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sorry. its x-3y= 12 2x-y=1
you looking to graph both and find where they intersect?
will look like this
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\[y = (x+12)/3,y = 2 x-1\]
if you are going to do it by hand, probably the best think to do if fine the intercepts
\[x-3y=12\] find the x intercept by setting y = 0 get
\[x=12\] so you know (12,0) is on the graph. for the y - intercept set x = 0 and get
\[-3y=12\implies y=-4\] so you know (0,-4) is on the graph. plot those two points, connect the dots
repeat the process for
\[2x-y=1\] or else rewrite as earthcitizen wrote as
\[y=2x-1\] and then replace x by some well chosen numbers and find a couple points