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anonymous
 5 years ago
how do you solve x^212x+4=0 ?
anonymous
 5 years ago
how do you solve x^212x+4=0 ?

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Mertsj
 5 years ago
Best ResponseYou've already chosen the best response.1use the quadratic formula since it will not factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or completing the square

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^212 x+4 = 0 Subtract 4 from both sides: x^212 x = 4 Add 36 to both sides: x^212 x+36 = 32 Factor the left hand side: (x6)^2 = 32 Take the square root of both sides: sqrt(x6) = 4 sqrt(2) Eliminate the absolute value: x6 = 4 sqrt(2) or x6 = 4 sqrt(2) Add 6 to both sides: x = 64 sqrt(2) or x6 = 4 sqrt(2) Add 6 to both sides: x = 64 sqrt(2) or x = 6+4 sqrt(2)
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