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paglia

  • 4 years ago

hey, would someone tell me how to integrate log(2x+3)? it was suppose to be easy, but still haven't reached the right answer.

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  1. LagrangeSon678
    • 4 years ago
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    okay this is what we got:|dw:1324944796665:dw|

  2. TuringTest
    • 4 years ago
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    This is not a natural logarithm?

  3. paglia
    • 4 years ago
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    yes.

  4. LagrangeSon678
    • 4 years ago
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    okay, then i think a simple u-sub should do the trick, and then its cake from there

  5. LagrangeSon678
    • 4 years ago
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    The anit derivative of lnx, using integration by part is: x(lnx-1)+C

  6. paglia
    • 4 years ago
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    yes, that's what i tried. it was suppose to give (x+3/2)ln(2x+3)-x can't get the second term, probably something small that I didn't notice. thanks!

  7. LagrangeSon678
    • 4 years ago
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    |dw:1324945416421:dw|

  8. TuringTest
    • 4 years ago
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    @ lagrange http://omega.albany.edu:8008/Symbols.html

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