need some help im getting 311

- waheguru

need some help im getting 311

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- schrodinger

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- anonymous

ok

- jhonyy9

???

- karatechopper

311?

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## More answers

- waheguru

im posting the question sorry

- waheguru

##### 1 Attachment

- waheguru

here we are

- anonymous

Do you have the formula for the surface area of a cylinder?

- waheguru

2pirsq plus 2pirh

- anonymous

Surface area of fully cylinder = circumference * length. Here, you have half of it. So, 1/2*circumference*length = 1/2 * pi * 6 * 30 = 90 * pi

- jhonyy9

a.

- anonymous

waheguru - that is when including bottom and top circles. In this case, the roof has no such thing. So, you just need 1/2 circumference * length.

- asnaseer

@GT is right

- waheguru

oh so i included the bottom???

- anonymous

Yeah. Don't.

- waheguru

k so this is what i did
2 x pi x 3^2 + 2 x pi x 3 x 30 and divide by 2

- anonymous

hi

- anonymous

Remove 3*pi*r^2 and the rest is good.

- waheguru

y

- jhonyy9

a. is right sure

- anonymous

Because the roof does not have a base and top (according to the problem description).

- asnaseer

the question is asking for the area of the roofs curved surface - that does not include the two ends of the greenhouse

- waheguru

so just the lateral

- anonymous

yes.

- waheguru

thx brozz

- asnaseer

the curved surface of a cylinder has a surface area of \(2\pi rh\). in this case you have half a cylinder, so the surface area becomes \(\pi rh\)

- anonymous

HI GUYS

- waheguru

just practising for grade 9 EQAO

- asnaseer

what is EQAO?

- waheguru

evil questions attacking ontario lol im kidding its like an exam for grade 9 students

- asnaseer

lol! :-D - good luck with them...

- waheguru

thx

- jhonyy9

is half perimeter of base multiply lenght=surface area

- jhonyy9

this very easy

- asnaseer

@jhonyy9 - things are always easy when you know how to do them - try and recall the days when you were also at the lower end of the learning curve :-)

- asnaseer

like we ALL were

- jhonyy9

yes right but this is the same like a rectangle curved on the base

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