Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Solve the following equation, xe[2,0pi]. tan^3x-9tan^2x+17tanx-6=0

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Well I tried putting x=1, I got an error.
\[x \approx3.14159 n+1.10715\] \[x \approx3.14159 n+0.429998\] \[x \approx3.14159 n+1.4191\]
first see if you can solve this \[u^3-9u^2+17u-6=0\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Thanks myin; that's the way.
if you try u=2, you will see you have one solution
thats what i wasn gonna say replace tan with a variable
then using synthetic division you can find the other 2 solutions
I dunno what that is.
synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)
u can also urs long division to get factors
Wait a sec guys, I'm trying to understand this all...
A fancy way of saying that as u = 2 is a solution, (u-2) must be a factor of the polynomial. Hence you can write \[ u^3āˆ’9u^2+17^uāˆ’6 = (u-2)q(u) \] for some second order polynomial
make that 17u, not 17^u
lol
What happened to tan?
i'll let the other chefs take over
we will get back to the tan business after we solve that polynomial=0 for u
Ok, so I'm doing the whole F(#) thing at this point right?
what?
what does F(#) mean?
Looking for the value of x that makes everything 0.
u = 2 u = 1/2 (7-sqrt(37)) u = 1/2 (7+sqrt(37))
If you think how myininaya magically found that \( u=2 \) there is a analytical way of doing it which is known as Rational root test.
right fool
What if I got an error on my calculator?
Useless its tanx (as an entirety) that I using....
Your trying to plug number right into the equation?
i went through the possible rational zeros and found a rational zero i didn't go through all possible rational zeros as i only needed one so i can just mess with a quadratic
Lagrange, yes...
Not the right idea huh?
You need to NotThink a bit.
...ok? I do that a lot.
Follow those steps that myin showed, youll end with the right answers
I'm just looking at this and my notes, and I have not a clue.
Is u=tanx?
yes
Ok.
it's more like Let u = tan x then form a polynomial in u, factor it and then substitute back the u =tan x and then solve it ..
ERkk.
Imma do this slowly... If yo ugotta do something while you help me, do it now as I work this thru...
IS factor Thereom involved?
yes...if u-2 is a factor of P(u) ...P(2)=0
Let tan (x) = u \[u ^{3}-9u ^{2}+17u-6=0\] \[\left( u-2 \right)\left( u^2 - 7u -3\right) =0\]
wait wait waitt.... And that's also not how I was taught (or shown in the notes). I'll try it out after I'm done my thing tho/.
Sorry about that. My internet went wonky.
And now I divide the thing by u-2 right?
u^2-7u+3 ____________________ u-2| u^3-9u^2+17u-6 -(u^3-2u^2) ------------------- -7u^2+17u-6 -(-7u^2+14u) --------------- 3u-6 -(3u-6) -------- 0
ok
pax did i make a mistake?
our factorizations are a lttle different i have \[\left( u-2 \right)\left( u^2 - 7u +3\right) =0\]
myininaya, I wish If I can give you more medals for your patience.
Lol.
are you talking about me and my division above? lol
I think just waiting for me to finish up my stuff here. Thanks by the way.
oh i had a thing i was doing lol
sorry u r right. it's +3
ITs +3?
just making sure when it gets late i tend to screw up on little things
like sometimes i don't know how to add or multiply sometimes
we were talking about this: \[\left( u-2 \right)\left( u^2 - 7u +3\right) =0 \]
ok. that scared me for a sec.
yep myininaya I was talking about that :D
lol
so we know we have u=2 we also have \[u=\frac{7 \pm \sqrt{49-4(3)}}{2}\] don't forget to replace u with tan(x) and solve for x
Finally, I'm done the division.
lol
good
you have \[u-2=0 \text{ or } u^2-7u+3=0\]
we need to use the quadratic formula to solve the second equation
I hope I remember this for the test.
so this is trig class?
i could be wrong but this is too long to put on a test
there might be a similar problem he/she puts there
but shorter
Whoops. I didn't type that...Double post or something.
i could be wrong
sometimes teachers get problems from special books
I'm sleepy guys I'm sure if you need more help NotTim (who we decided was not myininaya earlier ;)lol) , fool and pax will continue to help unless they are are going.
K. Thanks man.
Do I look like a man to you?
Please say no
lol
Are you?
I actually have bad vision and human identification problems.
When I'm walking around I will misidentify everyone as the same person.
Ok. Its cool. No worries.
any1 know what I should do at (m-2)(m^2-7m+3)?
For m^2-7m+3, do I have to do the quadratic formula?
I guess I already know what to do with m-2, so I'm fine there.
ERm, are you people just gunna lurk there? It's fine, just....
find all places that u can be 0, then, recalling that u = tanx, solve for x.
you already found one solution is u=2, you can find the others by using the quadratic formula on the quadratic part of your factoring.
Ok.
Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?
Hi?
Um, sorry if I sound abrupt, but could anyone please answer my most recent question?

Not the answer you are looking for?

Search for more explanations.

Ask your own question