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hickers13

  • 4 years ago

how do you solve x^2-12x+4=0 ?

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  1. saifoo.khan
    • 4 years ago
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    Quadratic formula!

  2. Mertsj
    • 4 years ago
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    use the quadratic formula since it will not factor.

  3. theabsurd
    • 4 years ago
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    or completing the square

  4. DHASHNI
    • 4 years ago
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    x^2-12 x+4 = 0 Subtract 4 from both sides: x^2-12 x = -4 Add 36 to both sides: x^2-12 x+36 = 32 Factor the left hand side: (x-6)^2 = 32 Take the square root of both sides: sqrt(x-6) = 4 sqrt(2) Eliminate the absolute value: x-6 = -4 sqrt(2) or x-6 = 4 sqrt(2) Add 6 to both sides: x = 6-4 sqrt(2) or x-6 = 4 sqrt(2) Add 6 to both sides: x = 6-4 sqrt(2) or x = 6+4 sqrt(2)

  5. theabsurd
    • 4 years ago
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    ^what she did :)

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