hugsandkisses
What is the value of h in the function f(x)=1/2(x=5)29?
A. 5
B. 1/2
C. 9
D. 5



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across
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I am very confused: Why do you have a second equals sign in the middle of the function, and where is h?

hugsandkisses
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they didnt give me an h value :/
and that was supposed to be x=5

across
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I am now more confused. n_n

myininaya
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what? I'm confused too. The way you typed your problem is that exactly the way it looks?

hugsandkisses
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yeah. but the 2 is small and its raised

myininaya
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and inside the parenthesis is x=5?

myininaya
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\[f(x)=\frac{1}{2}(x \pm 5)^29\]
i think it should either be + or 

across
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\[f(x)=\frac{1}{2}(x=5)^29...\]I can't seem to make any sense of this.

myininaya
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and I'm assuming you want to find the x coordinate of the parabola

hugsandkisses
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Ummm, I guess.. I dont know. Im really really bad at math

myininaya
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can you write the function down one more time?

myininaya
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and i meant x coordinate of the vertex of the parabola lol

hugsandkisses
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f(x)=1/2(x+5)29

myininaya
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ok great!

myininaya
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now it makes more sense

hugsandkisses
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oh. sorry! haha

myininaya
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\[f(x)=\frac{1}{2}(x+5)^29\]
\[f(x)=a(xh)^2+k\]
what is h?

myininaya
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well we want h=5 right?

myininaya
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so if h=5, then h=?

hugsandkisses
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5? lol sorry, im super weak in math

myininaya
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5 is tight!

myininaya
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i mean right*

hugsandkisses
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YAY!! :D

hugsandkisses
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can you help me with more? Ive got a ton

myininaya
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Ok

myininaya
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But you have to give me a sprite or dr. pepper

hugsandkisses
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I'll give you both!

myininaya
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lol

myininaya
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ok thanks for the imaginary soda