nubeer
  • nubeer
find the area of the surface generated by revolving r^2=cos2x about y axis. this question is related to polar coordinates.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathmate
  • mathmate
|dw:1324838256977:dw| The function resembles two leaves defined between -pi/4 to pi/4, and from 3pi/4 to 5pi/4. Outside of these limits, r is not defined in real. Is this what you expect?
mathmate
  • mathmate
Question: is the "x" in r^2=cos2x meant to be theta, or is this x equals rcos(theta)?
nubeer
  • nubeer
yes was theta i just changed in x

Looking for something else?

Not the answer you are looking for? Search for more explanations.