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anonymous
 5 years ago
Can someone give me a only letter equation to solve?
anonymous
 5 years ago
Can someone give me a only letter equation to solve?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take 3 from both sides getting 2x=8 divide both sides by 2 gettin x=4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Btw, grats on Master rank

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can i have a harder one now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's called only a letter equation? :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nope but i take whats coming lol

across
 5 years ago
Best ResponseYou've already chosen the best response.4Let's do a slightly trickier one: (1/3)x+2=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ill take (1/3)x+2=3 1x+6=9, right sofar?

across
 5 years ago
Best ResponseYou've already chosen the best response.4Very good! Let's do this one now: (2/3)x+(5/2)=(5/4) (I love fractions.)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please put that in equation form

across
 5 years ago
Best ResponseYou've already chosen the best response.4\[\frac{2}{3}x+\frac{5}{2}=\frac{5}{4}\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4If you can do that without problems, then you would have mastered the solving of singlevariable, linear equations. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im supposed to "equalize the fractions" right?

across
 5 years ago
Best ResponseYou've already chosen the best response.4We're trying to solve for \(x\), so try and use the properties of addition, subtraction, multiplication and division to achieve that!\[\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2/3)x+(5/2)=(5/4)>(4/6)x+(10/4)=(10/8)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, just say yes or no, not why.

across
 5 years ago
Best ResponseYou've already chosen the best response.4You rewrote the equation. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2/3)x+(5/2)=(5/4) (2/3)x=(5/4)(5/2) Right so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now multiply both sides by 3 to get (3/3)x=(5/4)(5/2)*3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If so i have the answer

across
 5 years ago
Best ResponseYou've already chosen the best response.4You have the right idea, but you're overlooking a few steps. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(3/3)x=(5/4)*3(5/2)*3??

across
 5 years ago
Best ResponseYou've already chosen the best response.4Let's first focus on trying to simplify this:\[\frac{5}{4}\frac{5}{2}.\]Can you do that?

across
 5 years ago
Best ResponseYou've already chosen the best response.4There's where we're getting stuck. :P You need to learn how to simplify expressions of the form\[\frac{a}{b}\pm\frac{c}{d}.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:( i thought i knew this stuff...

across
 5 years ago
Best ResponseYou've already chosen the best response.4It's not too bad, really, there's a simple rule which states that\[\frac{a}{b}\pm\frac{c}{d}=\frac{ad\pm bc}{bd}.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Whats the logic in that?

across
 5 years ago
Best ResponseYou've already chosen the best response.4To put it simply, you cannot add nor subtract fractions with different bases. In other words,\[\frac{5}{4}\frac{5}{2}\]cannot be simplified as it stands since they have different bases (4 and 2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So i need to find the greates common (something i cant remember)?

across
 5 years ago
Best ResponseYou've already chosen the best response.4However, if you have something like\[\frac{3}{2}+\frac{5}{2},\]they have similar bases and thus you can add them accordingly:\[\frac{3+5}{2}=\frac{8}{2}=4.\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4You can do that OR you could use the fact that\[\frac{a}{b}\pm\frac{c}{d}=\frac{ad\pm bc}{bd}.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How about if they have similar (the ones we have over the base)(whatever they call them)

across
 5 years ago
Best ResponseYou've already chosen the best response.4The numerator? Do you mean something like\[\frac{3}{5}+\frac{3}{6}?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh wait, never mind i think i see why that wont work

across
 5 years ago
Best ResponseYou've already chosen the best response.4It doesn't matter: they have different bases and you can't add them.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2/3)x=(5/4)(5/2) 5*24*5/2*5?

across
 5 years ago
Best ResponseYou've already chosen the best response.4I saw something I liked: you know how to manipulate fractions. Could you manipulate\[\frac{5}{4}\frac{5}{2}\]so that they have similar bases?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not sure i know what you mean by manipulate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make them higher so they match or something?

across
 5 years ago
Best ResponseYou've already chosen the best response.4With "manipulate" I mean to say "play with" or "rearrange," like this:\[\frac{5}{2}=\frac{10}{4}=\frac{15}{6}=etc.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh you did mean like that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(5/2) (5/4)>2.5/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Aw man.. im really worthless at this..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0At this rate ill never learn quantum physics..

