A community for students.
Here's the question you clicked on:
 0 viewing
virtus
 4 years ago
find the definite integral y = x(1x) from 2 to 2
virtus
 4 years ago
find the definite integral y = x(1x) from 2 to 2

This Question is Closed

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2you can multiply the x into the parenthese and obtain:dw:1324593176181:dw, then its just routine

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2integrate and evaluate at the limits

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1could you please further elaborate thankx

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}(xx^2) dx=\frac{x^{1+1}}{1+1}\frac{x^{2+1}}{2+1}+C\] \[\int\limits_{a}^{b}f(x) dx=F(x)_a^b=F(b)F(a)\]

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2man, i caught up with something else, or else i would have explained it to you. But the one above me, did a fairly good job

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1thank you @ lagrangeson678 ^.^

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1myininaya what did you get as your answer?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0i found the antiderivative now all you have to do is: (just plug in upper limit) then write minus (then plug in lower limit)

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1oh because i got a negative answer

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1and according to the solution booklet it is a positive answer i.e 17/3 square units

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1324594394344:dw

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1324594437592:dw

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1yes and i got 16/3 square units

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2Chek out the graph of this fucntion: http://www.wolframalpha.com/input/?i=integral+y+%3D+x%281x%29+%5B2%2C2%5D

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2Do you notice anything?

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1yes the area is below the x axis, but how come in the solution book to this question, their answer is 17/3?

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1OH I SEE!!!!!!!!!! THANKS HEAPS

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2but why were you saying 17/3

virtus
 4 years ago
Best ResponseYou've already chosen the best response.1oh thats what the solution book says

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.2The answer is negative

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\limits_{}^{}(xx^2) dx=\frac{x^{1+1}}{1+1}\frac{x^{2+1}}{2+1}+C \] \[\int\limits_{2}^{2}(xx^2) dx=[\frac{x^2}{2}\frac{x^3}{3}]^2_{2}=[\frac{2^2}{2}\frac{2^3}{3}][\frac{(2)^2}{2}\frac{(2)^3}{3}]\] \[=[2\frac{8}{3}][2+\frac{8}{3}]=2\frac{8}{3}2\frac{8}{3}=22\frac{8}{3}\frac{8}{3}=0\frac{16}{3}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.