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Q: Solve
13+s/p=2 for p
A: p(13)=2(13)+2=28?
What is s? Ill say 2.
28/13≈2.15
 2 years ago
 2 years ago
Is this right? Q: Solve 13+s/p=2 for p A: p(13)=2(13)+2=28? What is s? Ill say 2. 28/13≈2.15
 2 years ago
 2 years ago

This Question is Closed

InopekiBest ResponseYou've already chosen the best response.1
Goddammit this is just hopeless..
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
hi Inopeki do not despair! practice practice...
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
what made you feel like putting a 13 there? we were supposed to get a function like before
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
you can't start plotting points like that until we've solved it for one of the variables. The answer to the question I was looking for should have 2 variables.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
13+s/p=2 what do you get multiplying both sides by p? do nothing else but that.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, I was wrong, nevermind
 2 years ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
13+s/p=2 for p 11+s/p=0 11=s/p p=s/11
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
See? This guy knows it. Why cant i?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Whatever. give me a new one
 2 years ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
You can with Time Inopeki
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
well, there's one way. btw Rhauckus I made up this problem for Inopeki to teach him how to solve for a variable @Inopeki, he has many years doing this, you need to practice basics. It will be like that for a while.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Well that sucks.. Still, if i really need to learn this i guess i will. Give me a new example so i can practise please
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
a new one? solve\[A=2\pi r h\] for A, r, and h I need to get you to stop thinking in numbers.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that's three problems, by the way.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
is \[\pi\] 3.14 here or is it a variable?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, it's about 3.14159..., that's why I didn't make it something to solve for. but don't think of it as a number, leave it as pi. The number does not matter.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Ok, so the answer should not be a number?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
it should be a function like r=5t+4 it has some numbers, but not all.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
One question. If i, in the answer have to give you As "definition", how can that not be a number?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
The formula I gave you is for the surface area of the side of a cylinder. The surface area of any particular cylinder depends on its radius and length. So the formula covers all possible cylinders, but only for some particular cylinders will you get a certain value for the surface area. It is a function, this time of both r and h.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
if I tell you the radius and height of our particular cylinder, only then can you get a number.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I just studied that in school! I thought we were talking algebra here..
 2 years ago

Akshay_BudhkarBest ResponseYou've already chosen the best response.0
@Turning you train guys well I will need your help for multivariable calculus, Laplace and stuff I will let you know then :D Great job is all I can say :D
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
Solving for a variable is algebra. They are all connected as you will learn. Thanks Akshay!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
But that still doesnt answer my question, how should i define A?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
in this case, A is already defined by\[A=2\pi rh\]that is basically the definition of the surface area of the side of a circular cylinder. No more definition is needed. I wanted you to catch that the first problem, solve for A, is already done for you: we already have A=(something) so it IS solved for A. So now solve it for r, if you can. what can we divide by to get r by itself?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
We can divide h with A, right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
when you say 'divide h with A' I'm not sure what you mean. Do you mean divide both sides by A or divide both sides by h ??? One is okay, one is not. You know that division is the inverse of multiplication. So ask yourself 'what is r being multiplied by?' and divide by that. Well, what is r being multiplied by?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
where did you see a squared term?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I have no idea.. i realize thats wrong now cause that is for getting the volume of a cylinder..
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
And that concludes that i am an utter and complete retard
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
it's okay. so again, what, in all, is r being multiplied by?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
c'mon, being hard on yourself never helped anything.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
right, it's being multiplied by 2(pi)h so that is what we need to divide by no don;t take it back!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
if you divide both sides by h, and both sides by pi you should isolate it so you have 2r, right?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Yeah.. pretty much what you said
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
But that doesnt mathematically give us anything..
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Then you just divide both sides by 2 and get r
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
sure it does, it gives us the answer not all answers in math are numbers, in fact I hate using numbers if I can help it. about your last post, yes, so what do we get for r=?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
what is on the other side of the equation when we solve for r?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
what did we divide both sides by?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
right. so what will A be divided by?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
well we get r on both sides right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, just one and all alone, that's what it means to solve for r again, yes to your last post so write out r=...?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
where did you get 1 ?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Nevermind, my mind is messing up my mind, if you know what i mean
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
If you are tired then take a break here is the answer, watch is closely: \[A=2\pi rh\]divide both sides by\[2\pi h\]giving\[r=\frac{A}{2\pi h}\]If you want to keep going then try just something simpler with NO numbers:\[ab=c\]solve for a
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Maybe i should catch some sleep, its 4:50 am here..
