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paglia
hey, would someone tell me how to integrate log(2x+3)? it was suppose to be easy, but still haven't reached the right answer.
okay this is what we got:|dw:1324944796665:dw|
This is not a natural logarithm?
okay, then i think a simple u-sub should do the trick, and then its cake from there
The anit derivative of lnx, using integration by part is: x(lnx-1)+C
yes, that's what i tried. it was suppose to give (x+3/2)ln(2x+3)-x can't get the second term, probably something small that I didn't notice. thanks!
|dw:1324945416421:dw|
@ lagrange http://omega.albany.edu:8008/Symbols.html