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creekrat48
Group Title
A sample of phosphorus32 has a halflife of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 days, what was the mass of the original sample?
 2 years ago
 2 years ago
creekrat48 Group Title
A sample of phosphorus32 has a halflife of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 days, what was the mass of the original sample?
 2 years ago
 2 years ago

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Kainui Group TitleBest ResponseYou've already chosen the best response.4
A halflife is the amount of time it takes for half of the total isotope to decay. So if you know that 55g are left after 57 days and it decreases the total amount by half every 14.28 days, can you set up an equation that describes this?
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
thank you
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
You're welcome, if you need more help just ask =D
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
wait is it 13.75 g
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
Nope, it can't be simply because you ended up with 55 g of the sample in the end. How could you have 13.75 g decaying away to become more than what you started with?
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
ok so i didnt understand how to work this out sorry
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
You're on the right track, but not quite there. 3.99 is not the mass in grams, it is the number of halflives that the sample has gone through! So now that you know how many times it has split in half, maybe that will help you out more?
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
I am not sure where to go from here is it mass to mole
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
Nope, no moles are involved in this problem. I'll type out a better explanation, give me a sec haha.
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
OK PLEASE, I HAVE STRUGGLED WITH THIS FOR 2 DAYS AND HAVE SO MUCH MORE TO DO.
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
So you know that the sample has been around for 57 days and the half life is 14.28 days. That must mean that 57/14.28 days. That gave you your 3.99 number of halflives (not moles) So you have 1/2 to the 3.99 power because you have 1/2 times itself as many times as you have gone through a halflife. 55g = X.5^(57/14.28) Divide 55 by 1/2 to the 57/14.28 power and you should get something like 880g
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.4
I rounded 3.99 to 4 when I did my calculation, so your answer will be 873.92g if you use 3.99 instead. Hope that helps.
 2 years ago

creekrat48 Group TitleBest ResponseYou've already chosen the best response.1
thank you your the best!!!!
 2 years ago
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