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 3 years ago
Is this right?
Q: Solve
13+s/p=2 for p
A: p(13)=2(13)+2=28?
What is s? Ill say 2.
28/13≈2.15
 3 years ago
Is this right? Q: Solve 13+s/p=2 for p A: p(13)=2(13)+2=28? What is s? Ill say 2. 28/13≈2.15

This Question is Closed

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Goddammit this is just hopeless..

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2hi Inopeki do not despair! practice practice...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2what made you feel like putting a 13 there? we were supposed to get a function like before

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you can't start plotting points like that until we've solved it for one of the variables. The answer to the question I was looking for should have 2 variables.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.213+s/p=2 what do you get multiplying both sides by p? do nothing else but that.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, I was wrong, nevermind

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.013+s/p=2 for p 11+s/p=0 11=s/p p=s/11

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1See? This guy knows it. Why cant i?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Whatever. give me a new one

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0You can with Time Inopeki

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2well, there's one way. btw Rhauckus I made up this problem for Inopeki to teach him how to solve for a variable @Inopeki, he has many years doing this, you need to practice basics. It will be like that for a while.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Well that sucks.. Still, if i really need to learn this i guess i will. Give me a new example so i can practise please

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2a new one? solve\[A=2\pi r h\] for A, r, and h I need to get you to stop thinking in numbers.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that's three problems, by the way.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1is \[\pi\] 3.14 here or is it a variable?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, it's about 3.14159..., that's why I didn't make it something to solve for. but don't think of it as a number, leave it as pi. The number does not matter.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Ok, so the answer should not be a number?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2it should be a function like r=5t+4 it has some numbers, but not all.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1One question. If i, in the answer have to give you As "definition", how can that not be a number?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2The formula I gave you is for the surface area of the side of a cylinder. The surface area of any particular cylinder depends on its radius and length. So the formula covers all possible cylinders, but only for some particular cylinders will you get a certain value for the surface area. It is a function, this time of both r and h.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2if I tell you the radius and height of our particular cylinder, only then can you get a number.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I just studied that in school! I thought we were talking algebra here..

Akshay_Budhkar
 3 years ago
Best ResponseYou've already chosen the best response.0@Turning you train guys well I will need your help for multivariable calculus, Laplace and stuff I will let you know then :D Great job is all I can say :D

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2Solving for a variable is algebra. They are all connected as you will learn. Thanks Akshay!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1But that still doesnt answer my question, how should i define A?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2in this case, A is already defined by\[A=2\pi rh\]that is basically the definition of the surface area of the side of a circular cylinder. No more definition is needed. I wanted you to catch that the first problem, solve for A, is already done for you: we already have A=(something) so it IS solved for A. So now solve it for r, if you can. what can we divide by to get r by itself?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1We can divide h with A, right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2when you say 'divide h with A' I'm not sure what you mean. Do you mean divide both sides by A or divide both sides by h ??? One is okay, one is not. You know that division is the inverse of multiplication. So ask yourself 'what is r being multiplied by?' and divide by that. Well, what is r being multiplied by?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2where did you see a squared term?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I have no idea.. i realize thats wrong now cause that is for getting the volume of a cylinder..

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1And that concludes that i am an utter and complete retard

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2it's okay. so again, what, in all, is r being multiplied by?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2c'mon, being hard on yourself never helped anything.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2right, it's being multiplied by 2(pi)h so that is what we need to divide by no don;t take it back!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1if you divide both sides by h, and both sides by pi you should isolate it so you have 2r, right?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah.. pretty much what you said

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1But that doesnt mathematically give us anything..

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Then you just divide both sides by 2 and get r

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2sure it does, it gives us the answer not all answers in math are numbers, in fact I hate using numbers if I can help it. about your last post, yes, so what do we get for r=?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2what is on the other side of the equation when we solve for r?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2what did we divide both sides by?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2right. so what will A be divided by?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1well we get r on both sides right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, just one and all alone, that's what it means to solve for r again, yes to your last post so write out r=...?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2where did you get 1 ?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Nevermind, my mind is messing up my mind, if you know what i mean

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2If you are tired then take a break here is the answer, watch is closely: \[A=2\pi rh\]divide both sides by\[2\pi h\]giving\[r=\frac{A}{2\pi h}\]If you want to keep going then try just something simpler with NO numbers:\[ab=c\]solve for a

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Maybe i should catch some sleep, its 4:50 am here..

