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Well I tried putting x=1, I got an error.

\[x \approx3.14159 n+1.10715\]
\[x \approx3.14159 n+0.429998\]
\[x \approx3.14159 n+1.4191\]

first see if you can solve this
\[u^3-9u^2+17u-6=0\]

Thanks myin; that's the way.

if you try u=2, you will see you have one solution

thats what i wasn gonna say replace tan with a variable

then using synthetic division you can find the other 2 solutions

I dunno what that is.

synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)

u can also urs long division to get factors

Wait a sec guys, I'm trying to understand this all...

make that 17u, not 17^u

lol

What happened to tan?

i'll let the other chefs take over

we will get back to the tan business after we solve that polynomial=0 for u

Ok, so I'm doing the whole F(#) thing at this point right?

what?

what does F(#) mean?

Looking for the value of x that makes everything 0.

u = 2
u = 1/2 (7-sqrt(37))
u = 1/2 (7+sqrt(37))

right fool

What if I got an error on my calculator?

Useless its tanx (as an entirety) that I using....

Your trying to plug number right into the equation?

Lagrange, yes...

Not the right idea huh?

You need to NotThink a bit.

...ok? I do that a lot.

Follow those steps that myin showed, youll end with the right answers

I'm just looking at this and my notes, and I have not a clue.

Is u=tanx?

yes

Ok.

ERkk.

Imma do this slowly...
If yo ugotta do something while you help me, do it now as I work this thru...

IS factor Thereom involved?

yes...if u-2 is a factor of P(u) ...P(2)=0

Let tan (x) = u \[u ^{3}-9u ^{2}+17u-6=0\] \[\left( u-2 \right)\left( u^2 - 7u -3\right) =0\]

Sorry about that. My internet went wonky.

And now I divide the thing by u-2 right?

ok

pax did i make a mistake?

our factorizations are a lttle different
i have
\[\left( u-2 \right)\left( u^2 - 7u +3\right) =0\]

myininaya, I wish If I can give you more medals for your patience.

Lol.

are you talking about me and my division above? lol

I think just waiting for me to finish up my stuff here. Thanks by the way.

oh i had a thing i was doing lol

sorry u r right. it's +3

ITs +3?

just making sure
when it gets late i tend to screw up on little things

like sometimes i don't know how to add or multiply sometimes

we were talking about this:
\[\left( u-2 \right)\left( u^2 - 7u +3\right) =0 \]

ok. that scared me for a sec.

yep myininaya I was talking about that :D

lol

Finally, I'm done the division.

lol

good

you have
\[u-2=0 \text{ or } u^2-7u+3=0\]

we need to use the quadratic formula to solve the second equation

I hope I remember this for the test.

so this is trig class?

i could be wrong but this is too long to put on a test

there might be a similar problem he/she puts there

but shorter

Whoops. I didn't type that...Double post or something.

i could be wrong

sometimes teachers get problems from special books

K. Thanks man.

Do I look like a man to you?

Please say no

lol

Are you?

I actually have bad vision and human identification problems.

When I'm walking around I will misidentify everyone as the same person.

Ok. Its cool. No worries.

any1 know what I should do at (m-2)(m^2-7m+3)?

For m^2-7m+3, do I have to do the quadratic formula?

I guess I already know what to do with m-2, so I'm fine there.

ERm, are you people just gunna lurk there? It's fine, just....

find all places that u can be 0, then, recalling that u = tanx, solve for x.

Ok.

Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?

Hi?

Um, sorry if I sound abrupt, but could anyone please answer my most recent question?