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Hannah_AhnBest ResponseYou've already chosen the best response.0
\[\left( 1 \over secx + tanx \right) = \left( 1sinx \over \cos x \right)\]
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
LHS=cosx / (1+sinx) LHS/RHS = (cos^2 x)/(1sin^2 x)=cos^2 x / cos^2 x =1 so LHS=RHS
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
multiply the numerator and denominator by cosx
 2 years ago

Hannah_AhnBest ResponseYou've already chosen the best response.0
I don't get LHS/RHS? what's going on hehe
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
divide LHS by RHS and found it is 1. so we can say LHS=RHS
 2 years ago

Hannah_AhnBest ResponseYou've already chosen the best response.0
(1sinx) times (1+sinx) is one?
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
(1sinx) times (1+sinx) = dw:1325741008297:dw
 2 years ago
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