A community for students.
Here's the question you clicked on:
 0 viewing
NotTim
 5 years ago
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0
NotTim
 5 years ago
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0

This Question is Closed

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Well I tried putting x=1, I got an error.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x \approx3.14159 n+1.10715\] \[x \approx3.14159 n+0.429998\] \[x \approx3.14159 n+1.4191\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6first see if you can solve this \[u^39u^2+17u6=0\]

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks myin; that's the way.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6if you try u=2, you will see you have one solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i wasn gonna say replace tan with a variable

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6then using synthetic division you can find the other 2 solutions

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)

Nubeer
 5 years ago
Best ResponseYou've already chosen the best response.0u can also urs long division to get factors

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Wait a sec guys, I'm trying to understand this all...

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.0A fancy way of saying that as u = 2 is a solution, (u2) must be a factor of the polynomial. Hence you can write \[ u^3−9u^2+17^u−6 = (u2)q(u) \] for some second order polynomial

JamesJ
 5 years ago
Best ResponseYou've already chosen the best response.0i'll let the other chefs take over

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6we will get back to the tan business after we solve that polynomial=0 for u

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so I'm doing the whole F(#) thing at this point right?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Looking for the value of x that makes everything 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u = 2 u = 1/2 (7sqrt(37)) u = 1/2 (7+sqrt(37))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you think how myininaya magically found that \( u=2 \) there is a analytical way of doing it which is known as Rational root test.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0What if I got an error on my calculator?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Useless its tanx (as an entirety) that I using....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your trying to plug number right into the equation?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6i went through the possible rational zeros and found a rational zero i didn't go through all possible rational zeros as i only needed one so i can just mess with a quadratic

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to NotThink a bit.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Follow those steps that myin showed, youll end with the right answers

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0I'm just looking at this and my notes, and I have not a clue.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's more like Let u = tan x then form a polynomial in u, factor it and then substitute back the u =tan x and then solve it ..

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Imma do this slowly... If yo ugotta do something while you help me, do it now as I work this thru...

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0IS factor Thereom involved?

PaxPolaris
 5 years ago
Best ResponseYou've already chosen the best response.1yes...if u2 is a factor of P(u) ...P(2)=0

PaxPolaris
 5 years ago
Best ResponseYou've already chosen the best response.1Let tan (x) = u \[u ^{3}9u ^{2}+17u6=0\] \[\left( u2 \right)\left( u^2  7u 3\right) =0\]

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0wait wait waitt.... And that's also not how I was taught (or shown in the notes). I'll try it out after I'm done my thing tho/.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry about that. My internet went wonky.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0And now I divide the thing by u2 right?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6u^27u+3 ____________________ u2 u^39u^2+17u6 (u^32u^2)  7u^2+17u6 (7u^2+14u)  3u6 (3u6)  0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6pax did i make a mistake?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6our factorizations are a lttle different i have \[\left( u2 \right)\left( u^2  7u +3\right) =0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myininaya, I wish If I can give you more medals for your patience.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6are you talking about me and my division above? lol

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0I think just waiting for me to finish up my stuff here. Thanks by the way.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6oh i had a thing i was doing lol

PaxPolaris
 5 years ago
Best ResponseYou've already chosen the best response.1sorry u r right. it's +3

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6just making sure when it gets late i tend to screw up on little things

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6like sometimes i don't know how to add or multiply sometimes

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6we were talking about this: \[\left( u2 \right)\left( u^2  7u +3\right) =0 \]

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0ok. that scared me for a sec.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep myininaya I was talking about that :D

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6so we know we have u=2 we also have \[u=\frac{7 \pm \sqrt{494(3)}}{2}\] don't forget to replace u with tan(x) and solve for x

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Finally, I'm done the division.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6you have \[u2=0 \text{ or } u^27u+3=0\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6we need to use the quadratic formula to solve the second equation

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0I hope I remember this for the test.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6so this is trig class?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6i could be wrong but this is too long to put on a test

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6there might be a similar problem he/she puts there

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Whoops. I didn't type that...Double post or something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sometimes teachers get problems from special books

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6I'm sleepy guys I'm sure if you need more help NotTim (who we decided was not myininaya earlier ;)lol) , fool and pax will continue to help unless they are are going.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6Do I look like a man to you?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0I actually have bad vision and human identification problems.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0When I'm walking around I will misidentify everyone as the same person.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.6Ok. Its cool. No worries.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0any1 know what I should do at (m2)(m^27m+3)?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0For m^27m+3, do I have to do the quadratic formula?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0I guess I already know what to do with m2, so I'm fine there.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0ERm, are you people just gunna lurk there? It's fine, just....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find all places that u can be 0, then, recalling that u = tanx, solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you already found one solution is u=2, you can find the others by using the quadratic formula on the quadratic part of your factoring.

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?

NotTim
 5 years ago
Best ResponseYou've already chosen the best response.0Um, sorry if I sound abrupt, but could anyone please answer my most recent question?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.