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Inopeki
Group Title
In linear equations, how do i know if i should subtract from the right side or the left side?
 2 years ago
 2 years ago
Inopeki Group Title
In linear equations, how do i know if i should subtract from the right side or the left side?
 2 years ago
 2 years ago

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karatechopper Group TitleBest ResponseYou've already chosen the best response.0
example..
 2 years ago

meverett04 Group TitleBest ResponseYou've already chosen the best response.3
I like my coefficient for x to remain positive; therefore, if I have 2x + 10 = 12x I subtract 2x from the left side and if I have 12x + 10 = 2x I subtract 2x from the right side
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
3x + 7 = 10x +5 7 = 7x +5  ^here? ^ or here?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
it really doesn't matter so long as you keep the goal in mind: get x by itself pick one and we can continue from there
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
And how much do i subtract? the whole number or so it remains +/0?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
so i got 0=7x2
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
now i need to divide 2 by 7?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no, we need the 2 on the other side of the equation that's what I mean about getting x by itself
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Ok so i dont do 0=7x2?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
if we divide by 7 now we get\[0=x\frac{2}{7}\]which is okay, we can still solve it from here; but it's a good policy to leave fractions for the end if possible. so instead add 2 to both sides to make x a little bit more alone.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I dont get it, i get like 0.29..
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
leave the answer in fraction form
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh i see, so i get 2=7x?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
right, now we divide by 7 to isolate x what is x=? (leave as a fraction)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I dont know.. 2/7?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
you do know! lol shall we do another?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
If you want more info, watch this and the next 2 videos http://www.khanacademy.org/video/simpleequations?playlist=Algebra
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
that's what he's working from phi
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Another?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Well ill be damned.. it was right!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
got one you want to post? or should I make one up?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
wait, ill try the next one. 6x+3=2x+7
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
just go ahead and see how far you get
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So i subtract 2x from both sides, getting 4x+3=7
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good, then?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Then i subtract 3 from both sides, getting 4x=4
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good, then?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
And then i divide 4 by 4 and get 1 as the final answer :D
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
well taught turing:)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
TT, you are an awesome teacher!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
tadah! nice see how you didn't need to ask me which was better, subtract 7 or 3? you knew by looking that 3 was the smart way to go :) practice practice... thanks for the compliment btw
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So where do i go on from here?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
have you done ALL the exercises from this section already?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Soon. you mean until i can choose another section right?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Yes. It is imperative that you do every problem. This needs to become second nature for you when you can look at 5x3=2x+12 and tell me the answer very quickly, with almost no work shown, then you can continue
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
actually 1/3
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
nope, better keep working on it. practice practice... don't try to get ahead of yourself, if you need to write it and go slowly, do it. Don't try to shortcut past that.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
alright. but i couldnt figure the last one out, it was 6x+6=0
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I didnt know what to do there. was it 1 or 0? maybe 6?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
just try the problem and show me your steps you don't need to tell me what each step is, btw, I can see by looking
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
it was 9x+9=3x+3 6x+9=3 6x+6=0 6x= 6?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
so now what is the last step to get x all alone?
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
tht was correct now show us your next and final step
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
perfect
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
now simplify that
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
correct
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes, very good what was the last step? dividing by...?
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
that wasn't too bad now was it!
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
The number on the right?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
dividing the quantity of x by the number on the right side of =?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no, that is what I was afraid of... though you got the right answer, the 6 should have stayed on top. 6x=6 what do we divide by to isolate x?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
it's just one answer: divide by 6
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
let's try something a little different... solve xy+7=10 for x
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Note that above for 6x=6 we divided both sides by the number next to the x (i.e. 6), that is what I wanted you to see. We do not divide by the number on the right. You will see why in this next problem
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
1.5 or 2 for x
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
so now xy+7=10 you got a number answer? what happened to y? please show steps.
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
@turing does he know what he is solving for?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
solve for x thanks karate
 2 years ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
anytime turing:)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I thought that x times y would be the answer. since 1.5x2 is 3 (which was needed to make 10) i thought that x would be 1.5 or 2.(the other one being y)
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
you are overthinking Inopeki just take each step onebyone what is the first step?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Determening what i need to make to complete 10
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no the first step is the same as the others xy+7=10 subtract 7 from both sides
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
what do we have after?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good! now again, we want x by itself. it looks like x is being multiplied by y, so how can we get x by itself?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Removing y from the equation?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
y cannot leave the equation entirely, we can only shift it to one side. I mentioned that x was being multiplied by y. Do you know the inverse operation of multiplication?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
right! and in this case what do we need to divide by to get x by itself?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
close, but what do you mean "divide by y with 3"? that makes no sense again it can only be one answer divide by...?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
just to make it visible again: xy=3 what do we divide by on both sides (one answer to this question)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Ah, divide x and 3 by y?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
YES!!! and what do we have after? write the expression.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
How can i do that when i dont even know what y is?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Good question. write the answer first and I will tell you what it means after.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
You mean x/y=3/y?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
close, but on the left x should be by itself, that's why we divided by y right? so it should be...
