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Anikate

  • 2 years ago

So a graph had points that are not connected and the question is "Describe and correct the error in classifying the domain". The points are: (1,5)(2,10)(3,15)(4,20)

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  1. Mertsj
    • 2 years ago
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    Would have to see the graph.

  2. Anikate
    • 2 years ago
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    can you graph it on a paper near u plz, I really need help

  3. theabsurd
    • 2 years ago
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    what are you not understanding? looks to me y=5x

  4. Mertsj
    • 2 years ago
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    The question is to describe and correct the error in classifying the domain. So what is the description and classification of the domain?

  5. Anikate
    • 2 years ago
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    Huh? r u asking me a question or answer that other person

  6. Mertsj
    • 2 years ago
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    The domain of the points you gave is {1,2,3,4}

  7. Anikate
    • 2 years ago
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    yup

  8. Mertsj
    • 2 years ago
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    Well I was going to try to help you but I will turn you over to the superior intelligence of "theabsurd"

  9. theabsurd
    • 2 years ago
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    I'm asking you Anikate, what's the problem?

  10. Anikate
    • 2 years ago
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    lets me say it again

  11. theabsurd
    • 2 years ago
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    @mertsj I'm only good at algebra and a bit of geometry, i'm far from skilled in math.

  12. Anikate
    • 2 years ago
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    So a graph had points that are not connected and the question is "Describe and correct the error in classifying the domain". The points are: (1,5)(2,10)(3,15)(4,20)

  13. Anikate
    • 2 years ago
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    The points are graphed in the textbook where I got this question from

  14. theabsurd
    • 2 years ago
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    Ok I don't understand what needs to be done.

  15. Anikate
    • 2 years ago
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    I need to correct the graph and I also forgot to say one thing " The domain is continuous"

  16. Anikate
    • 2 years ago
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    Graph the question on a paper first then solve it

  17. Mertsj
    • 2 years ago
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    Ok. So let's start over now.

  18. Anikate
    • 2 years ago
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    The domain is continuous

  19. Mertsj
    • 2 years ago
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    The problem you posted said to correct the error.

  20. Anikate
    • 2 years ago
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    yup

  21. Mertsj
    • 2 years ago
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    Can you correct an error if you don't know what the error is?

  22. Anikate
    • 2 years ago
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    that's what I'm supposed to do

  23. Anikate
    • 2 years ago
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    idk the error itself

  24. Mertsj
    • 2 years ago
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    First the error must be identified.

  25. Anikate
    • 2 years ago
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    yup, bulls eye

  26. Mertsj
    • 2 years ago
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    So all you have given is 4 ordered pairs.

  27. Anikate
    • 2 years ago
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    yup and the x axis goes up to 5 and the y axis goes up to . Graph it on a paper it will make it easier

  28. Anikate
    • 2 years ago
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    y axis goes up to 25

  29. Mertsj
    • 2 years ago
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    These ordered pairs contain no errors. So there must be more to the problem or you have mis-stated the problem or something.

  30. Mertsj
    • 2 years ago
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    Because there is nothing to correct from what you have posted.

  31. Mertsj
    • 2 years ago
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    Yes. I can easily graph those ordered pairs but what good would that do? That would not show me an error to correct.

  32. Anikate
    • 2 years ago
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    dont leave I'm going to post a picture

  33. Mertsj
    • 2 years ago
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    ok

  34. Anikate
    • 2 years ago
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    |dw:1324515583912:dw| the scribbled part id the part we do not need the graph also extends into the negatives.

  35. Anikate
    • 2 years ago
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    the graph also extends into the negative

  36. Anikate
    • 2 years ago
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    but only till -5 for y axis and -1 for x axis

  37. Mertsj
    • 2 years ago
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    I do not know how to make you understand that you have to post the entire problem. I could easily have graphed those ordered pairs myself but that GIVES ME NO ERROR TO IDENTIFY AND CORRECT!!! WHAT IS THE REST OF THE PROBLEM???????

  38. Anikate
    • 2 years ago
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    Can you plz give me an example of a continuous line on a graph with points plz

  39. Mertsj
    • 2 years ago
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    |dw:1324516284730:dw|

  40. Anikate
    • 2 years ago
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    oh ok now I get it

  41. Anikate
    • 2 years ago
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    I got the anwer

  42. Anikate
    • 2 years ago
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    There should only be 2 end points

  43. Anikate
    • 2 years ago
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    thx buddy

  44. Mertsj
    • 2 years ago
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    There are no endpoints on a continuous line.

