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Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.0not possible i don't think a^(n) = 0 is possible

MasterMindXD
 3 years ago
Best ResponseYou've already chosen the best response.0Well, this is what I had before....log(log(x+11))=log^((1/2)^(x+11)).

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.0i am assuming it's \[\log_{10} \log_{10} (x+11) = \log_{10} \frac{1}{2^{x+ 11}}\]

cristiann
 3 years ago
Best ResponseYou've already chosen the best response.3The equation log(x+11)=((1/2))^{x+11} has a unique solution, which cannot be found exactly (or guessed ... :) ) The existence is proved by Darbouxtype reasoning: for x=10: log1=0<(1/2)^1=1/2 for x=1: log10=1>(1/2)^10 Unicity is proven by monotonicity ... :)

cristiann
 3 years ago
Best ResponseYou've already chosen the best response.3The unique solution may be found numerically to be x=9.5559 Darbouxtype reasoning refers to: f(x1)<0 and f(x2)>0 and f() continuous then there is at least one value x0 between x1 and x2 such that f(x0)=0

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.0wow cristiann, you're awesome at mathematics

cristiann
 3 years ago
Best ResponseYou've already chosen the best response.3Thanks ... not really ... just older ... :)

cristiann
 3 years ago
Best ResponseYou've already chosen the best response.3And I'm taking you all the fun of doing them ...:)
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