Anikate

Huh? r u asking me a question or answer that other person

- Mertsj

The domain of the points you gave is {1,2,3,4}

- Anikate

yup

- Mertsj

Well I was going to try to help you but I will turn you over to the superior intelligence of "theabsurd"

- anonymous

I'm asking you Anikate, what's the problem?

- Anikate

lets me say it again

- anonymous

@mertsj I'm only good at algebra and a bit of geometry, i'm far from skilled in math.

- Anikate

- Anikate

The points are graphed in the textbook where I got this question from

- anonymous

Ok I don't understand what needs to be done.

- Anikate

I need to correct the graph and I also forgot to say one thing " The domain is continuous"

- Anikate

Graph the question on a paper first then solve it

- Mertsj

Ok. So let's start over now.

- Anikate

The domain is continuous

- Mertsj

The problem you posted said to correct the error.

- Anikate

yup

- Mertsj

Can you correct an error if you don't know what the error is?

- Anikate

that's what I'm supposed to do

- Anikate

idk the error itself

- Mertsj

First the error must be identified.

- Anikate

yup, bulls eye

- Mertsj

So all you have given is 4 ordered pairs.

- Anikate

yup and the x axis goes up to 5 and the y axis goes up to . Graph it on a paper it will make it easier

- Anikate

y axis goes up to 25

- Mertsj

These ordered pairs contain no errors. So there must be more to the problem or you have mis-stated the problem or something.

- Mertsj

Because there is nothing to correct from what you have posted.

- Mertsj

Yes. I can easily graph those ordered pairs but what good would that do? That would not show me an error to correct.

- Anikate

dont leave I'm going to post a picture

- Mertsj

ok

- Anikate

|dw:1324515583912:dw| the scribbled part id the part we do not need the graph also extends into the negatives.

- Anikate

the graph also extends into the negative

- Anikate

but only till -5 for y axis and -1 for x axis

- Mertsj

I do not know how to make you understand that you have to post the entire problem. I could easily have graphed those ordered pairs myself but that GIVES ME NO ERROR TO IDENTIFY AND CORRECT!!! WHAT IS THE REST OF THE PROBLEM???????

- Anikate

Can you plz give me an example of a continuous line on a graph with points plz

- Mertsj

|dw:1324516284730:dw|

- Anikate

oh ok now I get it

- Anikate

I got the anwer

- Anikate

There should only be 2 end points

- Anikate

thx buddy

- Mertsj

There are no endpoints on a continuous line.

- Mertsj

I just didn't put all 4 points on the line because it was easier not to.

- Anikate

then what is a discrete line

- Anikate

The attachment is the picture and right beside the picture there is a question that says Describe and correct the eerror in classifying the domain.

##### 1 Attachment

- Anikate

Remember when you said that the question is in complete. What part is incomplete?

- Mertsj

Well, by golly, you finally posted the entire problem. It's a miracle. And it only took an hour.

- Mertsj

Do you see that the graph shows exactly 4 points?

- Anikate

yeah

- Mertsj

Do you understand that the domain of those 4 points is {1,2,3,4} ?

- Anikate

yeah?

- Mertsj

Do you see that the caption of the graph says that the domain in continuous?

- Anikate

yeah I said that

- Anikate

and that's when I got my answer

- Mertsj

Do you think, when you look at the graph, that that caption is true?

- Anikate

no

- Mertsj

Do you think that might be the error that you are supposed to correct?

- Anikate

yes, but in a continuous line is it neccessary to have 2 point or is it neccessary to connect the line

- Mertsj

The domain is described as "continuous".

- Mertsj

That is not true.

- Anikate

yes so, how do u know?

- Mertsj

The problem said to describe and correct the error.

- Mertsj

The description of the error is that the domain is not continuous.

- Mertsj

The correction of the error is that the domain is discrete.

- Anikate

yes, but how do u explain that? do u have proof

- Anikate

what in the graph tells u that

- Mertsj

If the domain were continuous, there would be a point whose x value is 1/2 and 3/4 and 1.5 and 50, and 900 and -8 and -30.6 and.....

- Mertsj

So since I can name numbers which are not in the domain, I know the domain is NOT continuous.

- Anikate

like 5?

- Mertsj

Any number you want to name, sweetheart, except 1,2,3,4

- Anikate

ok so 5 is ok right?

- Mertsj

How are you going to answer the question?

- Mertsj

Post your answer and I will see if it is right.

- Anikate

k brb

- Anikate

just a minute

- Anikate

r u still there?

- Anikate

r u still there?

##### 1 Attachment

- Anikate

This is my answer

- Anikate

r u still there?

- Anikate

Hello? brb

- Mertsj

So you have made the graph match the description. I think the problem said to correct the description. Therefore, I think you should have said

- Mertsj

"The domain in not continuous. The domain in discrete. If the domain were continuous, the graph would be a line."

- Anikate

r u still there?

- Anikate

I'm even supposed to graph it, but thanks

- Mertsj

"Describe and correct the error in classifying the domain". That was the question you were supposed to answer. Nowhere does it mention making the graph match the description.

- Anikate

r u still there?

- Anikate

my annoying teacher told me to

- Mertsj

yes

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