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that is a very good idea then. sleep on it and try it in the morning. I can't tell you how many problems I've solved just by sleeping on them. Don't worry, stepbystep. You will get there I know. Goodnight!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Good night, thank you for all the help!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
A=2πrh divide both sides by 2πh giving r=A2πh If you want to keep going then try just something simpler with NO numbers: ab=c solve for a When you say "solve for a", do you mean i should isolate it? I guess we would divide both sides by b and then c.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I would then get a/b=c/b Simplified, a=c/b
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
^^^correct! now get some sleep dude! the mind needs to be fresh.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I did sleep, that answer was today.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
lol I thought you stayed up all night. Told you sleeping on it would help. now solve ab=c for b
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Thats easy, both sides divided by a, you get b/a=c/a Simplify: b=c/a
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that's what I wanted to hear since it's so easy A=2πrh for r
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Divide both sides with 2(pi)h, you get A/2(pi)h=2(pi)rh/2(pi)h Simplified: A/2(pi)h=r
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
awesome! I know you got it but you should write it as A/(2π)h=r parentheses make it clear what is on the bottom.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
sorry, meant A/(2πh)=r
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
anyway, slightly different one: solve 5t=t/2+s for s, then for t
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
So the whole bottom part in parenthesis?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that's two problems^^^
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Multiply both sides by 2+s, right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
right, because everything in parentheses is on the bottom if you wrote 1/2x I don't know whether you mean\[\frac{1}{2x}\]or\[\frac{1}{2}x\]so parentheses are nice to clear things up think you can do the other? solve \[5t=\frac{t}{2}+s\] for s a good first step is to subtract t/2 from both sides. Then s will be isolated, right?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Oh, i thought you meant t/(2+s)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
I would have used parentheses if I meant that. if I had meant that then you would have been right, so you'll get one like that soon. but for now solve it as it is for s
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Right, so now i have 5tt/2=s, am i right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
totally, but can you simplify the left a little?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
so I mean what is 5tt/2 as a fraction?\[5t\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{9t}{2}\]do you know how to simplify fractions in this way?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
well did you know that you can only add or subtract the numerators when the denominators are the same?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Where did you get the 10?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
so we had to get the 5 to have a 2 in the denominator. How can we do this without changing our expression? the trick is to multiply the top and bottom by the same thing, in this case 2/2. Notice that 2/2=1 so it won't change our expression, because multiplying by 1 changes nothing.\[5t\frac{t}{2}=5t*\frac{2}{2}\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{9t}{2}\]make sure you understand the above. here's a couple pages on fractions http://www.mathsisfun.com/fractions_addition.html http://www.mathsisfun.com/numbers/fractionsmixedaddition.html
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Oh, i knew that, i still dont see where the 10 and 9 come from...
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Wait, i see now! 5t *2/2 should become 10/10 though...
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
No, wait, since the top is the only "t" part that is the only one being multiplied. THEN we take that minus t/2 and that simplifies it to 9t/2
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no it doesn't because the original denominator is 1\[5t\frac{t}{2}=\frac{5t}{1}*\frac{2}{2}\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{10tt}{2}=\frac{9t}{2}\]everything is secretly over 1, times 1, and to the power of 1. we just don't write\[a=\frac{1a^1}{1}\]because it is redundant, but they are the same. You figured it out as I was typing.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I have to isolate t by getting away the 5, right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yeah, solve it for t you can take it from\[\frac{9t}{2}=s\]there is nothing wrong with starting there if you want. It's up to you
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Divide both sides by 5?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
my first step if I start from 5t=t/2+s would be to multiply both sides by 2 to get rid of the fraction can you do that?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
what about s? didn't it get multiplied by 2 as well?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
so now you should be able to solve for t...
