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solve this to get find global extreme values:
f(x)=x^48x^2+4x+2 at [(20/25),(64/25)]
 2 years ago
 2 years ago
solve this to get find global extreme values: f(x)=x^48x^2+4x+2 at [(20/25),(64/25)]
 2 years ago
 2 years ago

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TuringTestBest ResponseYou've already chosen the best response.0
Why do you specify a point?
 2 years ago

suju101Best ResponseYou've already chosen the best response.0
yep!! extrema values fall in the range so it is specified.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
can't solve the cubic is all?
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.0
find criticle points check criticle points and boundary points
 2 years ago

suju101Best ResponseYou've already chosen the best response.0
i know that but i couldn't solve the equation
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.0
D[x^48x^2+4x+2 ]>= 4x^3 16x+4=0
 2 years ago

imranmeah91Best ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=4x%5E3%2016x%2B4%3D0&t=crmtb01
 2 years ago

suju101Best ResponseYou've already chosen the best response.0
and how to solve that eqn to get value of x
 2 years ago

sam_unleashedBest ResponseYou've already chosen the best response.0
x^34x+1=0...then.. main problem is , to solve for x...
 2 years ago
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