In the equation ___CH4 + ___O2 ___CO2 + ___H2O, what number will go in front of the H2O to balance the equation?

- anonymous

- schrodinger

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- anonymous

idk that is hard lol

- JamesJ

I guess what you mean is
___CH4 + ___O2 --> ___CO2 + ___H2O
is that right?

- anonymous

yes

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- anonymous

yeah i was going tay what james said

- anonymous

lol

- anonymous

hi james it is snowball

- anonymous

i got banned made another acount thoe

- JamesJ

well the number of atoms of each element has to balance on both sides. So if we start with one CH4 atom, we must have one CO2 atom:
1 CH4 + ___O2 --> 1 CO2 + ___H2O
Now, what can you say about the other two atoms?
(Hi online/snowball)

- anonymous

hi james

- anonymous

that there are a 2 of them

- anonymous

yeah

- JamesJ

Did you see why with one CH4 molecule there must be one CO2 molecule?
That is because with one CH4 molecule, there is only one carbon atom on the left-hand side. So there must only be one carbon atom on the right-hand side.

- anonymous

ok. I understand

- anonymous

good

- JamesJ

So right now we have that
1 CH4 + ___O2 --> 1 CO2 + ___H2O
Now, given that, how many hydrogen atoms must there be on the RHS (right hand side)?

- anonymous

4?

- JamesJ

Yes. And hence how many water molecules H2O must there be?

- anonymous

4

- JamesJ

No. Each water molecule has two hydrogen atoms, that's why we write H2O and not HO

- anonymous

so it's 2?

- anonymous

yes

- JamesJ

Yes. Hence we now have that
1 CH4 + ___O2 --> 1 CO2 + 2 H2O
Now, count up the oxygen atoms on the RHS and figure out how many O2 molecules we need on the LHS.

- anonymous

2

- anonymous

omh lhs iw my highschool i use to go to

- JamesJ

right. So the final answer is
1 CH4 + 2 O2 --> 1 CO2 + 2 H2O

- anonymous

ok thank you

- anonymous

no problem

- JamesJ

You can see that there are some more questions like this here; scroll down a bit. You might find it useful to have a look at them.

- anonymous

ok. I will

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