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Hannah_Ahn

  • 4 years ago

prove 1+sin2x=(sinx=cosx)^2

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  1. Zarkon
    • 4 years ago
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    got a lot of equal signs there ;)

  2. Zarkon
    • 4 years ago
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    for \[1+\sin(2x)=(\sin(x)+\cos(x))^2\] use \[\sin(2x)=2\sin(x)\cos(x)\] and \[\sin^2(x)+\cos^2(x)=1\]

  3. Will!
    • 4 years ago
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    \[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\]

  4. Hannah_Ahn
    • 4 years ago
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    zarkon: haha thanks for noticing that ;) and....? is that it?

  5. Will!
    • 4 years ago
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    Nah you still have to work it out, just fit the pieces together lol

  6. Zarkon
    • 4 years ago
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    combine the work Will! and I did.

  7. Hannah_Ahn
    • 4 years ago
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    i don't get it :(

  8. Zarkon
    • 4 years ago
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    \[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\] \[= \sin^2 x + \cos^2 x +2\sin x \cos x=\cdots\]

  9. Zarkon
    • 4 years ago
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    now use what I told you to use. :)

  10. Hannah_Ahn
    • 4 years ago
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    aha! solved! :) gracias :)

  11. Zarkon
    • 4 years ago
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    De nada

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