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Zed
 2 years ago
Best ResponseYou've already chosen the best response.1yes, so when you do that what will you get?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ab}{b}=\frac{c}{b}\] \[a=\frac{c}{b}\]

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Oh! now i get it, can you set up another example so i can try?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Ok, divide ax with a, then divide c with a getting ax/a+y=c/a. You then simplify that getting x+y=c/a. Then you take both sides minus y getting x=c/ay

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1Really close but we need to either get rid of the y first before divide or also divide the y by a

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3YES! Thanks for teaching me :)

abdul_shabeer
 2 years ago
Best ResponseYou've already chosen the best response.0No, first start by subtracting y from both sides

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Alright, so ax+y=c ax=cy x/a=c/ay x=c/ay

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1remeber that when you divide the a you need to do it to all the terms

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2Inopeki got the answer i just put it in the equation maker for ease of the viewers

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1inopeki you need to write x=(cy)/a just to make it clearer. i see it now good work

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Thanks for the help :) Is there any way you can make it a little harder to give me a challenge?

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2yea i will come up with one for you

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2\[\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\] Solve for T_2

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Nobody mentioned division by zero ?!!

abdul_shabeer
 2 years ago
Best ResponseYou've already chosen the best response.0Good observation @ Foolformath

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Well to begin with i need to multiply both sides with P2V2, getting P1V1/T1*P2V2, right?\[P _{1}V _{1}divT _{1}+P _{2}V _{2}=T2\]

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2I'll lay it out by steps for you

abdul_shabeer
 2 years ago
Best ResponseYou've already chosen the best response.0Cross multiplication

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2lcd = T_1T_2 \[T_2P_1V_1=V_2P_2T_1\] \[T_2=\frac{V_2P_2T_1}{P_1V_1}\]

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Oh right, i see it now. You wanted me to put the things i was multiplying by(V2P2) in by the other things that were multiplied. That would mean my answer is right, but yours is simplified.

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2No because you need to multiply both sides by the lcd of \[T_1T_2\] first then we cancel one of the varibles out because they are the same on top and bottom. then we can break T_2 apart from the rest of the left side by division, your answer would look close but in the end it would be wrong

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3What is an lcd? What makes T1 jump up?

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2lcd= lowest common denominator

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Is a denominator the 1 in T1?

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2The denominator is what is on the bottom of the fraction, so when we do the left side we get \[\frac{T_1T_2P_11V_1}{T_1}\] and because we have the same thing on the top and bottom we can cancel out the denominator leving us with \[T_2P_1V_1\] and we do the same operation on the right side

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Why do we get T1 on both sides of the line?

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2because you are multiplying by t1t2 but on each side one of them will cancell

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2Good job that was a hard one

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Thanks, when am i going to get to learn this in school?

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2Not sure when you will cover that but it's a chemistry equation compariing similar gasses to determine preasure, temp, or volume. You might touch it in highschool sometime.

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Oh, cool. What should i do now?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1And then try this \[V=\frac{4}{3}\pi r^3\] Solve for r

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Divide both sides by rt, getting PV/rt=n, am i right? By the way, why is PV upper case?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Zed, isnt that for volúmes of spheres or something? exept r should be ^3

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2good question and i don't have an answer for you but in that equation they are all upercase but the little n but i made a mistake and didn't capitilize the RT

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Zed, im going to do yours now.

zbay
 2 years ago
Best ResponseYou've already chosen the best response.2yes you were right and that was the ideal gas law by the way

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Oh, that was a ^3! Divide both sides with (pi)r^2 getting V/(pi)r=4/3r, am i right sofar?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3What does the law state?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1okay so first step is to get r^3 by itself. what do you get?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Wait. I take back my first answer. First you divide both sides by 4/3(pi) to isolate r^3

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1good. have you done powers before and their inverses?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3I think so, what do you mean?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1okay so we have \[r^3=\frac{3V}{4}\] how do I get rid of the cubed part?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Oh, i have done powers but i dont recall doing inverses, is that like squareroot and cubicroot? I guess we need to get the "cubicalroot" out of r^3.

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3We should be able to just divide r by r 2 times.

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.33* and by itself i mean the root.

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1not quite see let's try this example to help explain it \[x^2=4\]\[x=\sqrt{4}\]\[x=4^{\frac{1}{2}}\]\[x=2\]

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3What? Can you explain that?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1okay so when we bring powers (eg 3) over the equation sign they turn to 1/powers (eg 1/3). if we look at squared when we bring it over it turns to 1/2 which is also known as the square root.

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3Why does it become 1/2?

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1the may be abit hard to follow but this is why. Let f(x)=y \[y=x^7\] \[\ln y=7 \ln x\] \[lnx=(lny)/7\] \[x=e^{(lny)/7}\] \[Inverse = f^{1}(x)=e^{(lnx)/7}\] \[ f^{1}(x)=e^{lnx^\frac{1}{7}}\]\[=x^\frac{1}{7}\]

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1Now usually when learning this we just accept this as fact that \[x^n=x^{\frac{1}{n}}\] where n is a positive integer

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1That was probably way too much information at once just use the rule in the above post and try to solve \[r^3=\frac{3V}{4}\]

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3So if r^2 becomes 1/2, then r^3 should become 1/3, right?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3That means that i have to maake r^3 to 1/3 and convert 1/3 to 4/12(to merge it with the right side). i then convert the right sides fractions too, getting 9V/12. Now i should be able to merge them, right? so i get r=13/12?

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3I screwed that up right...

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1Sorry we want to raise both sides by the power of (1/3)

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1so the left hand side will be \[(r^3)^{\frac{1}{3}}=r^{\frac{3}{3}}=r^1=r\]

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1okay the right side is good. we have \[(\frac{3V}{4})^\frac{1}{3}\]

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1remember on the left hand side we had r^3 and when raised it to the power of 1/3 the powers need to be multiplied.

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1yes exactly it's one of the rules for powers. here are others if you wanted to learn and practice http://www.math.com/school/subject2/lessons/S2U2L2DP.html

Inopeki
 2 years ago
Best ResponseYou've already chosen the best response.3So the answer is r^3*1/3=3V^3/4

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1yes and that simplifies to r=(3V/4)^1/3

Zed
 2 years ago
Best ResponseYou've already chosen the best response.1Well I'm off to sleep. I'll be on tomorrow if you want more examples or help :)
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