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What is the value of h in the function f(x)=1/2(x=5)2-9? A. 5 B. 1/2 C. 9 D. -5

Mathematics
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I am very confused: Why do you have a second equals sign in the middle of the function, and where is h?
they didnt give me an h value :-/ and that was supposed to be x=5
I am now more confused. n_n

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Other answers:

what? I'm confused too. The way you typed your problem is that exactly the way it looks?
yeah. but the 2 is small and its raised
and inside the parenthesis is x=5?
\[f(x)=\frac{1}{2}(x \pm 5)^2-9\] i think it should either be + or -
\[f(x)=\frac{1}{2}(x=5)^2-9...\]I can't seem to make any sense of this.
and I'm assuming you want to find the x coordinate of the parabola
Ummm, I guess.. I dont know. Im really really bad at math
can you write the function down one more time?
and i meant x coordinate of the vertex of the parabola lol
f(x)=1/2(x+5)2-9
ok great!
now it makes more sense
oh. sorry! haha
\[f(x)=\frac{1}{2}(x+5)^2-9\] \[f(x)=a(x-h)^2+k\] what is h?
well we want -h=5 right?
so if -h=5, then h=?
-5? lol sorry, im super weak in math
-5 is tight!
i mean right*
YAY!! :D
can you help me with more? Ive got a ton
Ok
But you have to give me a sprite or dr. pepper
I'll give you both!
lol
ok thanks for the imaginary soda

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