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hey, would someone tell me how to integrate log(2x+3)?
it was suppose to be easy, but still haven't reached the right answer.
 2 years ago
 2 years ago
hey, would someone tell me how to integrate log(2x+3)? it was suppose to be easy, but still haven't reached the right answer.
 2 years ago
 2 years ago

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LagrangeSon678Best ResponseYou've already chosen the best response.1
okay this is what we got:dw:1324944796665:dw
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
This is not a natural logarithm?
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.1
okay, then i think a simple usub should do the trick, and then its cake from there
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.1
The anit derivative of lnx, using integration by part is: x(lnx1)+C
 2 years ago

pagliaBest ResponseYou've already chosen the best response.0
yes, that's what i tried. it was suppose to give (x+3/2)ln(2x+3)x can't get the second term, probably something small that I didn't notice. thanks!
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.1
dw:1324945416421:dw
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
@ lagrange http://omega.albany.edu:8008/Symbols.html
 2 years ago
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