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NotTim
 4 years ago
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0
NotTim
 4 years ago
Solve the following equation, xe[2,0pi]. tan^3x9tan^2x+17tanx6=0

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NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Well I tried putting x=1, I got an error.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x \approx3.14159 n+1.10715\] \[x \approx3.14159 n+0.429998\] \[x \approx3.14159 n+1.4191\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6first see if you can solve this \[u^39u^2+17u6=0\]

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks myin; that's the way.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6if you try u=2, you will see you have one solution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats what i wasn gonna say replace tan with a variable

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6then using synthetic division you can find the other 2 solutions

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u can also urs long division to get factors

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Wait a sec guys, I'm trying to understand this all...

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0A fancy way of saying that as u = 2 is a solution, (u2) must be a factor of the polynomial. Hence you can write \[ u^3−9u^2+17^u−6 = (u2)q(u) \] for some second order polynomial

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0i'll let the other chefs take over

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6we will get back to the tan business after we solve that polynomial=0 for u

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so I'm doing the whole F(#) thing at this point right?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Looking for the value of x that makes everything 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u = 2 u = 1/2 (7sqrt(37)) u = 1/2 (7+sqrt(37))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you think how myininaya magically found that \( u=2 \) there is a analytical way of doing it which is known as Rational root test.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0What if I got an error on my calculator?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Useless its tanx (as an entirety) that I using....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your trying to plug number right into the equation?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6i went through the possible rational zeros and found a rational zero i didn't go through all possible rational zeros as i only needed one so i can just mess with a quadratic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You need to NotThink a bit.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Follow those steps that myin showed, youll end with the right answers

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0I'm just looking at this and my notes, and I have not a clue.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's more like Let u = tan x then form a polynomial in u, factor it and then substitute back the u =tan x and then solve it ..

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Imma do this slowly... If yo ugotta do something while you help me, do it now as I work this thru...

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0IS factor Thereom involved?

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1yes...if u2 is a factor of P(u) ...P(2)=0

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1Let tan (x) = u \[u ^{3}9u ^{2}+17u6=0\] \[\left( u2 \right)\left( u^2  7u 3\right) =0\]

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0wait wait waitt.... And that's also not how I was taught (or shown in the notes). I'll try it out after I'm done my thing tho/.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry about that. My internet went wonky.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0And now I divide the thing by u2 right?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6u^27u+3 ____________________ u2 u^39u^2+17u6 (u^32u^2)  7u^2+17u6 (7u^2+14u)  3u6 (3u6)  0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6pax did i make a mistake?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6our factorizations are a lttle different i have \[\left( u2 \right)\left( u^2  7u +3\right) =0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0myininaya, I wish If I can give you more medals for your patience.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6are you talking about me and my division above? lol

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0I think just waiting for me to finish up my stuff here. Thanks by the way.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6oh i had a thing i was doing lol

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1sorry u r right. it's +3

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6just making sure when it gets late i tend to screw up on little things

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6like sometimes i don't know how to add or multiply sometimes

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6we were talking about this: \[\left( u2 \right)\left( u^2  7u +3\right) =0 \]

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0ok. that scared me for a sec.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep myininaya I was talking about that :D

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6so we know we have u=2 we also have \[u=\frac{7 \pm \sqrt{494(3)}}{2}\] don't forget to replace u with tan(x) and solve for x

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Finally, I'm done the division.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6you have \[u2=0 \text{ or } u^27u+3=0\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6we need to use the quadratic formula to solve the second equation

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0I hope I remember this for the test.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6so this is trig class?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6i could be wrong but this is too long to put on a test

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6there might be a similar problem he/she puts there

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Whoops. I didn't type that...Double post or something.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sometimes teachers get problems from special books

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6I'm sleepy guys I'm sure if you need more help NotTim (who we decided was not myininaya earlier ;)lol) , fool and pax will continue to help unless they are are going.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6Do I look like a man to you?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0I actually have bad vision and human identification problems.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0When I'm walking around I will misidentify everyone as the same person.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.6Ok. Its cool. No worries.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0any1 know what I should do at (m2)(m^27m+3)?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0For m^27m+3, do I have to do the quadratic formula?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0I guess I already know what to do with m2, so I'm fine there.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0ERm, are you people just gunna lurk there? It's fine, just....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find all places that u can be 0, then, recalling that u = tanx, solve for x.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you already found one solution is u=2, you can find the others by using the quadratic formula on the quadratic part of your factoring.

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?

NotTim
 4 years ago
Best ResponseYou've already chosen the best response.0Um, sorry if I sound abrupt, but could anyone please answer my most recent question?
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