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that is a very good idea then. sleep on it and try it in the morning. I can't tell you how many problems I've solved just by sleeping on them. Don't worry, stepbystep. You will get there I know. Goodnight!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Good night, thank you for all the help!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1A=2πrh divide both sides by 2πh giving r=A2πh If you want to keep going then try just something simpler with NO numbers: ab=c solve for a When you say "solve for a", do you mean i should isolate it? I guess we would divide both sides by b and then c.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I would then get a/b=c/b Simplified, a=c/b

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2^^^correct! now get some sleep dude! the mind needs to be fresh.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I did sleep, that answer was today.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2lol I thought you stayed up all night. Told you sleeping on it would help. now solve ab=c for b

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Thats easy, both sides divided by a, you get b/a=c/a Simplify: b=c/a

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that's what I wanted to hear since it's so easy A=2πrh for r

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Divide both sides with 2(pi)h, you get A/2(pi)h=2(pi)rh/2(pi)h Simplified: A/2(pi)h=r

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2awesome! I know you got it but you should write it as A/(2π)h=r parentheses make it clear what is on the bottom.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2sorry, meant A/(2πh)=r

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2anyway, slightly different one: solve 5t=t/2+s for s, then for t

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1So the whole bottom part in parenthesis?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that's two problems^^^

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Multiply both sides by 2+s, right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2right, because everything in parentheses is on the bottom if you wrote 1/2x I don't know whether you mean\[\frac{1}{2x}\]or\[\frac{1}{2}x\]so parentheses are nice to clear things up think you can do the other? solve \[5t=\frac{t}{2}+s\] for s a good first step is to subtract t/2 from both sides. Then s will be isolated, right?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Oh, i thought you meant t/(2+s)

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2I would have used parentheses if I meant that. if I had meant that then you would have been right, so you'll get one like that soon. but for now solve it as it is for s

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Right, so now i have 5tt/2=s, am i right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2totally, but can you simplify the left a little?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so I mean what is 5tt/2 as a fraction?\[5t\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{9t}{2}\]do you know how to simplify fractions in this way?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2well did you know that you can only add or subtract the numerators when the denominators are the same?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Where did you get the 10?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so we had to get the 5 to have a 2 in the denominator. How can we do this without changing our expression? the trick is to multiply the top and bottom by the same thing, in this case 2/2. Notice that 2/2=1 so it won't change our expression, because multiplying by 1 changes nothing.\[5t\frac{t}{2}=5t*\frac{2}{2}\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{9t}{2}\]make sure you understand the above. here's a couple pages on fractions http://www.mathsisfun.com/fractions_addition.html http://www.mathsisfun.com/numbers/fractionsmixedaddition.html

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Oh, i knew that, i still dont see where the 10 and 9 come from...

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Wait, i see now! 5t *2/2 should become 10/10 though...

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1No, wait, since the top is the only "t" part that is the only one being multiplied. THEN we take that minus t/2 and that simplifies it to 9t/2

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no it doesn't because the original denominator is 1\[5t\frac{t}{2}=\frac{5t}{1}*\frac{2}{2}\frac{t}{2}=\frac{10t}{2}\frac{t}{2}=\frac{10tt}{2}=\frac{9t}{2}\]everything is secretly over 1, times 1, and to the power of 1. we just don't write\[a=\frac{1a^1}{1}\]because it is redundant, but they are the same. You figured it out as I was typing.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I have to isolate t by getting away the 5, right?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, solve it for t you can take it from\[\frac{9t}{2}=s\]there is nothing wrong with starting there if you want. It's up to you

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Divide both sides by 5?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2my first step if I start from 5t=t/2+s would be to multiply both sides by 2 to get rid of the fraction can you do that?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2what about s? didn't it get multiplied by 2 as well?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so now you should be able to solve for t...

