Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

oh sorry f=guys but i deleted my question by a mastake could u tell me the answer again the problem is 2y+7+-1 how do you solve this.???

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

Add the like terms. And you are not solving it. You are simplifying.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

wasnt it equal to -1? and not adding -1?
oh yes
2y + 7 = -1 (it was your original problem) 2y = -1 - 7 2y = -8 y = -4
the problem is 2y+7=-1
so u want me to show u how kat got all tht?
1) Your ultimate goal is to bring all the constants onto one side of the equal sign Therefore, lets move the + 7 to the other side by substracting 7 with -1, resulting -8
Now your left with 2y = -8 Divide by 2 to get "y" by itself y = -8/2 y = -4 is your answer when simplified
oh thx guys !! i got it now!
No Problemo =)
duha what grade r u in ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question