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anonymous
 5 years ago
in how many ways can 6 people be arranged in a circle if 2 particular people are always separated?
anonymous
 5 years ago
in how many ways can 6 people be arranged in a circle if 2 particular people are always separated?

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TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8how many different places can the two people take in the circle of six of they cannot sit next to each other?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8question above?dw:1325222124878:dwhere is our circle of six. imagine the two people who cannot sit next to each other. How many different configurations can they be in?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8say joe sits at 1 and bob can't sit next to joe, where can he sit?dw:1325222254760:dwit looks like there are three possible places bob can sit for every place joe might sit. what about the rest? how many permutations can they take on for each possible configuration of joe and bob?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8does the order matter? does it matter who sits where? or is it just the relation between the people?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont think order matters

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe you could calculate all the possible combinations and just substract the one in which the 2 people are next each other

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8then it is three what about the rest of the people, how many configurations can they take on for each configuration of bob and joe?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8how many seats are there beside bob and joe?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8and how many permutations can those four seats have for each configuration of bob and joe?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhhhhhhhhhhhhhhh i think i have got it, is it 4! x 3=72?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8should be if the order doesn't matter :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0one more thing could you help me check this question because my ans is different to the one in the solution book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in how many ways can 5 boys and 3 women be arranged in a row?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't think there is any order so would it be 8!

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8do you know 8! is wrong? because that's what it looks like to me too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok well the solution books says the answ is 4320, maybe you could work from this

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8it looks like 8!=40320 with a zero missing to me :/ I'd have to think of another solution...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha that is exactly what i thought

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0I hope you don't mind me going back to the first question for a moment. The answer of 72, is that the final answer or is that just the amount for the first person in one position? Wouldn't the answer be 72 * 6 to account for each position the first of the two people could be in? I'm going to be taking combinatorics in the upcoming semester, and I am guessing that I will be seeing alot of these kind of problems. btw, I agree with 8! on the second problem as well, but can't say for sure that is right.

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8The first one had 2 people who could take the drivers seat, so that's just one seat to be filled by the people, so you don't have to look for other positions of the people. When each of them is driving the rest of the people have 5! permutations of seats in the car. Since there are only two possible configurations for the driver, and 5! permutations of the remaining seats for each driver, the total is 2(5!)=240 I really don't think I know about this last one though...

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8I'd imagine across and Zarkon do, but they are being quiet...

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8oh you meant the first question on this post ChrisS?

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8Oh, yes it would be 72*6 if where they sat mattered, but we decided it didn't, just the relative configurations of the people.

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0I meant the first problem in this specific thread, the circle with six positions and two specific people cant sit next to each other. so for a given position of the first person, there are three spots the second person can be. Add in the other four positions where the order doesn't matter and you get the answer you arrived at of 3(4!)=72. But if you shift the first person through each of the 6 positions, doesn't each of those have to be added in to the total for a total of 72*6 or 432?

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0ok... I see you answered while I was typing lol

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8since there are only 3 configurations of the two people if it doesn't matter where they sat. If it does you get your answer yep, sorry for the miscommunication

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0Well I think the four extra people it doesn't matter, but since it does matter between the two specific people, then it seems like with respect to the first person that each scenario should be accounted for.

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8That is the other possibility, so we should point that out to the questioner: @virtus: If the seating matters then the answer is what ChrisS said, if not then it is what we found earlier. still don't know about your last one.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0AWWW THANK YOU SO MUCH GUYS, but i think the question does not take order into mind as in the solution book the answer is 72

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.8there you go... happy to help!

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah I was sitting here thinking about it and I guess it all boils down to "spots" being occupied on a circle which is how I was imagining it, or just a circle with 6 people in various configurations which by the answer is obviously how it was intended.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0however, i tried your method turning test on another similar question and i don't think i'm quite getting the right answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0father, mother and 6 children stand in a ring. In how many ways can they be arranged if father and mother are not to stand together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if we fix the father then the mother has 4 alternative places where she can stand right? and the 6 kids can stand in any order so they will be 6!

ChrisS
 5 years ago
Best ResponseYou've already chosen the best response.0I got 5 alternative places when I drew out my circle of 8 spots. ^ for the kids and two for the parents.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhhhhh indeed my bad

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorrry that was my mistake hehehehe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok heres another question i'm stuck on How many even numbers of 4 digits can be formed with the figures 3,4,7,8 if (a) no figure is repeated, (b) if repetitions are allowed
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