A community for students.
Here's the question you clicked on:
 0 viewing
suju101
 3 years ago
solve this to get find global extreme values:
f(x)=x^48x^2+4x+2 at [(20/25),(64/25)]
suju101
 3 years ago
solve this to get find global extreme values: f(x)=x^48x^2+4x+2 at [(20/25),(64/25)]

This Question is Closed

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0Why do you specify a point?

suju101
 3 years ago
Best ResponseYou've already chosen the best response.0yep!! extrema values fall in the range so it is specified.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0can't solve the cubic is all?

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0find criticle points check criticle points and boundary points

suju101
 3 years ago
Best ResponseYou've already chosen the best response.0i know that but i couldn't solve the equation

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0D[x^48x^2+4x+2 ]>= 4x^3 16x+4=0

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=4x%5E3%2016x%2B4%3D0&t=crmtb01

suju101
 3 years ago
Best ResponseYou've already chosen the best response.0and how to solve that eqn to get value of x

sam_unleashed
 3 years ago
Best ResponseYou've already chosen the best response.0x^34x+1=0...then.. main problem is , to solve for x...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.