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 3 years ago
Seven people are in an elevator which stops at ten
floors. In how many ways
can they get o the elevator...
 3 years ago
Seven people are in an elevator which stops at ten floors. In how many ways can they get o the elevator...

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FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3what is the answer ?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3@across: I don't think that's the right answer.

vishal_kothari
 3 years ago
Best ResponseYou've already chosen the best response.10(a) 7^10 (b) 10^7

vishal_kothari
 3 years ago
Best ResponseYou've already chosen the best response.10answer lies between this two...

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3answer is \( 10^7 \) then.

AnwarA
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, I think the answer that across gave assumed that each one gets off in a different floor?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3The problem is modeled as " how many ways can n distinct object can be divided in r distinct groups " some groups may be empty.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3My earlier answer assumes the superset and I over counted few other cases.

across
 3 years ago
Best ResponseYou've already chosen the best response.0Think of it in smaller terms: suppose there are three floors and two people; they can get off the elevator in 9 different ways, which is \(3^2\) as FFM's model states.\[\]

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3Precisely, my earlier answer assumes that the seven people need not to get off the elevator at all and only some of them get down and all of the other obvious cases.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3@across: wanna try a variation " atleast one should get off in each floor" ? ; )

across
 3 years ago
Best ResponseYou've already chosen the best response.0In this case, though, there are more floors than there are people. :p

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3@vishal kothari: It's a bit hard, don't attempt it if you don't need it.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3@across: well just increase the numbers :P

across
 3 years ago
Best ResponseYou've already chosen the best response.0Let's try 7 floors and 10 people.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3or more generally any \( r \gt n \)

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3Sorry it should be: or more generally any \( r<n \) pertaining to my above model.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3@across: Sorry, that doesn't seem correct, as \( n^{ \underline{r} } \) is not the correct assumption, generally people attempt it with mutual inclusionexclusion, but there is a even clever way, If you want I can give you a hint but it would be probably a spoiler.

pokemon23
 3 years ago
Best ResponseYou've already chosen the best response.1anyone willing to explain me about square roots?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3Anyways, always excuse my solecism :P

robtobey
 3 years ago
Best ResponseYou've already chosen the best response.0Assume that the elevator riders are considered indistinguishable, for example, 7 warm bodies. There are 11440 ways for them to get off of an elevator servicing 10 floors. http://2000clicks.com/mathhelp/CountingObjectsInBoxes.aspx Refer to: Indistinguishable Objects to Distinguishable Boxes The number of different ways to distribute n indistinguishable balls into k distinguishable boxes is C(n+k1,k1). For those who have access to Mathematica the following is a user defined function called Elevator where r is the number of riders and f is the number of floors. Elevator[ r_ , f_ ] := Binomial[ r + f  1, f  1]
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