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shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.1This is a redox reaction... Write half reactions and balance them and add., Mn(7+)O4 +5e + 8H+ > Mn(2+) +4H2O .....*6 As(3+)2O3 +5H2O > 2As(6+)O4 +10H+ + 6e ...*5 Now add them to write the final equation... (I dont know how to use subscripts Sorry abt that).

ChemistKama
 3 years ago
Best ResponseYou've already chosen the best response.0You can also use the oxidationstate method it will be easier: 6KMnO4 +5 As2O3 +18 HCl + H2O > 6MnCl2 +10 H2AsO4 + 6KCl Mn(+7)+5eMn(+2) 6 As(+3)(3*2e)As(+6) 5

shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.1What i have done os the same thing you can't write Mn as 7+ directly as it is not an ion hence it should be written as MnO4

ChemistKama
 3 years ago
Best ResponseYou've already chosen the best response.0Why? u used method of half reactions but me the oxidationstate method ) i think both are correct

shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.1You can NOT write Mn as only Mn7+ in Mn04 in any method it is NOT an ion.

ChemistKama
 3 years ago
Best ResponseYou've already chosen the best response.0I know that it's not an ion.I balanced the atoms!!! At the result I obtained the correct answer) It's the main.
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