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Hannah_Ahn
 4 years ago
prove the identity: [\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]
Hannah_Ahn
 4 years ago
prove the identity: [\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]

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Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1\[\left( \cos2x \over \sin x \right) = \left( \cot^2x1 \over \csc x \right)\]

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1i got it until (cos^2 over sinx)  (sinx) after your second step i multiplied deno and numerator by sinx. but how did you get cos^2sin^2x over sinx and how is it same as cos^2x over sinx?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Because cos(2x) = cos^2(x)sin^2(x)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Look at your trig double angle formulas

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1ohh aha! thanks. where did sin^2x come from

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1yea i meant shouln't you get cos^2sinx over sinx instead of cos^2x sin^2x over sinx

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1And...dw:1325731384713:dw

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1i am so sorry.. shouldn't you be dividing them by sinx not sin^2x? hahah :P

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1thanks! i always thought dw:1325731485027:dw

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1hehe i learned something 8p im always so confused .. : Sdfksj skJ anyway okay keep going please

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1ohhhhhhh!!!!!!!!!!!!!!! you can always work out right side instead of the left side too right? thanks!!!!!!!!!!!!!!! :P

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1Thanks alot for being patient with me :) and your explanation is great and quite fast! :)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1You can work on either side when proving an identity or both sides. You just can't work across the equal sign like adding the same thing to both sides or something like that.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Well I could go faster if I knew how to make fractions with the equation thing.

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1you just type out 'over'

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1uw. p.s. are you a tutor? like to help students? anywho when you see identity questions how do you know what to do and which side to solve first?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1I used to teach math in high school for 32 years and now I am retired and tutor students who come to my house. I can usually solve identities.

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1oh wow, i see. well thanks again :) your help is always appreciated! :)

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.1i got stuck again.. \[\left( cosx \over 1+sinx \right) = \left( 1sinx \over cosx \right)\] what should be the nxt step ?
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