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In the equation ___CH4 + ___O2 ___CO2 + ___H2O, what number will go in front of the H2O to balance the equation?

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idk that is hard lol
I guess what you mean is ___CH4 + ___O2 --> ___CO2 + ___H2O is that right?

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yeah i was going tay what james said
hi james it is snowball
i got banned made another acount thoe
well the number of atoms of each element has to balance on both sides. So if we start with one CH4 atom, we must have one CO2 atom: 1 CH4 + ___O2 --> 1 CO2 + ___H2O Now, what can you say about the other two atoms? (Hi online/snowball)
hi james
that there are a 2 of them
Did you see why with one CH4 molecule there must be one CO2 molecule? That is because with one CH4 molecule, there is only one carbon atom on the left-hand side. So there must only be one carbon atom on the right-hand side.
ok. I understand
So right now we have that 1 CH4 + ___O2 --> 1 CO2 + ___H2O Now, given that, how many hydrogen atoms must there be on the RHS (right hand side)?
Yes. And hence how many water molecules H2O must there be?
No. Each water molecule has two hydrogen atoms, that's why we write H2O and not HO
so it's 2?
Yes. Hence we now have that 1 CH4 + ___O2 --> 1 CO2 + 2 H2O Now, count up the oxygen atoms on the RHS and figure out how many O2 molecules we need on the LHS.
omh lhs iw my highschool i use to go to
right. So the final answer is 1 CH4 + 2 O2 --> 1 CO2 + 2 H2O
ok thank you
no problem
You can see that there are some more questions like this here; scroll down a bit. You might find it useful to have a look at them.
ok. I will

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