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Hannah_Ahn
Prove the identity \[\left( \sin2x \over 1+\cos2x \right) = \left( \sec ^{2}x-1 \over \tan x \right)\]
use sin2x=2sinxcosx cos2x=2cos^2 x -1 sec^2 x -1 =tan^2 x then LHS=tanx=RHS
how did you get tan^2x
I got Left side : sinx over cosx-1 Right side : (1over cosx-1) over sinx ...?
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