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  • 4 years ago

Double Integration Question originally asked by Jyqft: My Integration is a bit rusty, but I found this problem interesting... Could some show me step by step how you get to the answer? From the discussion I understood so far (hope I got it right): \[\int\limits\limits_1^2\int\limits\limits_0^{\frac{2-x}{2}} e^{y-y^2} dy dx\] \[=\int\limits\limits_0^{1/2}\int\limits\limits_0^{2-2y} e^{y-y^2} dx dy\]

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  1. Mr.Math
    • 4 years ago
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    Medals 2

    The new limits are not correct. dx should be between 1 and 2-2y.

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