Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

lperkows Group TitleBest ResponseYou've already chosen the best response.1
#2 is correct. You know this because when you solve for y, the x's have the same slope.
 2 years ago

trumpetboy101 Group TitleBest ResponseYou've already chosen the best response.3
Only 2. I agree.
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
y=mx+b where "m" is the gradient < marmar i hope you are familiar with this equation. so for 2y =22x, you agree that it can be written as 2y=2x+2, and after you factorise/simplify(ie divide everything by 2) it will look like y =x+1 does this look familiar to the form y= mx+b, hence we may deduce that m= 1 if we then look at the options they offer for the SECOND one 1x 4 =1y do you agree that this is the same as writing 1y= 1x +4 thus "m" =1 which is the SAME for 2y =22x for the THIRD one, 2y 4 =x, you agree this is the same as y =(x/2)+(4/2) where "m" = 1/2 which is NOT THE SAME for 2y =22x for the FOURTH one, 2y 3 =2x, you agree this is the same as writing y=(2x/2) +(3/2), thus "m" =1 which is NOT THE SAME for 2y =22x therefore, it is true for only the SECOND ONE. and because it is true for the SECOND ONE we may dismiss the FIRST ONE which is "None of them" as a possible answer. so the final answer is the SECOND ONE. i hope this makes sense
 2 years ago

Prebz Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=2x%2B2y%3D2+and+x4%3Dy+and+2x%3Dy%2B4+and+2y4%3Dx+and+2y3%3D2x Here's a (hopefully) easy visualization of the problem.
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
nice diagram!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.