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they didnt give me an h value :-/
and that was supposed to be x=5

I am now more confused. n_n

what? I'm confused too. The way you typed your problem is that exactly the way it looks?

yeah. but the 2 is small and its raised

and inside the parenthesis is x=5?

\[f(x)=\frac{1}{2}(x \pm 5)^2-9\]
i think it should either be + or -

\[f(x)=\frac{1}{2}(x=5)^2-9...\]I can't seem to make any sense of this.

and I'm assuming you want to find the x coordinate of the parabola

Ummm, I guess.. I dont know. Im really really bad at math

can you write the function down one more time?

and i meant x coordinate of the vertex of the parabola lol

f(x)=1/2(x+5)2-9

ok great!

now it makes more sense

oh. sorry! haha

\[f(x)=\frac{1}{2}(x+5)^2-9\]
\[f(x)=a(x-h)^2+k\]
what is h?

well we want -h=5 right?

so if -h=5, then h=?

-5? lol sorry, im super weak in math

-5 is tight!

i mean right*

YAY!! :D

can you help me with more? Ive got a ton

Ok

But you have to give me a sprite or dr. pepper

I'll give you both!

lol

ok thanks for the imaginary soda