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Inopeki

  • 4 years ago

Can someone teach me systems of equations?

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  1. agdgdgdgwngo
    • 4 years ago
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    a linear system is simply a set of linear equations.

  2. Inopeki
    • 4 years ago
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    Ok, but can you give me an example so i can try?

  3. agdgdgdgwngo
    • 4 years ago
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    here's an easy one: 2x + y = 3 x + y = 1

  4. Inopeki
    • 4 years ago
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    2x + y = 3 + x + y = 1 Is this the right first step?

  5. agdgdgdgwngo
    • 4 years ago
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    you can do 3 different things to solve a linear system: 1. graph the equations, and find where they intersect. 2. substitution 3. elimination.

  6. Inopeki
    • 4 years ago
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    Im gonna do elimination then substitution

  7. Inopeki
    • 4 years ago
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    No wait

  8. Inopeki
    • 4 years ago
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    I cant do elimination on this one

  9. Inopeki
    • 4 years ago
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    2x + y = 3 + x + -y = 1-2y 3x=4-2y

  10. Inopeki
    • 4 years ago
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    That cant be right

  11. agdgdgdgwngo
    • 4 years ago
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    you can; in fact elimination would be the easy way out of this one

  12. Inopeki
    • 4 years ago
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    WAIT

  13. Inopeki
    • 4 years ago
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    Can i divide the equations?

  14. agdgdgdgwngo
    • 4 years ago
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    if you subtract equation 2 from equation 1: you get x = 2 x + y = 1 next step is to subtract the new equation 1 from equation 2

  15. Inopeki
    • 4 years ago
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    y=1?

  16. agdgdgdgwngo
    • 4 years ago
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    you can't really divide the equations

  17. Inopeki
    • 4 years ago
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    Ok, i see why now

  18. Inopeki
    • 4 years ago
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    Give me another one so i can try, i think i see the pattern

  19. agdgdgdgwngo
    • 4 years ago
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    2x + y = 5 x + y = 3

  20. Inopeki
    • 4 years ago
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    2x + y = 5 - x + y = 3 = x=2? The y's cancel out right?

  21. Inopeki
    • 4 years ago
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    Now i can substitute to get y

  22. agdgdgdgwngo
    • 4 years ago
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    right

  23. Inopeki
    • 4 years ago
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    2 + y = 3 y=1

  24. Inopeki
    • 4 years ago
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    I can cross check this with the other equation

  25. Inopeki
    • 4 years ago
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    4 + 1 = 5 2 + 1 = 3

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