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Inopeki Group TitleBest ResponseYou've already chosen the best response.3
And that is all?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
yes, so when you do that what will you get?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ab}{b}=\frac{c}{b}\] \[a=\frac{c}{b}\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh! now i get it, can you set up another example so i can try?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
Sure ax+y=c, solve for x
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Ok, divide ax with a, then divide c with a getting ax/a+y=c/a. You then simplify that getting x+y=c/a. Then you take both sides minus y getting x=c/ay
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Is this correct?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
Really close but we need to either get rid of the y first before divide or also divide the y by a
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
YES! Thanks for teaching me :)
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
No, first start by subtracting y from both sides
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Alright, so ax+y=c ax=cy x/a=c/ay x=c/ay
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
remeber that when you divide the a you need to do it to all the terms
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Where did you get z?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh right.. so x=cy/a
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
\[x=\frac{cy}{a}\]
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
zbay is correct
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
Inopeki got the answer i just put it in the equation maker for ease of the viewers
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
inopeki you need to write x=(cy)/a just to make it clearer. i see it now good work
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Thanks for the help :) Is there any way you can make it a little harder to give me a challenge?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
yea i will come up with one for you
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\] Solve for T_2
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
umm.. ill try
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.0
Nobody mentioned division by zero ?!!
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
Good observation @ Foolformath
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Well to begin with i need to multiply both sides with P2V2, getting P1V1/T1*P2V2, right?\[P _{1}V _{1}divT _{1}+P _{2}V _{2}=T2\]
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
I'll lay it out by steps for you
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
NOO. wait. Its
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
Cross multiplication
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
P1V1/T1*P2V2=T2
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
lcd = T_1T_2 \[T_2P_1V_1=V_2P_2T_1\] \[T_2=\frac{V_2P_2T_1}{P_1V_1}\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh right, i see it now. You wanted me to put the things i was multiplying by(V2P2) in by the other things that were multiplied. That would mean my answer is right, but yours is simplified.
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
No because you need to multiply both sides by the lcd of \[T_1T_2\] first then we cancel one of the varibles out because they are the same on top and bottom. then we can break T_2 apart from the rest of the left side by division, your answer would look close but in the end it would be wrong
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
What is an lcd? What makes T1 jump up?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
lcd= lowest common denominator
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
What is that?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Is a denominator the 1 in T1?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
The denominator is what is on the bottom of the fraction, so when we do the left side we get \[\frac{T_1T_2P_11V_1}{T_1}\] and because we have the same thing on the top and bottom we can cancel out the denominator leving us with \[T_2P_1V_1\] and we do the same operation on the right side
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Why do we get T1 on both sides of the line?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
because you are multiplying by t1t2 but on each side one of them will cancell
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
Good job that was a hard one
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Thanks, when am i going to get to learn this in school?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
what grade are you?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
Not sure when you will cover that but it's a chemistry equation compariing similar gasses to determine preasure, temp, or volume. You might touch it in highschool sometime.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh, cool. What should i do now?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
PV=nrt solve for n
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
And then try this \[V=\frac{4}{3}\pi r^3\] Solve for r
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Divide both sides by rt, getting PV/rt=n, am i right? By the way, why is PV upper case?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Zed, isnt that for volúmes of spheres or something? exept r should be ^3
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
good question and i don't have an answer for you but in that equation they are all upercase but the little n but i made a mistake and didn't capitilize the RT
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
But was i right?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Zed, im going to do yours now.
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
yes you were right and that was the ideal gas law by the way
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh, that was a ^3! Divide both sides with (pi)r^2 getting V/(pi)r=4/3r, am i right sofar?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
What does the law state?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
okay so first step is to get r^3 by itself. what do you get?
 2 years ago

zbay Group TitleBest ResponseYou've already chosen the best response.2
http://en.wikipedia.org/wiki/Ideal_gas_law
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Wait. I take back my first answer. First you divide both sides by 4/3(pi) to isolate r^3
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
good. have you done powers before and their inverses?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I think so, what do you mean?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
okay so we have \[r^3=\frac{3V}{4}\] how do I get rid of the cubed part?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh, i have done powers but i dont recall doing inverses, is that like squareroot and cubicroot? I guess we need to get the "cubicalroot" out of r^3.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
We should be able to just divide r by r 2 times.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
3* and by itself i mean the root.
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
not quite see let's try this example to help explain it \[x^2=4\]\[x=\sqrt{4}\]\[x=4^{\frac{1}{2}}\]\[x=2\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
What? Can you explain that?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
okay so when we bring powers (eg 3) over the equation sign they turn to 1/powers (eg 1/3). if we look at squared when we bring it over it turns to 1/2 which is also known as the square root.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Why does it become 1/2?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
the may be abit hard to follow but this is why. Let f(x)=y \[y=x^7\] \[\ln y=7 \ln x\] \[lnx=(lny)/7\] \[x=e^{(lny)/7}\] \[Inverse = f^{1}(x)=e^{(lnx)/7}\] \[ f^{1}(x)=e^{lnx^\frac{1}{7}}\]\[=x^\frac{1}{7}\]
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
Now usually when learning this we just accept this as fact that \[x^n=x^{\frac{1}{n}}\] where n is a positive integer
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
That was probably way too much information at once just use the rule in the above post and try to solve \[r^3=\frac{3V}{4}\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So if r^2 becomes 1/2, then r^3 should become 1/3, right?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
That means that i have to maake r^3 to 1/3 and convert 1/3 to 4/12(to merge it with the right side). i then convert the right sides fractions too, getting 9V/12. Now i should be able to merge them, right? so i get r=13/12?
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I screwed that up right...
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
Sorry we want to raise both sides by the power of (1/3)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
r^1/3=3V^1/3/4?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
so the left hand side will be \[(r^3)^{\frac{1}{3}}=r^{\frac{3}{3}}=r^1=r\]
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
I dont understand.
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
okay the right side is good. we have \[(\frac{3V}{4})^\frac{1}{3}\]
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
remember on the left hand side we had r^3 and when raised it to the power of 1/3 the powers need to be multiplied.
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Oh! So its r^3*1/3?
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
yes exactly it's one of the rules for powers. here are others if you wanted to learn and practice http://www.math.com/school/subject2/lessons/S2U2L2DP.html
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
So the answer is r^3*1/3=3V^3/4
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
yes and that simplifies to r=(3V/4)^1/3
 2 years ago

Zed Group TitleBest ResponseYou've already chosen the best response.1
Well I'm off to sleep. I'll be on tomorrow if you want more examples or help :)
 2 years ago

Inopeki Group TitleBest ResponseYou've already chosen the best response.3
Thanks for everything!
 2 years ago
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