A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

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A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

Mathematics
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momentum divided by time equals to force the force=\[(M \times n)\]\[\div60\]
\[(M \times n)\div60\]
Right. Impulse = integral of Force over time = change in momentum ==> Force = (change in impulse)/( time) = (change of momentum) / (time)

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oh wait it should be 2(Mxn)รท60 because the change in momentum should be 2M
Assuming it is elastic collision

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