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Yifan12879Best ResponseYou've already chosen the best response.1
i think you mistyped something...
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
it should be sin2x over (22cos^2x) = cotx
 2 years ago

Hannah_AhnBest ResponseYou've already chosen the best response.0
\[\left( \sin2x \over 22\cos^2x \right) = cotx\]
 2 years ago

Yifan12879Best ResponseYou've already chosen the best response.1
first look at the numerator sin2x=2sinx cosx then the deno 22cos^2 x = 2(1cos^2 x)=2 sin^2 x= 2 sinx sinx so LHS=nume/demo=2sinxcosx / 2sinxsinx = cosx/sinx=cotx
 2 years ago
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