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Now divide both sides by 10?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Then we get t=t+2s/(10)

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, because the t on the right would be divided by 10 as well let's see what happens if we do that: t=t/10+s/5 I don't think that helps... any other ideas?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2hint: combine like terms, we want the t's together 10t=t+2s

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1subtract t from both of them?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2@Inopeki yes! @arvind no I have to do 2 weeks of spanish homework in one day, I'm multitasking sorry.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1TT, shouldnt you do your homework first?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2I am doing it, this doesn't really distract me much, but arvind's problems can be kinda tricky, so that would distract me.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Oh, ok. Now he have 9t=2s

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1We have no other choice but to divide them by 9. Do we get t=4.5s then?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2how did it change to negative? and you need to leave it as a fraction for now. What did you do to both sides?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you say you divided by 9 but \[2/9\neq 4.5\]

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah, i have no idea what happened there..

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so go again... 9t=2s

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1How do i divide 2 by 9?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2just like I wrote it: 2/9

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Oh nevermind.. so t=2/9s?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yes, good, but it is better to write t=2s/9 that way I don't think you put the s in the denominator now do the same starting from the equation when it was solved for s: s=9t/2 solve for t

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that would solve it for s, right? we wanted to solve for t...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yes, which gives what as the answer??

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2which is what we got before, right? so mathematics is consistent, hooray! slightly different one: yz/(z+4)=7 solve for y

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2me too, good idea, breakfast!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Hah, i hade dinner.. You there?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yep, where were we? yz/(z+4)=7 solve for y

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1yz/(z+4)=7 I need to isolate y so maybe i should multiply both sides with z+4. then im left with yz=7z+4

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2good but you forgot to distribute the 7 yz=7(z+4) do you know what I mean by distribute?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yes, what do you get by distributing the 7? remember\[a(b+c+d)=ab+ac+ad\]you need to multiply each term in the parentheses by what is on the outside

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so what should you have gotten after you multiplication? yz/(z+4)=7

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Oh well, yz/(z+4)=7>yz=7(z+4) >y=7(4)? Can i do that?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no you dropped the z take it from yz=7(z+4) and remember to distribute the 7 to all terms in the parentheses

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2good, now feel free to multiply the 7 and 4...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2write thew whole expression every time

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1This must be like teaching physics to a mentally challenged monkey..

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Without all the throwing of feces

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2stupid server is very slow today :( yz=7z+28 what can we do next to solve for y ?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah :/ subtract 1z from both sides, getting y=6z+28

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you can't subtract z because it is being multiplied by y what is the inverse of multiplication again?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Division, right. Divide both zs by 2?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2will that isolate y ? why divide by 2 ?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I dont really know.. Maybe divide by z?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yes, see you do know!

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1yz=7z+28>y1=7z+28?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2almost, but you didn't divide the right by z... always gotta do BOTH sides

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2again, almost, but you need to divide each term by z you didn't divide 28 and look now there is no z in our expression! we can't be dropping variables like that. try again and make sure to divide every term yz=7z+28

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2what about the 7z now you forgot to divide that term by z... gotta do both

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1But you said i shouldnt drop that z? y=7+28/z?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you didn't you still have z in the expression, so that is right. good job, but I'm gonna make you do it again for practice please show every step, and try to write it all out in one post. so from the top: yz/(z+4)=7 solve for y please show each step clearly.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1yz/(z+4)=7 yz=7(z+4) Here i took multiply both sides by (z+4). yz=7z+28 Here i simplify 7(z+4). y=7+28/z Here i divide both sides by z. y=35/z Here i simplify the right side.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that's good but you can't simplify the right side like that at the end. you also don't need to tell me what each step is, just show. I can see what you are doing. yz/(z+4)=7 yz=7(z+4) yz=7z+28 y=7+28/z ^^^ this is sufficient as far as the simplifications you tried, I will show you a way to change the expression on the right that are valid:\[y=7+\frac{28}{z}=\frac{7z}{z}+\frac{28}{z}=\frac{7z+28}{z}\]this doesn't really make it more simple though, so there's not much point in it. remember we can only add when the denominators are the same, so here we had to multiply 7 by z/z first. still, good job! another: 4s(11/s)=5s+t solve for s (hint: first step is to distribute)

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Awesome! Ok i got this..

