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anonymous
 4 years ago
A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be
anonymous
 4 years ago
A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0momentum divided by time equals to force the force=\[(M \times n)\]\[\div60\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(M \times n)\div60\]

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2Right. Impulse = integral of Force over time = change in momentum ==> Force = (change in impulse)/( time) = (change of momentum) / (time)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Assuming it is elastic collision
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