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\[\frac{ \frac{1}{sin {\theta}}}{tan{\theta}}+\frac{1}{tan{\theta}}=cos{\theta}\]

I am sorry, how did that happen?

Sorry I will write it up first and post it with steps. Just a moment

Sweet, thanks!

does it mean that (1/sin x)^2+(1/sin x)=1?

if you divide the cos theta from both sides

Yes correct

I still would appreciate to see the steps plz :s

but why? let x=pi/6 then 4+2=1??

yes I'm having that issue too. Are you sure it's written down right?

\[\csc \theta \over \tan \theta +\cot \theta\]
=
[\cos \theta\]

I see now, next time put the tan theta + cot theta in brackets to make it clearer.

multiply the LHS by sinx cosx

gotcha. sorry about that.

im sorry it should be theta...

why did you multiply each sides by sinx cosx? how could u tell?

Here's a different way to go about it :)

because there are sinx cosx in the denominator

zed; yur way is something to think about, and it's cool.
yet i won't b able to use your method

yifian; i don't really get how you got there.. :(

i can't figure it out

which step?

is there other way to do it?

sorry that second last line was supposed to be cosx

yeah that is a good prove except that you substitute theta for x..

yeah i got tired of writing theta out

thanks Yifan

1 over cos x isn't same as cos x

It was a typo

i got that too.

well thanks for your time :)