NotTim
  • NotTim
Solve the following equation, xe[2,0pi]. tan^3x-9tan^2x+17tanx-6=0
Mathematics
chestercat
  • chestercat
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NotTim
  • NotTim
Well I tried putting x=1, I got an error.
anonymous
  • anonymous
\[x \approx3.14159 n+1.10715\] \[x \approx3.14159 n+0.429998\] \[x \approx3.14159 n+1.4191\]
myininaya
  • myininaya
first see if you can solve this \[u^3-9u^2+17u-6=0\]

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JamesJ
  • JamesJ
Thanks myin; that's the way.
myininaya
  • myininaya
if you try u=2, you will see you have one solution
anonymous
  • anonymous
thats what i wasn gonna say replace tan with a variable
myininaya
  • myininaya
then using synthetic division you can find the other 2 solutions
NotTim
  • NotTim
I dunno what that is.
myininaya
  • myininaya
synethic division+quadratic formula (or perhaps factoring if we have other rational zeros)
nubeer
  • nubeer
u can also urs long division to get factors
NotTim
  • NotTim
Wait a sec guys, I'm trying to understand this all...
JamesJ
  • JamesJ
A fancy way of saying that as u = 2 is a solution, (u-2) must be a factor of the polynomial. Hence you can write \[ u^3āˆ’9u^2+17^uāˆ’6 = (u-2)q(u) \] for some second order polynomial
JamesJ
  • JamesJ
make that 17u, not 17^u
myininaya
  • myininaya
lol
NotTim
  • NotTim
What happened to tan?
JamesJ
  • JamesJ
i'll let the other chefs take over
myininaya
  • myininaya
we will get back to the tan business after we solve that polynomial=0 for u
NotTim
  • NotTim
Ok, so I'm doing the whole F(#) thing at this point right?
myininaya
  • myininaya
what?
myininaya
  • myininaya
what does F(#) mean?
NotTim
  • NotTim
Looking for the value of x that makes everything 0.
anonymous
  • anonymous
u = 2 u = 1/2 (7-sqrt(37)) u = 1/2 (7+sqrt(37))
anonymous
  • anonymous
If you think how myininaya magically found that \( u=2 \) there is a analytical way of doing it which is known as Rational root test.
myininaya
  • myininaya
right fool
NotTim
  • NotTim
What if I got an error on my calculator?
NotTim
  • NotTim
Useless its tanx (as an entirety) that I using....
anonymous
  • anonymous
Your trying to plug number right into the equation?
myininaya
  • myininaya
i went through the possible rational zeros and found a rational zero i didn't go through all possible rational zeros as i only needed one so i can just mess with a quadratic
NotTim
  • NotTim
Lagrange, yes...
NotTim
  • NotTim
Not the right idea huh?
anonymous
  • anonymous
You need to NotThink a bit.
NotTim
  • NotTim
...ok? I do that a lot.
anonymous
  • anonymous
Follow those steps that myin showed, youll end with the right answers
NotTim
  • NotTim
I'm just looking at this and my notes, and I have not a clue.
NotTim
  • NotTim
Is u=tanx?
myininaya
  • myininaya
yes
NotTim
  • NotTim
Ok.
anonymous
  • anonymous
it's more like Let u = tan x then form a polynomial in u, factor it and then substitute back the u =tan x and then solve it ..
NotTim
  • NotTim
ERkk.
NotTim
  • NotTim
Imma do this slowly... If yo ugotta do something while you help me, do it now as I work this thru...
NotTim
  • NotTim
IS factor Thereom involved?
PaxPolaris
  • PaxPolaris
yes...if u-2 is a factor of P(u) ...P(2)=0
PaxPolaris
  • PaxPolaris
Let tan (x) = u \[u ^{3}-9u ^{2}+17u-6=0\] \[\left( u-2 \right)\left( u^2 - 7u -3\right) =0\]
NotTim
  • NotTim
wait wait waitt.... And that's also not how I was taught (or shown in the notes). I'll try it out after I'm done my thing tho/.
NotTim
  • NotTim
Sorry about that. My internet went wonky.
