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tux Group Title

Decide convergence / divergence: sum n=1 to infinity 1/(n*sqrt(n)+2)

  • 2 years ago
  • 2 years ago

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  1. satellite73 Group Title
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    converges for sure

    • 2 years ago
  2. satellite73 Group Title
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    since exponent in denominator is greater than 1

    • 2 years ago
  3. tux Group Title
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    How to solve using comparison test or integral test?

    • 2 years ago
  4. amistre64 Group Title
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    integral test is just integrate from 1 to infinity

    • 2 years ago
  5. amistre64 Group Title
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    comparison is a limit of the ratio of .... \[\frac{a_{n+1}}{a_n}\]

    • 2 years ago
  6. satellite73 Group Title
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    actually that is "ratio test" comparison means compare to something else you know converges (or diverges)

    • 2 years ago
  7. amistre64 Group Title
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    of is the comparison a b_n of another ..... yeah lol

    • 2 years ago
  8. satellite73 Group Title
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    \[\sum_1^{\infty}\frac{1}{n\sqrt{n}+2}\]compare \[\frac{1}{n\sqrt{n}+2}<\frac{1}{n^{\frac{3}{2}}}\] second sum converges

    • 2 years ago
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