TT or across, teach me some algebra!!!

- anonymous

TT or across, teach me some algebra!!!

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- schrodinger

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- anonymous

who is TT ?

- anonymous

TuringTest

- Anikate

what is x in this equation?
6+x=2

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## More answers

- anonymous

-4

- Anikate

good job that was basic

- anonymous

I have been studying basic algebra.

- Anikate

x^2*x^3

- anonymous

x^5

- anonymous

x+y=6
x-y=7
can you find the x and y?

- Anikate

(x^3)^2

- Anikate

x=7+y

- anonymous

Anikate, he meant me.

- anonymous

FFM give me another one

- Anikate

oh ok...

- anonymous

\( a+b=9 \)
\( a-b=11 \)
what is \( a \) and what is \(b\) ?

- anonymous

a=10
b=-1
or
a=9-b
b=9-a

- anonymous

Okay .. do you understand the difference between variable and constant?

- anonymous

variable is something you put instead of a number, right?

- anonymous

More importantly, do you understand what in earth an equation means?

- anonymous

Excuse me?

- anonymous

Precisely, variable is something that varies, so yes you are right :)

- anonymous

Were you just calling me stupid?

- anonymous

No,lol :D you misunderstand my tone :)
So what is an equation ?

- anonymous

Its a line that states values of variables, i guess

- anonymous

Hm. Let me explain.

- anonymous

A equation has two parts, right hand side and left hand side.

- anonymous

I know that

- anonymous

Anything right of the '=' sign is right hand side

- anonymous

I know, if you do something to the LHS you have to do the same to the RHS

- anonymous

yadda yadda, i know all that.

- anonymous

Good :D

- anonymous

Hey, that's not the right attitude towards mathematics :)

- anonymous

anyways back to the problem our hand:
a+b=9
a−b=11

- anonymous

Yeah.

- anonymous

we want to find a and b in terms of constants only.

- anonymous

So whats a constant?

- anonymous

How could we do that ?

- anonymous

constant is something which value is fixed.

- anonymous

Ok, so we can subtract a from both sides to get b on the top one, right?

- anonymous

Why don't we add the equations?
like this \[ a+b+a-b=9+11\]

- anonymous

Oh you want me to use both equations?

- anonymous

Well we can simplify that to a2=20, right?

- anonymous

Cause the b's cancel eachother out

- anonymous

yes.

- anonymous

And for a we can just divide both sides by 2 getting x=10

- anonymous

a=10*

- anonymous

Good, now what about b ?

- anonymous

a+b+a−b=9+11
a2 +b=20+b
Am i doing alright so far?

- anonymous

no, you need to subtract this time

- anonymous

Subtract what exactly?

- anonymous

a+b-a+b=9-11

- anonymous

Is is (a+b)-(a+b) or without parenthesis?

- anonymous

second equation from the first.

- anonymous

Oh i see, this si the second one?

- anonymous

(a+b)-(a-b) without parentheses

- anonymous

a+b-a+b=9-11
2b=9-11
2b=-2
b=-1

- anonymous

See? I can do this!

- anonymous

Very good :)

- anonymous

:D

- anonymous

Gimme something harder!

- anonymous

If
ax - a = x - 1
what is x equal to?

- anonymous

Divide both sides by x, right so far?

- anonymous

No wait,
ax - a = x - 1
ax=x-1+a
x=x-1
Im stumped

- anonymous

First, bring all the x terms to one side, and everything else to the other.

- anonymous

Im sorry, i havent studied factoring yet :/

- anonymous

Ok. Here's the solution
ax - a = x - 1
ax - x - a = -1
ax - x = a - 1
x(a - 1) = a - 1
hence
x = 1

- anonymous

Ok, youll have to give me another one tommorrow so i can try :D

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