anonymous
  • anonymous
Quadrilateral WXYZ is located at W(3, 6), X(5, -10), Y(-2, -4), Z(-4, 8). A rotation of the quadrilateral is located at W�(-6, 3), X�(10, 5), Y�(4, -2), Z�(-8, -4). How is the quadrilateral transformed? A. Quadrilateral WXYZ is rotated 90º counterclockwise about the origin B. Quadrilateral WXYZ is rotated 90º clockwise about the origin C. Quadrilateral WXYZ is rotated 180º about the origin D. Quadrilateral WXYZ is rotated 45º about the origin
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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TuringTest
  • TuringTest
hmm... it looks like all the coordinates are changing from\[(a,b)\to(-b,a)\]I wonder what that means.
anonymous
  • anonymous
I wonder what that means too!
TuringTest
  • TuringTest
pretty sure meverett will tell you

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More answers

anonymous
  • anonymous
Draw a picture of the original shape. Then like the previous one, draw four circles for W, X, Y and Z. We have the 180 degree rotation again. C is our answer
anonymous
  • anonymous
I dont understand the rotations thing though. is there a formula, or do I have to draw everytime?
anonymous
  • anonymous
I am a visual learner, I draw the picture every time. @Turing, do you have a formula?
TuringTest
  • TuringTest
When you see the coordinates change from... \[(a,b)\to(-b,a)\]that means.a means counter-clockwise rotation 90 degrees clockwise is this change\[(a,b)\to(b,-a)\]the opposite of course. 180deg is\[(a,b)\to(-a,-b)\]which is obvious if you think about it. So I guess I do...
anonymous
  • anonymous
Oh, I see
anonymous
  • anonymous
Why does this work Turing?
TuringTest
  • TuringTest
I can recall that only because I just did it yesterday The real formula is done with matrices, but gives the same result.
TuringTest
  • TuringTest
I will show you the actual formula...
anonymous
  • anonymous
thankyou
TuringTest
  • TuringTest
you don't want it hugsandkisses it is above your level sorry...
anonymous
  • anonymous
Haha, alright. thanks for trying though
TuringTest
  • TuringTest
this multiplication maps a vector onto itself:\[(a,b)\left[\begin{matrix}1 & 0 \\ 0 & 1\end{matrix}\right]\]...
TuringTest
  • TuringTest
this one turns it 180 degrees\[(a,b)\left[\begin{matrix}-1 & 0 \\ 0 & -1\end{matrix}\right]\]
anonymous
  • anonymous
umm.. thanks for trying to explain it to me :P
TuringTest
  • TuringTest
here is 90 deg closkwise\[(a,b)\left[\begin{matrix}0 & -1 \\ 1 & 0\end{matrix}\right]\]and counter-clockwise is\[(a,b)\left[\begin{matrix}0 & 1 \\ -1 & 0\end{matrix}\right]\]
anonymous
  • anonymous
thanks again for trying sir!
anonymous
  • anonymous
Hmmm ... I have some reading to due .... thank you for the start ...
TuringTest
  • TuringTest
but for you hugs and kisses just use what I gave above. I actually gave you the answer is you put my posts together.
TuringTest
  • TuringTest
not the matrices The part with the arrows
anonymous
  • anonymous
the arrows thing was much easier, thanks a ton

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