## anonymous 4 years ago A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

1. anonymous

momentum divided by time equals to force the force=$(M \times n)$$\div60$

2. anonymous

$(M \times n)\div60$

3. JamesJ

Right. Impulse = integral of Force over time = change in momentum ==> Force = (change in impulse)/( time) = (change of momentum) / (time)

4. anonymous

oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M

5. anonymous

Assuming it is elastic collision