how do i solve f(x)=secx at [-pi/3,pi/6] to get global extreme values??

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- anonymous

how do i solve f(x)=secx at [-pi/3,pi/6] to get global extreme values??

- jamiebookeater

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- anonymous

There are two methods:-
1)Graph Do you know nature of sec x graph?
2) theory: f'(x)=sec x tan x you need to see in (-pi/6,pi/3) if it is 0,+ve or _ve.

- anonymous

Here f'(x)<0 when x<0 as sec x>0 and tan x<0 and f'(x)>0 for x>0 so function is decreasing for -ve x and increasing for +ve x hence max will be attained in the given interval at max possible x=pi/6

- across

What you're stating is contradictory: You're asking to find the global values of a function... within an interval?

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- anonymous

it is a closed interval so yes..

- anonymous

@across they're not contradictory You could have mutiple extemums in a given interval the question wants the maximun of those local maximums

- across

Perhaps I'm misunderstanding the meaning of "global" here.

- anonymous

err yeah global in this case is the given domain....

- anonymous

Anyways suju this question is easier by graph method... Do you know graph of sec x?

- across

Sorry, I'm a nitpick when it comes to word usage. :P Wouldn't those be local extrema instead?

- anonymous

Not really in a given interval what if there are two local maximums, The maximum of the two maximums is assumed to be global in this case...

- anonymous

Oh and in the theory part you also need to check the least value of x as f(x) is decreasing when x<0

- across

I see. Thanks for clarifying. :)

- anonymous

@shankee i don't know abt the graph and i am supposed to solve this theoritically.

- anonymous

Err okay so f'(x)<0 at x<0 means function is initially decreasing. Then at x=F'(x)=0 as tanx=0 so tangent is horizontal and f'(x)>0at x>0 implies function increases afterwards. Now theoratically the maximum could occur at two points which are the two end points THis is bcoz All values in between them in their nieghbourhood will be less than them. So just plug in the end points whichever gives greater value is the answer

- anonymous

|dw:1325938871185:dw| Just to make it clear initially it is decreasing then increasing.

- anonymous

thnx.

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