  45. Mertsj
    • 2 years ago
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    I just didn't put all 4 points on the line because it was easier not to.

  46. Anikate
    • 2 years ago
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    then what is a discrete line

  47. Anikate
    • 2 years ago
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    The attachment is the picture and right beside the picture there is a question that says Describe and correct the eerror in classifying the domain.

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  48. Anikate
    • 2 years ago
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    Remember when you said that the question is in complete. What part is incomplete?

  49. Mertsj
    • 2 years ago
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    Well, by golly, you finally posted the entire problem. It's a miracle. And it only took an hour.

  50. Mertsj
    • 2 years ago
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    Do you see that the graph shows exactly 4 points?

  51. Anikate
    • 2 years ago
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    yeah

  52. Mertsj
    • 2 years ago
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    Do you understand that the domain of those 4 points is {1,2,3,4} ?

  53. Anikate
    • 2 years ago
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    yeah?

  54. Mertsj
    • 2 years ago
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    Do you see that the caption of the graph says that the domain in continuous?

  55. Anikate
    • 2 years ago
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    yeah I said that

  56. Anikate
    • 2 years ago
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    and that's when I got my answer

  57. Mertsj
    • 2 years ago
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    Do you think, when you look at the graph, that that caption is true?

  58. Anikate
    • 2 years ago
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    no

  59. Mertsj
    • 2 years ago
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    Do you think that might be the error that you are supposed to correct?

  60. Anikate
    • 2 years ago
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    yes, but in a continuous line is it neccessary to have 2 point or is it neccessary to connect the line

  61. Mertsj
    • 2 years ago
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    The domain is described as "continuous".

  62. Mertsj
    • 2 years ago
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    That is not true.

  63. Anikate
    • 2 years ago
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    yes so, how do u know?

  64. Mertsj
    • 2 years ago
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    The problem said to describe and correct the error.

  65. Mertsj
    • 2 years ago
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    The description of the error is that the domain is not continuous.

  66. Mertsj
    • 2 years ago
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    The correction of the error is that the domain is discrete.

  67. Anikate
    • 2 years ago
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    yes, but how do u explain that? do u have proof

  68. Anikate
    • 2 years ago
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    what in the graph tells u that

  69. Mertsj
    • 2 years ago
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    If the domain were continuous, there would be a point whose x value is 1/2 and 3/4 and 1.5 and 50, and 900 and -8 and -30.6 and.....

  70. Mertsj
    • 2 years ago
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    So since I can name numbers which are not in the domain, I know the domain is NOT continuous.

  71. Anikate
    • 2 years ago
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    like 5?

  72. Mertsj
    • 2 years ago
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    Any number you want to name, sweetheart, except 1,2,3,4

  73. Anikate
    • 2 years ago
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    ok so 5 is ok right?

  74. Mertsj
    • 2 years ago
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    How are you going to answer the question?

  75. Mertsj
    • 2 years ago
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    Post your answer and I will see if it is right.

  76. Anikate
    • 2 years ago
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    k brb

  77. Anikate
    • 2 years ago
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    just a minute

  78. Anikate
    • 2 years ago
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    r u still there?

  79. Anikate
    • 2 years ago
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    r u still there?

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  80. Anikate
    • 2 years ago
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    This is my answer

  81. Anikate
    • 2 years ago
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    r u still there?

  82. Anikate
    • 2 years ago
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    Hello? brb

  83. Mertsj
    • 2 years ago
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    So you have made the graph match the description. I think the problem said to correct the description. Therefore, I think you should have said

  84. Mertsj
    • 2 years ago
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    "The domain in not continuous. The domain in discrete. If the domain were continuous, the graph would be a line."

  85. Anikate
    • 2 years ago
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    r u still there?

  86. Anikate
    • 2 years ago
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    I'm even supposed to graph it, but thanks

  87. Mertsj
    • 2 years ago
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    "Describe and correct the error in classifying the domain". That was the question you were supposed to answer. Nowhere does it mention making the graph match the description.

  88. Anikate
    • 2 years ago
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    r u still there?

  89. Anikate
    • 2 years ago
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    my annoying teacher told me to

  90. Mertsj
    • 2 years ago
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    yes

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