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Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1i think you mistyped something...

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1it should be sin2x over (22cos^2x) = cotx

Hannah_Ahn
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( \sin2x \over 22\cos^2x \right) = cotx\]

Yifan12879
 3 years ago
Best ResponseYou've already chosen the best response.1first look at the numerator sin2x=2sinx cosx then the deno 22cos^2 x = 2(1cos^2 x)=2 sin^2 x= 2 sinx sinx so LHS=nume/demo=2sinxcosx / 2sinxsinx = cosx/sinx=cotx
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