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Hannah_Ahn
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( 1 \over secx + tanx \right) = \left( 1sinx \over \cos x \right)\]

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1LHS=cosx / (1+sinx) LHS/RHS = (cos^2 x)/(1sin^2 x)=cos^2 x / cos^2 x =1 so LHS=RHS

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1multiply the numerator and denominator by cosx

Hannah_Ahn
 3 years ago
Best ResponseYou've already chosen the best response.0I don't get LHS/RHS? what's going on hehe

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1divide LHS by RHS and found it is 1. so we can say LHS=RHS

Hannah_Ahn
 3 years ago
Best ResponseYou've already chosen the best response.0(1sinx) times (1+sinx) is one?

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1(1sinx) times (1+sinx) = dw:1325741008297:dw
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