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.14s(11/s)=5s+t 4(11/)=5s+t if i take the s in 4s and put it into the same parenthesis that has 11/s the two s'es should "negate" eachother since one is divided by and one is multiplied by, it would be like saying this: 2*4/2. Am i right so far?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Im sorry for the delay, openstudy crashed for me

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, you lost an s we should practice distribution I think 4s(11/s)=4s4s(1/s)=4s4 one of the s's cancelled because it was multiplied by 1/s the other did not new exercise distribute: 5r(2+1/r+r)

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2where did the r on the outside go? you didn't multiply anything in the parentheses at all :( watch very closely every step: 5r(2+1/r+r)=5r(2)+5r(1/r)+5r(r)=10r+5+5r^2 another distribute 2x(x1/x)

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2not quite, you keep forgetting to multiply EVERY term. write out the middle step: 2x(x1/x)=2x(x)2x(1/x)=??? continue from there

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2no, sorry, I think you need to practice division.. 2x(x1/x)=2x(x)2x(1/x)=2x^22 what is a(1/a)=?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1a? I dont know.. This is just hopeless! Do i really need all this for physics?!

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2there you go anything multiplied by its reciprocal is 1 a(1/a)=1 x(1/x)=1 3(1/3)=1 what about something like a(2/a)=?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2yes, good! here are a few for practice x(5/x)=? 3y(1/y)=? z(2/3z)=?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2inopeki a(2/a)=2 the a's cancel sorry I couldn't correct myself, but the lag... so now that you know that try x(5/x)=? 3y(1/y)=? z(2/3z)=? again, sorry for the confusion.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.15 1 2/3 I dont know.. Do i need to know much more before i cant start with trigo or calc?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2The first and last are right, but 3y(1/y)=3 and I hope you don't get discouraged, but you're gonna have to master basically all of algebra, which will take at least a year. the year after you will have to master trigonometry and precalculus. You will not be in calculus for some time, so get prepared to settle into algebra for a while...

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1That sucks... Are you sure that it will take a year?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2maybe not if you really delve into it, but if you want to do that you better get an algebra book and read it covertocover. That's what I did over the summer when I was 15. Like I said I knew very little before that and always considered myself bad a math.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1What book do you reccommend?

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Is all the algebra i need included in khanacademy?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2I actually just used the algebra book from my high school, I don't know what it was called. But any decent textbook on algebra should be fine. ask around. I think much algebra is in khan, but I doubt that by itself is enough. You need to practice a LOT of problems to get good. I'm not sure khan has enough.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Khans practice place has unlimited problems, i think. Or did you mean that the subjects there arent enough?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2If it has unlimited practice problems than do at least 75 from each section. I don't know khan I don't use it. I still recommend getting a book though. You need good reference material.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I will, we have one universal book for all the math subjects we are supposed to cover that year. Should i just google algebra?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2Maybe, but I think you should post the question on OS 'what is a good algebra book from basics to advanced algebra' I'm sure somebody has an opinion on that here.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Where were we, algebra wise?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2pretty basic honestly. solving linear equations, inverse operations, distribution, etc. we haven't even done factoring yet, let alone quadratics.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1So im pretty much still at square 1?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2for the most part, yes. don't get discouraged though, I remind you I refused to look at math until I was 15 there is plenty of time.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1But even this is so hard.. How do you expect me to get advanced level algebra when i barely understand linear equations..

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2You need to learn the basic rules a bit better, then you will see it makes more sense. You are trying to bite off more than you can chew at once. Learn all these rules like your very name: http://www.capitan.k12.nm.us/teachers/shearerk/basic_rules_of_algebra.htm that is the first step. it will take more than 1 day to commit all this to memory, so be patient and practice along the way with khan as you try.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Just the first part? (Algebra properties)

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2No, everything on the page. Dividing fractions, adding unlike denominators, everything. All the basic rules are there, so one you know them the rest will be much much easier.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1I think i know all the first ones

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2I bet you have seen them before, but this time you really need to commit all the rules to memory, not just get the basic idea. Like I said, keep working practice problems in the meantime. When you get stuck, look at the list and try to apply a rule, that way they will have more meaning. Just memorizing the list out of context is pretty difficult and seemingly pointless.

Inopeki
 3 years ago
Best ResponseYou've already chosen the best response.1Thanks again for all your help!

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you're welcome I'll see you when this site starts working properly again. Keep it up, and good luck!
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