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How to solve 10^[(10^(x+11)) +(0.5^(x+11))] =0

Mathematics
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not possible i don't think a^(n) = 0 is possible
Well, this is what I had before....log(log(x+11))=log^((1/2)^(x+11)).
oh okay

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Other answers:

log^((1/2)^(x+11))??
yeah
i am assuming it's \[\log_{10} \log_{10} (x+11) = \log_{10} \frac{1}{2^{x+ 11}}\]
okay yeah...
The equation log(x+11)=((1/2))^{x+11} has a unique solution, which cannot be found exactly (or guessed ... :) ) The existence is proved by Darboux-type reasoning: for x=-10: log1=0<(1/2)^1=1/2 for x=-1: log10=1>(1/2)^10 Unicity is proven by monotonicity ... :)
The unique solution may be found numerically to be x=-9.5559 Darboux-type reasoning refers to: f(x1)<0 and f(x2)>0 and f() continuous then there is at least one value x0 between x1 and x2 such that f(x0)=0
:)
wow cristiann, you're awesome at mathematics
Thanks ... not really ... just older ... :)
And I'm taking you all the fun of doing them ...:)
REFER http://www.wolframalpha.com/input/?i=solve%7B10%5E%5B%2810%5E%28x%2B11%29%29+%2B%280.5%5E%28x%2B11%29%29%5D+%3D0%7D

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