anonymous
  • anonymous
prove 1+sin2x=(sinx=cosx)^2
Mathematics
katieb
  • katieb
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katieb
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Zarkon
  • Zarkon
got a lot of equal signs there ;)
Zarkon
  • Zarkon
for \[1+\sin(2x)=(\sin(x)+\cos(x))^2\] use \[\sin(2x)=2\sin(x)\cos(x)\] and \[\sin^2(x)+\cos^2(x)=1\]
anonymous
  • anonymous
\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\]

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anonymous
  • anonymous
zarkon: haha thanks for noticing that ;) and....? is that it?
anonymous
  • anonymous
Nah you still have to work it out, just fit the pieces together lol
Zarkon
  • Zarkon
combine the work Will! and I did.
anonymous
  • anonymous
i don't get it :(
Zarkon
  • Zarkon
\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\] \[= \sin^2 x + \cos^2 x +2\sin x \cos x=\cdots\]
Zarkon
  • Zarkon
now use what I told you to use. :)
anonymous
  • anonymous
aha! solved! :) gracias :)
Zarkon
  • Zarkon
De nada

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