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Ishaan94Best ResponseYou've already chosen the best response.0
not possible i don't think a^(n) = 0 is possible
 2 years ago

MasterMindXDBest ResponseYou've already chosen the best response.0
Well, this is what I had before....log(log(x+11))=log^((1/2)^(x+11)).
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
i am assuming it's \[\log_{10} \log_{10} (x+11) = \log_{10} \frac{1}{2^{x+ 11}}\]
 2 years ago

cristiannBest ResponseYou've already chosen the best response.3
The equation log(x+11)=((1/2))^{x+11} has a unique solution, which cannot be found exactly (or guessed ... :) ) The existence is proved by Darbouxtype reasoning: for x=10: log1=0<(1/2)^1=1/2 for x=1: log10=1>(1/2)^10 Unicity is proven by monotonicity ... :)
 2 years ago

cristiannBest ResponseYou've already chosen the best response.3
The unique solution may be found numerically to be x=9.5559 Darbouxtype reasoning refers to: f(x1)<0 and f(x2)>0 and f() continuous then there is at least one value x0 between x1 and x2 such that f(x0)=0
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
wow cristiann, you're awesome at mathematics
 2 years ago

cristiannBest ResponseYou've already chosen the best response.3
Thanks ... not really ... just older ... :)
 2 years ago

cristiannBest ResponseYou've already chosen the best response.3
And I'm taking you all the fun of doing them ...:)
 2 years ago
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