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nubeer

  • 2 years ago

find the area of the surface generated by revolving r^2=cos2x about y axis. this question is related to polar coordinates.

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  1. mathmate
    • 2 years ago
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    |dw:1324838256977:dw| The function resembles two leaves defined between -pi/4 to pi/4, and from 3pi/4 to 5pi/4. Outside of these limits, r is not defined in real. Is this what you expect?

  2. mathmate
    • 2 years ago
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    Question: is the "x" in r^2=cos2x meant to be theta, or is this x equals rcos(theta)?

  3. nubeer
    • 2 years ago
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    yes was theta i just changed in x

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spraguer (Moderator)
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