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Hannah_Ahn

  • 4 years ago

prove: (sin2x over 2-2cos^2x) = cotx

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  1. Yifan12879
    • 4 years ago
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    i think you mistyped something...

  2. Yifan12879
    • 4 years ago
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    it should be sin2x over (2-2cos^2x) = cotx

  3. Hannah_Ahn
    • 4 years ago
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    \[\left( \sin2x \over 2-2\cos^2x \right) = cotx\]

  4. Yifan12879
    • 4 years ago
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    first look at the numerator sin2x=2sinx cosx then the deno 2-2cos^2 x = 2(1-cos^2 x)=2 sin^2 x= 2 sinx sinx so LHS=nume/demo=2sinxcosx / 2sinxsinx = cosx/sinx=cotx

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