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I GET IT NOW! because the left side was x times y we needed to isolate x so we divided x with y to reverse the effect. now it is x=3/y
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
YES!!! very good! but what does it mean...? as you said y can be any number (except zero, but we'll discuss that later) so we have x=3/y that means we have infinite solutions to this problem. To find what they are plug in various numbers for y. So what is x if y=1 y=3 y=10 ???
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no, its different for each one. Remember that I said there were infinite solutions. just plug in the numbers into the equation there is no one answer for x=3/y so plug in a number for y like y=1 what is x?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes! what about when y=3?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Excellent :) and y=10?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
better to leave it as a fraction, but yes
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
YES! I get it now!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Great! so what is going on here? it looks like we can put any value for y (except zero) and we get a number for x. THIS IS YOUR FIRST FUNCTION I told you earlier that a function takes a number as an input (in this case what we put for y is our input) and out pops another number. So x=3/y is a formula for x as a function of y. denoted x=f(y)=3/y here is a graph of your function http://www.wolframalpha.com/input/?i=f%28y%29%3D3%2Fy this line denotes all the points that are solutions. notice that some of these points (x,y) are (1,3) (3,1) (10,3/10) etc. just like you found :)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Whoa, whoa, whoa. You just made this 10x more complicated.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
look all the deal is is that you put in a number for y, you get a number back for x that's what a function is
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh! I just made a function?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Yes. Well actually it was always a function, buit you made it workable. in this case we would write that x is a function of y. f(y)=3/y
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So f(x) means that you want to pop something for y?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
exactly! if you want to find f(x) then solve\[xy+7=10\]for x instead of y
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
sorry, I meant y instead of x above
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So thats what ill be using in quadratic equalities?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
it's one thing you will need in order to understand them. in general though, you should not be thrown by seeing f(x)=5x+7 that is just the same situation we had. they are saying that f(x) depends on what number you put in for x. you may see 'find when f(x)=10 for f(x)=5x+5' in which case you just use the equation, and put the value of f(x) on the other side of the = sign: 10=5x+5 5=5x x=1 we can do that for any value of f(x)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Shouldnt x be 2 there?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
the problem? no follow it closely
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh nevermind
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Can you give me one so i can try?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
sure, solve 5t+2r=3r4 for r
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I see what you are doing, you are trying to flutter up my train of thoughts by replacing x and y with t and r.. hah, itll never work.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good! better get used to it, all kinds of funny symbols in physics :P
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
flutter is how they translate the fword lol
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
5t+2r=3r4 5t=r4 Am i right so far?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes, now what?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Well i need you to tell me what t is. Ill just assume it is 1. 5t=9(r)4?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no you don't. we are going to get a function out of this because we have two variable and only one eqn. so how do you isolate r?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
perfect! so do you think you can tell me 'what is a function of what' in this case?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes, that's right! sorry btw, you made a mistake earlier: 5t=r4 ADD 4 to both sides: 5t+4=r but you got the fact that this is a function of t, very good. which variable is a function of t?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
It must be because 4 is an insteger, right?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
perfect :) (the integer thing makes no difference. If it was\[r=5t+\sqrt2\]that would be a function as well. we can write our function as r=f(t)=5t+4 or we can also write r(t)=5t+4 both mean that r is a function of t. Same exact thing. Now I'm going to use the notation r(t)=5t+4 and I am asking you, what is f(0)=? f(1)=? f(1)=?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
sorry, I meant r(t)=5t+4 what is r(0)=? r(1)=? r(1)=?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I thought we determined that r(0) cant be a variable?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
that was only when the 'independent variable' (that's what we call the t in this case) was in the denominator, because any number divided by zero is undefined (infinity basically) here we don't have that problem, so just plug in the numbers and see what you get.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
r is called the 'dependent variable' btw, because it 'depends' on what we put for t.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
so find r(0) r(1) and r(1) for r=5t+4
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
r(t)=5t+4 what is r(0)=1/4 r(1)=1/9 r(1)=5
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Thats probably really wrong..
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no, show your work... r(0)=5(0)+4=4 do the same for the others
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
OH! so (this) is what equals t?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
r(t)=5t+4 what is r(0)=5(0)+4=4 r(1)=5(1)+4 So it equals 9! r(1)=5(1)+4=1 ((5)+4=1)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
That should do it.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
excellent!
