Hannah_Ahn
prove
1+sin2x=(sinx=cosx)^2



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Zarkon
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got a lot of equal signs there ;)

Zarkon
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for \[1+\sin(2x)=(\sin(x)+\cos(x))^2\]
use \[\sin(2x)=2\sin(x)\cos(x)\]
and
\[\sin^2(x)+\cos^2(x)=1\]

Will!
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\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\]

Hannah_Ahn
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zarkon: haha thanks for noticing that ;)
and....? is that it?

Will!
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Nah you still have to work it out, just fit the pieces together lol

Zarkon
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combine the work Will! and I did.

Hannah_Ahn
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i don't get it :(

Zarkon
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\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\]
\[= \sin^2 x + \cos^2 x +2\sin x \cos x=\cdots\]

Zarkon
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now use what I told you to use. :)

Hannah_Ahn
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aha! solved! :)
gracias :)

Zarkon
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De nada