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hugsandkisses

  • 3 years ago

Quadrilateral WXYZ is located at W(3, 6), X(5, -10), Y(-2, -4), Z(-4, 8). A rotation of the quadrilateral is located at W�(-6, 3), X�(10, 5), Y�(4, -2), Z�(-8, -4). How is the quadrilateral transformed? A. Quadrilateral WXYZ is rotated 90º counterclockwise about the origin B. Quadrilateral WXYZ is rotated 90º clockwise about the origin C. Quadrilateral WXYZ is rotated 180º about the origin D. Quadrilateral WXYZ is rotated 45º about the origin

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  1. TuringTest
    • 3 years ago
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    hmm... it looks like all the coordinates are changing from\[(a,b)\to(-b,a)\]I wonder what that means.

  2. hugsandkisses
    • 3 years ago
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    I wonder what that means too!

  3. TuringTest
    • 3 years ago
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    pretty sure meverett will tell you

  4. meverett04
    • 3 years ago
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    Draw a picture of the original shape. Then like the previous one, draw four circles for W, X, Y and Z. We have the 180 degree rotation again. C is our answer

  5. hugsandkisses
    • 3 years ago
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    I dont understand the rotations thing though. is there a formula, or do I have to draw everytime?

  6. meverett04
    • 3 years ago
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    I am a visual learner, I draw the picture every time. @Turing, do you have a formula?

  7. TuringTest
    • 3 years ago
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    When you see the coordinates change from... \[(a,b)\to(-b,a)\]that means.a means counter-clockwise rotation 90 degrees clockwise is this change\[(a,b)\to(b,-a)\]the opposite of course. 180deg is\[(a,b)\to(-a,-b)\]which is obvious if you think about it. So I guess I do...

  8. hugsandkisses
    • 3 years ago
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    Oh, I see

  9. meverett04
    • 3 years ago
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    Why does this work Turing?

  10. TuringTest
    • 3 years ago
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    I can recall that only because I just did it yesterday The real formula is done with matrices, but gives the same result.

  11. TuringTest
    • 3 years ago
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    I will show you the actual formula...

  12. hugsandkisses
    • 3 years ago
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    thankyou

  13. TuringTest
    • 3 years ago
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    you don't want it hugsandkisses it is above your level sorry...

  14. hugsandkisses
    • 3 years ago
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    Haha, alright. thanks for trying though

  15. TuringTest
    • 3 years ago
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    this multiplication maps a vector onto itself:\[(a,b)\left[\begin{matrix}1 & 0 \\ 0 & 1\end{matrix}\right]\]...

  16. TuringTest
    • 3 years ago
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    this one turns it 180 degrees\[(a,b)\left[\begin{matrix}-1 & 0 \\ 0 & -1\end{matrix}\right]\]

  17. hugsandkisses
    • 3 years ago
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    umm.. thanks for trying to explain it to me :P

  18. TuringTest
    • 3 years ago
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    here is 90 deg closkwise\[(a,b)\left[\begin{matrix}0 & -1 \\ 1 & 0\end{matrix}\right]\]and counter-clockwise is\[(a,b)\left[\begin{matrix}0 & 1 \\ -1 & 0\end{matrix}\right]\]

  19. hugsandkisses
    • 3 years ago
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    thanks again for trying sir!

  20. meverett04
    • 3 years ago
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    Hmmm ... I have some reading to due .... thank you for the start ...

  21. TuringTest
    • 3 years ago
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    but for you hugs and kisses just use what I gave above. I actually gave you the answer is you put my posts together.

  22. TuringTest
    • 3 years ago
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    not the matrices The part with the arrows

  23. hugsandkisses
    • 3 years ago
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    the arrows thing was much easier, thanks a ton

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