anonymous
  • anonymous
What is the value of h in the function f(x)=1/2(x=5)2-9? A. 5 B. 1/2 C. 9 D. -5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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across
  • across
I am very confused: Why do you have a second equals sign in the middle of the function, and where is h?
anonymous
  • anonymous
they didnt give me an h value :-/ and that was supposed to be x=5
across
  • across
I am now more confused. n_n

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myininaya
  • myininaya
what? I'm confused too. The way you typed your problem is that exactly the way it looks?
anonymous
  • anonymous
yeah. but the 2 is small and its raised
myininaya
  • myininaya
and inside the parenthesis is x=5?
myininaya
  • myininaya
\[f(x)=\frac{1}{2}(x \pm 5)^2-9\] i think it should either be + or -
across
  • across
\[f(x)=\frac{1}{2}(x=5)^2-9...\]I can't seem to make any sense of this.
myininaya
  • myininaya
and I'm assuming you want to find the x coordinate of the parabola
anonymous
  • anonymous
Ummm, I guess.. I dont know. Im really really bad at math
myininaya
  • myininaya
can you write the function down one more time?
myininaya
  • myininaya
and i meant x coordinate of the vertex of the parabola lol
anonymous
  • anonymous
f(x)=1/2(x+5)2-9
myininaya
  • myininaya
ok great!
myininaya
  • myininaya
now it makes more sense
anonymous
  • anonymous
oh. sorry! haha
myininaya
  • myininaya
\[f(x)=\frac{1}{2}(x+5)^2-9\] \[f(x)=a(x-h)^2+k\] what is h?
myininaya
  • myininaya
well we want -h=5 right?
myininaya
  • myininaya
so if -h=5, then h=?
anonymous
  • anonymous
-5? lol sorry, im super weak in math
myininaya
  • myininaya
-5 is tight!
myininaya
  • myininaya
i mean right*
anonymous
  • anonymous
YAY!! :D
anonymous
  • anonymous
can you help me with more? Ive got a ton
myininaya
  • myininaya
Ok
myininaya
  • myininaya
But you have to give me a sprite or dr. pepper
anonymous
  • anonymous
I'll give you both!
myininaya
  • myininaya
lol
myininaya
  • myininaya
ok thanks for the imaginary soda

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