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abdul_shabeer

  • 2 years ago

A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

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  1. yip
    • 2 years ago
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    momentum divided by time equals to force the force=\[(M \times n)\]\[\div60\]

  2. yip
    • 2 years ago
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    \[(M \times n)\div60\]

  3. JamesJ
    • 2 years ago
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    Right. Impulse = integral of Force over time = change in momentum ==> Force = (change in impulse)/( time) = (change of momentum) / (time)

  4. yip
    • 2 years ago
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    oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M

  5. yip
    • 2 years ago
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    Assuming it is elastic collision

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