NotTim
  • NotTim
And now I divide the thing by u-2 right?
myininaya
  • myininaya
u^2-7u+3 ____________________ u-2| u^3-9u^2+17u-6 -(u^3-2u^2) ------------------- -7u^2+17u-6 -(-7u^2+14u) --------------- 3u-6 -(3u-6) -------- 0
NotTim
  • NotTim
ok
myininaya
  • myininaya
pax did i make a mistake?
myininaya
  • myininaya
our factorizations are a lttle different i have \[\left( u-2 \right)\left( u^2 - 7u +3\right) =0\]
anonymous
  • anonymous
myininaya, I wish If I can give you more medals for your patience.
NotTim
  • NotTim
Lol.
myininaya
  • myininaya
are you talking about me and my division above? lol
NotTim
  • NotTim
I think just waiting for me to finish up my stuff here. Thanks by the way.
myininaya
  • myininaya
oh i had a thing i was doing lol
PaxPolaris
  • PaxPolaris
sorry u r right. it's +3
NotTim
  • NotTim
ITs +3?
myininaya
  • myininaya
just making sure when it gets late i tend to screw up on little things
myininaya
  • myininaya
like sometimes i don't know how to add or multiply sometimes
myininaya
  • myininaya
we were talking about this: \[\left( u-2 \right)\left( u^2 - 7u +3\right) =0 \]
NotTim
  • NotTim
ok. that scared me for a sec.
anonymous
  • anonymous
yep myininaya I was talking about that :D
myininaya
  • myininaya
lol
myininaya
  • myininaya
so we know we have u=2 we also have \[u=\frac{7 \pm \sqrt{49-4(3)}}{2}\] don't forget to replace u with tan(x) and solve for x
NotTim
  • NotTim
Finally, I'm done the division.
myininaya
  • myininaya
lol
myininaya
  • myininaya
good
myininaya
  • myininaya
you have \[u-2=0 \text{ or } u^2-7u+3=0\]
myininaya
  • myininaya
we need to use the quadratic formula to solve the second equation
NotTim
  • NotTim
I hope I remember this for the test.
myininaya
  • myininaya
so this is trig class?
myininaya
  • myininaya
i could be wrong but this is too long to put on a test
myininaya
  • myininaya
there might be a similar problem he/she puts there
myininaya
  • myininaya
but shorter
NotTim
  • NotTim
Whoops. I didn't type that...Double post or something.
myininaya
  • myininaya
i could be wrong
anonymous
  • anonymous
sometimes teachers get problems from special books
myininaya
  • myininaya
I'm sleepy guys I'm sure if you need more help NotTim (who we decided was not myininaya earlier ;)lol) , fool and pax will continue to help unless they are are going.
NotTim
  • NotTim
K. Thanks man.
myininaya
  • myininaya
Do I look like a man to you?
myininaya
  • myininaya
Please say no
myininaya
  • myininaya
lol
NotTim
  • NotTim
Are you?
NotTim
  • NotTim
I actually have bad vision and human identification problems.
NotTim
  • NotTim
When I'm walking around I will misidentify everyone as the same person.
myininaya
  • myininaya
Ok. Its cool. No worries.
NotTim
  • NotTim
any1 know what I should do at (m-2)(m^2-7m+3)?
NotTim
  • NotTim
For m^2-7m+3, do I have to do the quadratic formula?
NotTim
  • NotTim
I guess I already know what to do with m-2, so I'm fine there.
NotTim
  • NotTim
ERm, are you people just gunna lurk there? It's fine, just....
anonymous
  • anonymous
find all places that u can be 0, then, recalling that u = tanx, solve for x.
anonymous
  • anonymous
you already found one solution is u=2, you can find the others by using the quadratic formula on the quadratic part of your factoring.
NotTim
  • NotTim
Ok.
NotTim
  • NotTim
Hey, if one of my answers is 6.54, and I wanna get the other angle with it, what do i Do?
NotTim
  • NotTim
Hi?
NotTim
  • NotTim
Um, sorry if I sound abrupt, but could anyone please answer my most recent question?

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