across
 5 years ago
Best ResponseYou've already chosen the best response.4That's good! But try and make the bases of the two fractions match and try to have only whole numbers in both the numerator and denominator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well how? i cant go upward.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(5/2)>(10/4)!!!! (5/4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now i can have (15)/(4)

across
 5 years ago
Best ResponseYou've already chosen the best response.4I'll give you an example. I'm given\[\frac{7}{3}+\frac{4}{5}.\]I want their denominators match, so I multiply \(7/3\) by \(5/5\) to get \(35/15\), and I multiply \(4/5\) by \(3/3\) to get \(12/15\). They now have similar denominators and I can add them:\[\frac{35}{15}+\frac{12}{15}=\frac{47}{15}.\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4Very good! You converted\[\frac{5}{4}\frac{5}{2}\]into\[\frac{5}{4}\frac{10}{4}.\]What's the next step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2/3)x=(5/4)(10/4) (2/3)x=(105)/4?

across
 5 years ago
Best ResponseYou've already chosen the best response.4That's very close! But you switched the signs:\[\frac{5}{4}\frac{10}{4}=\frac{510}{4}.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh right! so its (2/3)x=(5)/4

across
 5 years ago
Best ResponseYou've already chosen the best response.4That's correct! Now, let's solve for x. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can we multiply both sides by 3 now?

across
 5 years ago
Best ResponseYou've already chosen the best response.4Well, let's look at the LHS only: when you multiplied\[\frac{2}{3}x\]by \(3\), you somehow got\[\frac{3}{3}x.\]How did this happen?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait, should i divide both sides by 2/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please say its right..

across
 5 years ago
Best ResponseYou've already chosen the best response.4You could do that, yes, but let's do it one step at a time first so that you understand the process. When you have\[\frac{2}{3}x,\]to get rid of that \(3\) in the denominator, we DO multiply the fraction by \(3\) so that this happens:\[\frac{2}{3}x\implies3\cdot\frac{2}{3}x\implies\not{3}\cdot\frac{2}{\not{3}}x\implies2x.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh right, i knew it had something to do with multiplying with the denominator!

across
 5 years ago
Best ResponseYou've already chosen the best response.4Now, let's do a cool little trick: what happens if I multiply\[\frac{2}{3}x\]by\[\frac{3}{2}?\]:)

across
 5 years ago
Best ResponseYou've already chosen the best response.4Close!\[\frac{3}{2}\cdot\frac{2}{3}x=\frac{6}{6}x=x.\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so essentially, i was right?

across
 5 years ago
Best ResponseYou've already chosen the best response.4Now, can you apply this to solve\[\frac{2}{3}x=\frac{5}{4}?\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4Yes, you were right, but I don't think you understood the whole process, which now you do. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Both sides multiplied by 3/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If thats not right, im gonna go give up on physics and go cry in a corner..

across
 5 years ago
Best ResponseYou've already chosen the best response.4I think you got it already, but you're trying to speed your way through it. Take your time! :) Let's check again:\[\frac{5}{4}\cdot\frac{3}{2}=?\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4I see what you're trying to do, but remember that multiplication and division of fractions is totally different from addition and subtraction. :) They're easier, in fact!\[\frac{a}{b}\cdot\frac{c}{d}=\frac{ac}{bd}.\]

across
 5 years ago
Best ResponseYou've already chosen the best response.4Look at our final expression:\[\frac{5}{4}\cdot\frac{3}{2}=\frac{5\cdot3}{4\cdot2}=?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait, do you know what this means?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That im a complete and utter failure and that i will never become a physicist.

across
 5 years ago
Best ResponseYou've already chosen the best response.4Hey, it's your first time doing this. Don't beat yourself too hard. We're taking it one step at a time, and that's the best way there is to go!

across
 5 years ago
Best ResponseYou've already chosen the best response.4Also, when I had your age, I knew much, much less than you do, and now look at me; I'm a math grad student! Your enthusiasm stretches beyond any of that I've seen in most students your age. Please keep at it; you will go really far. Take advantage of the fact that there are people out there that will gladly help you, and you can for sure include me in that group of people.

wasiqss
 5 years ago
Best ResponseYou've already chosen the best response.0susanne its really sweet of u to help sumone like this with this devotion

wasiqss
 5 years ago
Best ResponseYou've already chosen the best response.0n yehh that kid is damn focused on the job for sure!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you will never become a physicist

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, im done sulking. Wanna do some math?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Fumble you lagrangeson.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those word came out of your mouth, fumble yourself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You suck. At least across tries to help me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your saying i havent helped you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You just said i wasnt gonna become a physicist! Mark my words, I WILL!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0prove it then you little squirt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Screw you, ill get 2 phds
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