anonymous
  • anonymous
How to solve 10^[(10^(x+11)) +(0.5^(x+11))] =0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
not possible i don't think a^(n) = 0 is possible
anonymous
  • anonymous
Well, this is what I had before....log(log(x+11))=log^((1/2)^(x+11)).
anonymous
  • anonymous
oh okay

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
log^((1/2)^(x+11))??
anonymous
  • anonymous
yeah
anonymous
  • anonymous
i am assuming it's \[\log_{10} \log_{10} (x+11) = \log_{10} \frac{1}{2^{x+ 11}}\]
anonymous
  • anonymous
okay yeah...
cristiann
  • cristiann
The equation log(x+11)=((1/2))^{x+11} has a unique solution, which cannot be found exactly (or guessed ... :) ) The existence is proved by Darboux-type reasoning: for x=-10: log1=0<(1/2)^1=1/2 for x=-1: log10=1>(1/2)^10 Unicity is proven by monotonicity ... :)
cristiann
  • cristiann
The unique solution may be found numerically to be x=-9.5559 Darboux-type reasoning refers to: f(x1)<0 and f(x2)>0 and f() continuous then there is at least one value x0 between x1 and x2 such that f(x0)=0
cristiann
  • cristiann
:)
anonymous
  • anonymous
wow cristiann, you're awesome at mathematics
cristiann
  • cristiann
Thanks ... not really ... just older ... :)
cristiann
  • cristiann
And I'm taking you all the fun of doing them ...:)
anonymous
  • anonymous
REFER http://www.wolframalpha.com/input/?i=solve%7B10%5E%5B%2810%5E%28x%2B11%29%29+%2B%280.5%5E%28x%2B11%29%29%5D+%3D0%7D

Looking for something else?

Not the answer you are looking for? Search for more explanations.