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abdul_shabeer
Group Title
A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be
 2 years ago
 2 years ago
abdul_shabeer Group Title
A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be
 2 years ago
 2 years ago

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yip Group TitleBest ResponseYou've already chosen the best response.0
momentum divided by time equals to force the force=\[(M \times n)\]\[\div60\]
 2 years ago

yip Group TitleBest ResponseYou've already chosen the best response.0
\[(M \times n)\div60\]
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
Right. Impulse = integral of Force over time = change in momentum ==> Force = (change in impulse)/( time) = (change of momentum) / (time)
 2 years ago

yip Group TitleBest ResponseYou've already chosen the best response.0
oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M
 2 years ago

yip Group TitleBest ResponseYou've already chosen the best response.0
Assuming it is elastic collision
 2 years ago
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