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Now divide both sides by 10?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Then we get t=t+2s/(10)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, because the t on the right would be divided by 10 as well let's see what happens if we do that: t=t/10+s/5 I don't think that helps... any other ideas?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
hint: combine like terms, we want the t's together 10t=t+2s
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
subtract t from both of them?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
@Inopeki yes! @arvind no I have to do 2 weeks of spanish homework in one day, I'm multitasking sorry.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
TT, shouldnt you do your homework first?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
I am doing it, this doesn't really distract me much, but arvind's problems can be kinda tricky, so that would distract me.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Oh, ok. Now he have 9t=2s
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
We have no other choice but to divide them by 9. Do we get t=4.5s then?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
how did it change to negative? and you need to leave it as a fraction for now. What did you do to both sides?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
you say you divided by 9 but \[2/9\neq 4.5\]
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Yeah, i have no idea what happened there..
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
so go again... 9t=2s
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
How do i divide 2 by 9?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
just like I wrote it: 2/9
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Oh nevermind.. so t=2/9s?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, good, but it is better to write t=2s/9 that way I don't think you put the s in the denominator now do the same starting from the equation when it was solved for s: s=9t/2 solve for t
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that would solve it for s, right? we wanted to solve for t...
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, which gives what as the answer??
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
which is what we got before, right? so mathematics is consistent, hooray! slightly different one: yz/(z+4)=7 solve for y
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
me too, good idea, breakfast!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Hah, i hade dinner.. You there?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yep, where were we? yz/(z+4)=7 solve for y
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
yz/(z+4)=7 I need to isolate y so maybe i should multiply both sides with z+4. then im left with yz=7z+4
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
good but you forgot to distribute the 7 yz=7(z+4) do you know what I mean by distribute?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, what do you get by distributing the 7? remember\[a(b+c+d)=ab+ac+ad\]you need to multiply each term in the parentheses by what is on the outside
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
so what should you have gotten after you multiplication? yz/(z+4)=7
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Oh well, yz/(z+4)=7>yz=7(z+4) >y=7(4)? Can i do that?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no you dropped the z take it from yz=7(z+4) and remember to distribute the 7 to all terms in the parentheses
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
good, now feel free to multiply the 7 and 4...
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
write thew whole expression every time
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
This must be like teaching physics to a mentally challenged monkey..
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Without all the throwing of feces
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
stupid server is very slow today :( yz=7z+28 what can we do next to solve for y ?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Yeah :/ subtract 1z from both sides, getting y=6z+28
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
you can't subtract z because it is being multiplied by y what is the inverse of multiplication again?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Division, right. Divide both zs by 2?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
will that isolate y ? why divide by 2 ?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I dont really know.. Maybe divide by z?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, see you do know!
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
yz=7z+28>y1=7z+28?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
almost, but you didn't divide the right by z... always gotta do BOTH sides
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
again, almost, but you need to divide each term by z you didn't divide 28 and look now there is no z in our expression! we can't be dropping variables like that. try again and make sure to divide every term yz=7z+28
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
what about the 7z now you forgot to divide that term by z... gotta do both
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
But you said i shouldnt drop that z? y=7+28/z?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
you didn't you still have z in the expression, so that is right. good job, but I'm gonna make you do it again for practice please show every step, and try to write it all out in one post. so from the top: yz/(z+4)=7 solve for y please show each step clearly.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
yz/(z+4)=7 yz=7(z+4) Here i took multiply both sides by (z+4). yz=7z+28 Here i simplify 7(z+4). y=7+28/z Here i divide both sides by z. y=35/z Here i simplify the right side.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
that's good but you can't simplify the right side like that at the end. you also don't need to tell me what each step is, just show. I can see what you are doing. yz/(z+4)=7 yz=7(z+4) yz=7z+28 y=7+28/z ^^^ this is sufficient as far as the simplifications you tried, I will show you a way to change the expression on the right that are valid:\[y=7+\frac{28}{z}=\frac{7z}{z}+\frac{28}{z}=\frac{7z+28}{z}\]this doesn't really make it more simple though, so there's not much point in it. remember we can only add when the denominators are the same, so here we had to multiply 7 by z/z first. still, good job! another: 4s(11/s)=5s+t solve for s (hint: first step is to distribute)
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Awesome! Ok i got this..
