anonymous
  • anonymous
TT or across, teach me some algebra!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
who is TT ?
anonymous
  • anonymous
TuringTest
Anikate
  • Anikate
what is x in this equation? 6+x=2

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anonymous
  • anonymous
-4
Anikate
  • Anikate
good job that was basic
anonymous
  • anonymous
I have been studying basic algebra.
Anikate
  • Anikate
x^2*x^3
anonymous
  • anonymous
x^5
anonymous
  • anonymous
x+y=6 x-y=7 can you find the x and y?
Anikate
  • Anikate
(x^3)^2
Anikate
  • Anikate
x=7+y
anonymous
  • anonymous
Anikate, he meant me.
anonymous
  • anonymous
FFM give me another one
Anikate
  • Anikate
oh ok...
anonymous
  • anonymous
\( a+b=9 \) \( a-b=11 \) what is \( a \) and what is \(b\) ?
anonymous
  • anonymous
a=10 b=-1 or a=9-b b=9-a
anonymous
  • anonymous
Okay .. do you understand the difference between variable and constant?
anonymous
  • anonymous
variable is something you put instead of a number, right?
anonymous
  • anonymous
More importantly, do you understand what in earth an equation means?
anonymous
  • anonymous
Excuse me?
anonymous
  • anonymous
Precisely, variable is something that varies, so yes you are right :)
anonymous
  • anonymous
Were you just calling me stupid?
anonymous
  • anonymous
No,lol :D you misunderstand my tone :) So what is an equation ?
anonymous
  • anonymous
Its a line that states values of variables, i guess
anonymous
  • anonymous
Hm. Let me explain.
anonymous
  • anonymous
A equation has two parts, right hand side and left hand side.
anonymous
  • anonymous
I know that
anonymous
  • anonymous
Anything right of the '=' sign is right hand side
anonymous
  • anonymous
I know, if you do something to the LHS you have to do the same to the RHS
anonymous
  • anonymous
yadda yadda, i know all that.
anonymous
  • anonymous
Good :D
anonymous
  • anonymous
Hey, that's not the right attitude towards mathematics :)
anonymous
  • anonymous
anyways back to the problem our hand: a+b=9 a−b=11
anonymous
  • anonymous
Yeah.
anonymous
  • anonymous
we want to find a and b in terms of constants only.
anonymous
  • anonymous
So whats a constant?
anonymous
  • anonymous
How could we do that ?
anonymous
  • anonymous
constant is something which value is fixed.
anonymous
  • anonymous
Ok, so we can subtract a from both sides to get b on the top one, right?
anonymous
  • anonymous
Why don't we add the equations? like this \[ a+b+a-b=9+11\]
anonymous
  • anonymous
Oh you want me to use both equations?
anonymous
  • anonymous
Well we can simplify that to a2=20, right?
anonymous
  • anonymous
Cause the b's cancel eachother out
anonymous
  • anonymous
yes.
anonymous
  • anonymous
And for a we can just divide both sides by 2 getting x=10
anonymous
  • anonymous
a=10*
anonymous
  • anonymous
Good, now what about b ?
anonymous
  • anonymous
a+b+a−b=9+11 a2 +b=20+b Am i doing alright so far?
anonymous
  • anonymous
no, you need to subtract this time
anonymous
  • anonymous
Subtract what exactly?
anonymous
  • anonymous
a+b-a+b=9-11
anonymous
  • anonymous
Is is (a+b)-(a+b) or without parenthesis?
anonymous
  • anonymous
second equation from the first.
anonymous
  • anonymous
Oh i see, this si the second one?
anonymous
  • anonymous
(a+b)-(a-b) without parentheses
anonymous
  • anonymous
a+b-a+b=9-11 2b=9-11 2b=-2 b=-1
anonymous
  • anonymous
See? I can do this!
anonymous
  • anonymous
Very good :)
anonymous
  • anonymous
:D
anonymous
  • anonymous
Gimme something harder!
anonymous
  • anonymous
If ax - a = x - 1 what is x equal to?
anonymous
  • anonymous
Divide both sides by x, right so far?
anonymous
  • anonymous
No wait, ax - a = x - 1 ax=x-1+a x=x-1 Im stumped
anonymous
  • anonymous
First, bring all the x terms to one side, and everything else to the other.
anonymous
  • anonymous
Im sorry, i havent studied factoring yet :/
anonymous
  • anonymous
Ok. Here's the solution ax - a = x - 1 ax - x - a = -1 ax - x = a - 1 x(a - 1) = a - 1 hence x = 1
anonymous
  • anonymous
Ok, youll have to give me another one tommorrow so i can try :D

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