anonymous
  • anonymous
solve the inequality x^2+x-6>or equal to-4 by using a table and a graph
Mathematics
chestercat
  • chestercat
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Mr.Math
  • Mr.Math
\[x^2+x-6\ge -4 \implies x^2+x-2\ge0 \implies (x+2)(x-1)\ge0 \]
anonymous
  • anonymous
\( \Rightarrow x \le -2 \text{ or } x \gt 1 \)
Mr.Math
  • Mr.Math
Now, you need to study the intervals as shown below: -2 1 --------------------------------- - + + x+2 - - + x-1 + - + (x+2)(x-1)

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Mr.Math
  • Mr.Math
So our intervals are then \((-\infty,-2] + [1,\infty) \).
anonymous
  • anonymous
Just a minute typo: \[ \Rightarrow x \le -2 \text{ or } x \ge 1 \]
Mr.Math
  • Mr.Math
Yeah.
anonymous
  • anonymous
Thanks!
Mr.Math
  • Mr.Math
What's the latex for union? @FFM
anonymous
  • anonymous
\( \cup \cap \)
Mr.Math
  • Mr.Math
lol
anonymous
  • anonymous
;)

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