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anonymous
 5 years ago
find the definite integral y = x(1x) from 2 to 2
anonymous
 5 years ago
find the definite integral y = x(1x) from 2 to 2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can multiply the x into the parenthese and obtain:dw:1324593176181:dw, then its just routine

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0integrate and evaluate at the limits

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you please further elaborate thankx

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}(xx^2) dx=\frac{x^{1+1}}{1+1}\frac{x^{2+1}}{2+1}+C\] \[\int\limits_{a}^{b}f(x) dx=F(x)_a^b=F(b)F(a)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0man, i caught up with something else, or else i would have explained it to you. But the one above me, did a fairly good job

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you @ lagrangeson678 ^.^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myininaya what did you get as your answer?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i found the antiderivative now all you have to do is: (just plug in upper limit) then write minus (then plug in lower limit)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh because i got a negative answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and according to the solution booklet it is a positive answer i.e 17/3 square units

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1324594394344:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1324594437592:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes and i got 16/3 square units

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Chek out the graph of this fucntion: http://www.wolframalpha.com/input/?i=integral+y+%3D+x%281x%29+%5B2%2C2%5D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you notice anything?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes the area is below the x axis, but how come in the solution book to this question, their answer is 17/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH I SEE!!!!!!!!!! THANKS HEAPS

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but why were you saying 17/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh thats what the solution book says

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is negative

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\limits_{}^{}(xx^2) dx=\frac{x^{1+1}}{1+1}\frac{x^{2+1}}{2+1}+C \] \[\int\limits_{2}^{2}(xx^2) dx=[\frac{x^2}{2}\frac{x^3}{3}]^2_{2}=[\frac{2^2}{2}\frac{2^3}{3}][\frac{(2)^2}{2}\frac{(2)^3}{3}]\] \[=[2\frac{8}{3}][2+\frac{8}{3}]=2\frac{8}{3}2\frac{8}{3}=22\frac{8}{3}\frac{8}{3}=0\frac{16}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANK YOU @ MYININAYA
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