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
4s(11/s)=5s+t 4(11/)=5s+t if i take the s in 4s and put it into the same parenthesis that has 11/s the two s'es should "negate" eachother since one is divided by and one is multiplied by, it would be like saying this: 2*4/2. Am i right so far?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Im sorry for the delay, openstudy crashed for me
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, you lost an s we should practice distribution I think 4s(11/s)=4s4s(1/s)=4s4 one of the s's cancelled because it was multiplied by 1/s the other did not new exercise distribute: 5r(2+1/r+r)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
where did the r on the outside go? you didn't multiply anything in the parentheses at all :( watch very closely every step: 5r(2+1/r+r)=5r(2)+5r(1/r)+5r(r)=10r+5+5r^2 another distribute 2x(x1/x)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
not quite, you keep forgetting to multiply EVERY term. write out the middle step: 2x(x1/x)=2x(x)2x(1/x)=??? continue from there
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
no, sorry, I think you need to practice division.. 2x(x1/x)=2x(x)2x(1/x)=2x^22 what is a(1/a)=?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
a? I dont know.. This is just hopeless! Do i really need all this for physics?!
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
there you go anything multiplied by its reciprocal is 1 a(1/a)=1 x(1/x)=1 3(1/3)=1 what about something like a(2/a)=?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, good! here are a few for practice x(5/x)=? 3y(1/y)=? z(2/3z)=?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
inopeki a(2/a)=2 the a's cancel sorry I couldn't correct myself, but the lag... so now that you know that try x(5/x)=? 3y(1/y)=? z(2/3z)=? again, sorry for the confusion.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
5 1 2/3 I dont know.. Do i need to know much more before i cant start with trigo or calc?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
The first and last are right, but 3y(1/y)=3 and I hope you don't get discouraged, but you're gonna have to master basically all of algebra, which will take at least a year. the year after you will have to master trigonometry and precalculus. You will not be in calculus for some time, so get prepared to settle into algebra for a while...
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
That sucks... Are you sure that it will take a year?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
maybe not if you really delve into it, but if you want to do that you better get an algebra book and read it covertocover. That's what I did over the summer when I was 15. Like I said I knew very little before that and always considered myself bad a math.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
What book do you reccommend?
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Is all the algebra i need included in khanacademy?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
I actually just used the algebra book from my high school, I don't know what it was called. But any decent textbook on algebra should be fine. ask around. I think much algebra is in khan, but I doubt that by itself is enough. You need to practice a LOT of problems to get good. I'm not sure khan has enough.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Khans practice place has unlimited problems, i think. Or did you mean that the subjects there arent enough?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
If it has unlimited practice problems than do at least 75 from each section. I don't know khan I don't use it. I still recommend getting a book though. You need good reference material.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I will, we have one universal book for all the math subjects we are supposed to cover that year. Should i just google algebra?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
Maybe, but I think you should post the question on OS 'what is a good algebra book from basics to advanced algebra' I'm sure somebody has an opinion on that here.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Where were we, algebra wise?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
pretty basic honestly. solving linear equations, inverse operations, distribution, etc. we haven't even done factoring yet, let alone quadratics.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
So im pretty much still at square 1?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
for the most part, yes. don't get discouraged though, I remind you I refused to look at math until I was 15 there is plenty of time.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
But even this is so hard.. How do you expect me to get advanced level algebra when i barely understand linear equations..
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
You need to learn the basic rules a bit better, then you will see it makes more sense. You are trying to bite off more than you can chew at once. Learn all these rules like your very name: http://www.capitan.k12.nm.us/teachers/shearerk/basic_rules_of_algebra.htm that is the first step. it will take more than 1 day to commit all this to memory, so be patient and practice along the way with khan as you try.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Just the first part? (Algebra properties)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
No, everything on the page. Dividing fractions, adding unlike denominators, everything. All the basic rules are there, so one you know them the rest will be much much easier.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
I think i know all the first ones
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
I bet you have seen them before, but this time you really need to commit all the rules to memory, not just get the basic idea. Like I said, keep working practice problems in the meantime. When you get stuck, look at the list and try to apply a rule, that way they will have more meaning. Just memorizing the list out of context is pretty difficult and seemingly pointless.
 2 years ago

InopekiBest ResponseYou've already chosen the best response.1
Thanks again for all your help!
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.2
you're welcome I'll see you when this site starts working properly again. Keep it up, and good luck!
 2 years ago
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