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Add. (4c2 – 5c + 11) + (3c2 + c – 9)

  • 2 years ago
  • 2 years ago

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  1. angela210793
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    (4c2 – 5c + 11) + (3c2 + c – 9)=7c^2-4c+2

    • 2 years ago
  2. ariba96
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    look, i'm explaining it to u. lets open the brackets first. that would be 4c^2 - 5 +11 (same as it is) (1)*(3c^2)+(1)*(c)+(1)(-9) } Btw im multiplying with +1 because i want to make sure i dont get the signs jumbled up... this is imp when the signs are ngitive okay, so now we get: 4c^2-5c+11+3c^2 + c-9 4c^2+3c^2 -5c + c +11 -9 now u get : 7c^2 -4c +2 :) i hope u understand, u can always ask me anything :D ill be glad to help

    • 2 years ago
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