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
YEEEEEEEEES!!!!!!!!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
great, so now you have dealt with two functions today. do you know how to plot points on a graph?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
dw:1325547966414:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes! now do you know what r(0)=4 means as a point?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
As a point?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
yes, it is the point (0,4) we can call the updown direction on our graph r, and the horizontal direction t. this way we get a point out of every value of t we put in. the points (t,r) that we found are then r(0)=4>(0,4) r(1)=9>(1,9) r(1)=1>(1,1) ^^^don't continue until you understand all this, or at least have tried.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Ok, give me an example and ill try it. like r(2)=4>2,4?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
here is our graph marked from 0 to 4 in all directions:dw:1325548510639:dwcan you plot two of the points? If you want to try some more first that's even better: find the point (actually it's called an 'ordered pair') that corresponds to r(2) for r(t)=5t+4
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Actually, just do the question for now: find the ordered pair that corresponds to r(2) for r(t)=5t+4
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
r(2)=5(2)+4=6
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good, so what is the ordered pair (t,r) ?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
2 is right, but where did 5 come from? that's not the value of r(2)... and please put it in parentheses, that is how ordered pairs are written.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I see, (2,6)?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
perfect :D wanna try to graph it yet, or find more ordered pairs?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
One more ordered pair would be good.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
ok, find the ordered pairs that correspond to r(3) r(3) and r(5) for r=5x+4
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
sorry, you said one more you can only do one if you want.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Thats alright, ill do all of them. r(3)=5(3)+4=11 The corresponding pair is (3,11) r(3)=5(3)+4=19 The corresponding pair is (3,19) r(5)=5(5)+4=29 The corresponding pair is (5,29)
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
wow!!! you are a very fast learner Inopeki, you'll be doing calculus before you know it ;) so shall we try to graph it now?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
YES! Thanks, the teacher is just as important though! Sure.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
thanks for that :D so let's lay out some points that might fit on our graph: r(1)=1>(1,1) r(0)=4>(0,4) can you plot those points onto this graph?dw:1325549886229:dw(use 'reply with drawing')
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
dw:1325549850006:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
just put dots at their coordinates:dw:1325550068136:dwnow because this graph is linear, what will we connect those two points by?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
dw:1325550114671:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
good, but the line goes on to infinity in both directions:dw:1325550191308:dwthe arrows mean it keeps going. Good job though you have the idea. Here is a plot of our graph on two different scales: http://www.wolframalpha.com/input/?i=r%28t%29%3D5t%2B4 it doesn't look exactly like ours, but that is only because they made the increments of r larger because the graph is so steep. They wanted to fit more on there.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So now what?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
you can see on the graph I linked you to that the point (1,9) is on there, just as it should be. It also looks like the graph shows that the point (0.8,0) should be as well. Why don't you see if you can show that the point (0.8,0) is on our graph. Any idea how to do that?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
dw:1325550664006:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no, we want to do it mathematically, not graphically. Questions should only be answered graphically if they specifically request it. got a better way to show that (0.8,0) is a point?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
well that is the graphic solution, and it looks like you are right. But we want to PROVE that you are right. so how can we do that? think about this: if (0.8,0) is a point on the graph of r=5t+4 then what should r(0.8)=?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
r(0.8)=t(0.8)? r(0.8)=t(0)+0.8?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
oh wait, ill take that bacl
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
that's a point in the middle, not a comma, and it's negative: t=0.8 go again!
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Should i follow r=5t+4?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Ohhh.. r(0.8)=(0.8)+4=3.2?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
what happened to the 5? r=5t+4
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh right, i knew i forgot something. r(0.8)=5(0.8)+4=0!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
which makes sense right? the ordered pair corresponding to that is (0.8,0) which is what we wanted to prove, that this point is on the graph. Awesome job!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
I'm sure you've learned a lot today, please continue on your own working off khan academy. I do have to eat and stuff, so I'll catch you later. Again, super job! Keep practicing :D
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Alright :( Well thanks for all your help! It was really fun! Where do i start at khan now?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
did you finish ALL of that other lecture and problems? if you really finished it all, then you should do the nexttolast one that James gave you, then the first one he gave you. Most importantly, keep working on moving the symbols around. If you run out of exercises here are some to keep you busy. solve: 13+s/p=2 for p 5qr+6=qr/2 for q z/t+z=4t for z You shouldn't be able to do those so easily, as they involve factoring and such. If they give you too much trouble continue with the links James sent you. See you later tonight maybe, otherwise perhaps tomorrow. Good luck!
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
Here it is a little more clear. Again, if you can't do it it's okay. solve\[13+\frac{s}{p}=2\]for p\[5qr+6=\frac{qr}{2}\]for q\[\frac{z}{t}+z=4t\]for z
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
The 3 he gave me were linear equations 3, intro to the quadratic equation and simple equations, im soon finished with linear and then im gonna start with quadratic
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Wait, on the first one i need to do this: 13= s/p2 right?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
actually the first step on the first one is 1)multiply both sides by p the last one above will have a 'squared' term in it, so you may need the lectures first, I don't know. you're on the way to being a physicist, stepbystep again, good luck!
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
p(13)=2(13)+2=28? What is s? Ill say 2. \[28/13\approx2.15\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
5qr+6=qr2 4qr+6=qr I can now determine that q*r is negative because otherwise 4qr+6=qr The possibilities of what q and r are endless, what now?
 2 years ago
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