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NotTim
Group Title
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0
 2 years ago
 2 years ago
NotTim Group Title
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0
 2 years ago
 2 years ago

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NotTim Group TitleBest ResponseYou've already chosen the best response.0
Well I tried putting x=1, I got an error.
 2 years ago

ricnus Group TitleBest ResponseYou've already chosen the best response.0
\[x \approx3.14159 n+1.10715\] \[x \approx3.14159 n+0.429998\] \[x \approx3.14159 n+1.4191\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
first see if you can solve this \[u^39u^2+17u6=0\]
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
Thanks myin; that's the way.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
if you try u=2, you will see you have one solution
 2 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
thats what i wasn gonna say replace tan with a variable
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
then using synthetic division you can find the other 2 solutions
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I dunno what that is.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
u can also urs long division to get factors
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Wait a sec guys, I'm trying to understand this all...
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
A fancy way of saying that as u = 2 is a solution, (u2) must be a factor of the polynomial. Hence you can write \[ u^3−9u^2+17^u−6 = (u2)q(u) \] for some second order polynomial
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
make that 17u, not 17^u
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
What happened to tan?
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
i'll let the other chefs take over
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
we will get back to the tan business after we solve that polynomial=0 for u
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Ok, so I'm doing the whole F(#) thing at this point right?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
what does F(#) mean?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Looking for the value of x that makes everything 0.
 2 years ago

ricnus Group TitleBest ResponseYou've already chosen the best response.0
u = 2 u = 1/2 (7sqrt(37)) u = 1/2 (7+sqrt(37))
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
If you think how myininaya magically found that \( u=2 \) there is a analytical way of doing it which is known as Rational root test.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
right fool
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
What if I got an error on my calculator?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Useless its tanx (as an entirety) that I using....
 2 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
Your trying to plug number right into the equation?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
i went through the possible rational zeros and found a rational zero i didn't go through all possible rational zeros as i only needed one so i can just mess with a quadratic
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Lagrange, yes...
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Not the right idea huh?
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
You need to NotThink a bit.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
...ok? I do that a lot.
 2 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
Follow those steps that myin showed, youll end with the right answers
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I'm just looking at this and my notes, and I have not a clue.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
it's more like Let u = tan x then form a polynomial in u, factor it and then substitute back the u =tan x and then solve it ..
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Imma do this slowly... If yo ugotta do something while you help me, do it now as I work this thru...
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
IS factor Thereom involved?
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.1
yes...if u2 is a factor of P(u) ...P(2)=0
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.1
Let tan (x) = u \[u ^{3}9u ^{2}+17u6=0\] \[\left( u2 \right)\left( u^2  7u 3\right) =0\]
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
wait wait waitt.... And that's also not how I was taught (or shown in the notes). I'll try it out after I'm done my thing tho/.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Sorry about that. My internet went wonky.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
And now I divide the thing by u2 right?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
u^27u+3 ____________________ u2 u^39u^2+17u6 (u^32u^2)  7u^2+17u6 (7u^2+14u)  3u6 (3u6)  0
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
pax did i make a mistake?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
our factorizations are a lttle different i have \[\left( u2 \right)\left( u^2  7u +3\right) =0\]
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
myininaya, I wish If I can give you more medals for your patience.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
are you talking about me and my division above? lol
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I think just waiting for me to finish up my stuff here. Thanks by the way.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
oh i had a thing i was doing lol
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.1
sorry u r right. it's +3
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
just making sure when it gets late i tend to screw up on little things
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
like sometimes i don't know how to add or multiply sometimes
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
we were talking about this: \[\left( u2 \right)\left( u^2  7u +3\right) =0 \]
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
ok. that scared me for a sec.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
yep myininaya I was talking about that :D
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
so we know we have u=2 we also have \[u=\frac{7 \pm \sqrt{494(3)}}{2}\] don't forget to replace u with tan(x) and solve for x
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Finally, I'm done the division.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
you have \[u2=0 \text{ or } u^27u+3=0\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
we need to use the quadratic formula to solve the second equation
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I hope I remember this for the test.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
so this is trig class?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
i could be wrong but this is too long to put on a test
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
there might be a similar problem he/she puts there
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
but shorter
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Whoops. I didn't type that...Double post or something.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
i could be wrong
 2 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
sometimes teachers get problems from special books
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
I'm sleepy guys I'm sure if you need more help NotTim (who we decided was not myininaya earlier ;)lol) , fool and pax will continue to help unless they are are going.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
K. Thanks man.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
Do I look like a man to you?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
Please say no
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I actually have bad vision and human identification problems.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
When I'm walking around I will misidentify everyone as the same person.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.6
Ok. Its cool. No worries.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
any1 know what I should do at (m2)(m^27m+3)?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
For m^27m+3, do I have to do the quadratic formula?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
I guess I already know what to do with m2, so I'm fine there.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
ERm, are you people just gunna lurk there? It's fine, just....
 2 years ago

ktklown Group TitleBest ResponseYou've already chosen the best response.0
find all places that u can be 0, then, recalling that u = tanx, solve for x.
 2 years ago

ktklown Group TitleBest ResponseYou've already chosen the best response.0
you already found one solution is u=2, you can find the others by using the quadratic formula on the quadratic part of your factoring.
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
Um, sorry if I sound abrupt, but could anyone please answer my most recent question?
 2 years ago
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