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Hannah_Ahn
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prove the identity: [\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]
 2 years ago
 2 years ago
Hannah_Ahn Group Title
prove the identity: [\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]
 2 years ago
 2 years ago

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Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
\[\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
dw:1325730453048:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
i got it until (cos^2 over sinx)  (sinx) after your second step i multiplied deno and numerator by sinx. but how did you get cos^2sin^2x over sinx and how is it same as cos^2x over sinx?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Because cos(2x) = cos^2(x)sin^2(x)
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Look at your trig double angle formulas
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
ohh aha! thanks. where did sin^2x come from
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
dw:1325731291201:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
yea i meant shouln't you get cos^2sinx over sinx instead of cos^2x sin^2x over sinx
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
And...dw:1325731384713:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
i am so sorry.. shouldn't you be dividing them by sinx not sin^2x? hahah :P
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
dw:1325731527945:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
thanks! i always thought dw:1325731485027:dw
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
dw:1325731638760:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
hehe i learned something 8p im always so confused .. : Sdfksj skJ anyway okay keep going please
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
dw:1325731751062:dw
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
ohhhhhhh!!!!!!!!!!!!!!! you can always work out right side instead of the left side too right? thanks!!!!!!!!!!!!!!! :P
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
Thanks alot for being patient with me :) and your explanation is great and quite fast! :)
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
You can work on either side when proving an identity or both sides. You just can't work across the equal sign like adding the same thing to both sides or something like that.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Well I could go faster if I knew how to make fractions with the equation thing.
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
you just type out 'over'
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
uw. p.s. are you a tutor? like to help students? anywho when you see identity questions how do you know what to do and which side to solve first?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
I used to teach math in high school for 32 years and now I am retired and tutor students who come to my house. I can usually solve identities.
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
oh wow, i see. well thanks again :) your help is always appreciated! :)
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.1
i got stuck again.. \[\left( cosx \over 1+sinx \right) = \left( 1sinx \over cosx \right)\] what should be the nxt step ?
 2 years ago
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