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studyopen101 Group Title

solve the inequality x^2+x-6>or equal to-4 by using a table and a graph

  • 2 years ago
  • 2 years ago

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  1. Mr.Math Group Title
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    \[x^2+x-6\ge -4 \implies x^2+x-2\ge0 \implies (x+2)(x-1)\ge0 \]

    • 2 years ago
  2. FoolForMath Group Title
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    \( \Rightarrow x \le -2 \text{ or } x \gt 1 \)

    • 2 years ago
  3. Mr.Math Group Title
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    Now, you need to study the intervals as shown below: -2 1 --------------------------------- - + + x+2 - - + x-1 + - + (x+2)(x-1)

    • 2 years ago
  4. Mr.Math Group Title
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    So our intervals are then \((-\infty,-2] + [1,\infty) \).

    • 2 years ago
  5. FoolForMath Group Title
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    Just a minute typo: \[ \Rightarrow x \le -2 \text{ or } x \ge 1 \]

    • 2 years ago
  6. Mr.Math Group Title
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    Yeah.

    • 2 years ago
  7. studyopen101 Group Title
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    Thanks!

    • 2 years ago
  8. Mr.Math Group Title
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    What's the latex for union? @FFM

    • 2 years ago
  9. FoolForMath Group Title
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    \( \cup \cap \)

    • 2 years ago
  10. Mr.Math Group Title
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    lol

    • 2 years ago
  11. FoolForMath Group Title
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    ;)

    • 2 years ago
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