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Thanks in advance!

happy new yr in advance!

really? are you sure that's good?
does it work for indefinite?

It's a special case if that right?

brilliant, man!
good show!

wow

@jemurray3 - many thanks for the link - you sir are a star ;-)

Many thanks :)

This is much more clear than Wikipedia
Much thanks to you!

Whoa. not under the equals sign, under the integral sign o.0 haha

Make that
\[\sqrt{\frac{\pi}{a}} e^{\frac{-1}{4a}} \]
not my day with typos.... :)