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suju101

  • 4 years ago

solve this to get find global extreme values: f(x)=x^4-8x^2+4x+2 at [-(20/25),(64/25)]

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  1. TuringTest
    • 4 years ago
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    Why do you specify a point?

  2. imranmeah91
    • 4 years ago
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    is that range?

  3. suju101
    • 4 years ago
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    yep!! extrema values fall in the range so it is specified.

  4. TuringTest
    • 4 years ago
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    can't solve the cubic is all?

  5. imranmeah91
    • 4 years ago
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    find criticle points check criticle points and boundary points

  6. suju101
    • 4 years ago
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    i know that but i couldn't solve the equation

  7. imranmeah91
    • 4 years ago
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    D[x^4-8x^2+4x+2 ]-->= 4x^3 -16x+4=0

  8. imranmeah91
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=4x%5E3%20-16x%2B4%3D0&t=crmtb01

  9. suju101
    • 4 years ago
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    and how to solve that eqn to get value of x

  10. sam_unleashed
    • 4 years ago
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    x^3-4x+1=0...then.. main problem is , to solve for x...

  11. suju101
    • 4 years ago
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    @sam yes

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