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hugsandkisses Group Title

Quadrilateral WXYZ is located at W(3, 6), X(5, -10), Y(-2, -4), Z(-4, 8). A rotation of the quadrilateral is located at W�(-6, 3), X�(10, 5), Y�(4, -2), Z�(-8, -4). How is the quadrilateral transformed? A. Quadrilateral WXYZ is rotated 90º counterclockwise about the origin B. Quadrilateral WXYZ is rotated 90º clockwise about the origin C. Quadrilateral WXYZ is rotated 180º about the origin D. Quadrilateral WXYZ is rotated 45º about the origin

  • 2 years ago
  • 2 years ago

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  1. TuringTest Group Title
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    hmm... it looks like all the coordinates are changing from\[(a,b)\to(-b,a)\]I wonder what that means.

    • 2 years ago
  2. hugsandkisses Group Title
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    I wonder what that means too!

    • 2 years ago
  3. TuringTest Group Title
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    pretty sure meverett will tell you

    • 2 years ago
  4. meverett04 Group Title
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    Draw a picture of the original shape. Then like the previous one, draw four circles for W, X, Y and Z. We have the 180 degree rotation again. C is our answer

    • 2 years ago
  5. hugsandkisses Group Title
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    I dont understand the rotations thing though. is there a formula, or do I have to draw everytime?

    • 2 years ago
  6. meverett04 Group Title
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    I am a visual learner, I draw the picture every time. @Turing, do you have a formula?

    • 2 years ago
  7. TuringTest Group Title
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    When you see the coordinates change from... \[(a,b)\to(-b,a)\]that means.a means counter-clockwise rotation 90 degrees clockwise is this change\[(a,b)\to(b,-a)\]the opposite of course. 180deg is\[(a,b)\to(-a,-b)\]which is obvious if you think about it. So I guess I do...

    • 2 years ago
  8. hugsandkisses Group Title
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    Oh, I see

    • 2 years ago
  9. meverett04 Group Title
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    Why does this work Turing?

    • 2 years ago
  10. TuringTest Group Title
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    I can recall that only because I just did it yesterday The real formula is done with matrices, but gives the same result.

    • 2 years ago
  11. TuringTest Group Title
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    I will show you the actual formula...

    • 2 years ago
  12. hugsandkisses Group Title
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    thankyou

    • 2 years ago
  13. TuringTest Group Title
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    you don't want it hugsandkisses it is above your level sorry...

    • 2 years ago
  14. hugsandkisses Group Title
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    Haha, alright. thanks for trying though

    • 2 years ago
  15. TuringTest Group Title
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    this multiplication maps a vector onto itself:\[(a,b)\left[\begin{matrix}1 & 0 \\ 0 & 1\end{matrix}\right]\]...

    • 2 years ago
  16. TuringTest Group Title
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    this one turns it 180 degrees\[(a,b)\left[\begin{matrix}-1 & 0 \\ 0 & -1\end{matrix}\right]\]

    • 2 years ago
  17. hugsandkisses Group Title
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    umm.. thanks for trying to explain it to me :P

    • 2 years ago
  18. TuringTest Group Title
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    here is 90 deg closkwise\[(a,b)\left[\begin{matrix}0 & -1 \\ 1 & 0\end{matrix}\right]\]and counter-clockwise is\[(a,b)\left[\begin{matrix}0 & 1 \\ -1 & 0\end{matrix}\right]\]

    • 2 years ago
  19. hugsandkisses Group Title
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    thanks again for trying sir!

    • 2 years ago
  20. meverett04 Group Title
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    Hmmm ... I have some reading to due .... thank you for the start ...

    • 2 years ago
  21. TuringTest Group Title
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    but for you hugs and kisses just use what I gave above. I actually gave you the answer is you put my posts together.

    • 2 years ago
  22. TuringTest Group Title
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    not the matrices The part with the arrows

    • 2 years ago
  23. hugsandkisses Group Title
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    the arrows thing was much easier, thanks a ton

    • 2 years ago
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