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anonymous
 4 years ago
prove the identity:
\[\left( \cot x  1 \over 1  \tan x\right) = \left( \csc x \over \sec x \right)\]
anonymous
 4 years ago
prove the identity: \[\left( \cot x  1 \over 1  \tan x\right) = \left( \csc x \over \sec x \right)\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0left hand side is \[\frac{\frac{1}{b}}{\frac{1}{a}}=\frac{a}{b}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry that was right hand side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0left hand side is \[\frac{\frac{a}{b}1}{1\frac{b}{a}}=\frac{a^2ab}{abb^2}=\frac{a(ab)}{b(ab)}=\frac{a}{b}\] so there are the same. there is no trig here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is an awesome way to prove it! you are amazing! thanks!!!
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