Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Zarkon Group TitleBest ResponseYou've already chosen the best response.4
got a lot of equal signs there ;)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.4
for \[1+\sin(2x)=(\sin(x)+\cos(x))^2\] use \[\sin(2x)=2\sin(x)\cos(x)\] and \[\sin^2(x)+\cos^2(x)=1\]
 2 years ago

Will! Group TitleBest ResponseYou've already chosen the best response.1
\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\]
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
zarkon: haha thanks for noticing that ;) and....? is that it?
 2 years ago

Will! Group TitleBest ResponseYou've already chosen the best response.1
Nah you still have to work it out, just fit the pieces together lol
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.4
combine the work Will! and I did.
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
i don't get it :(
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.4
\[(\sin x + \cos x)^2 = \sin^2 x + 2(\sin x \cos x) + \cos^2 x\] \[= \sin^2 x + \cos^2 x +2\sin x \cos x=\cdots\]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.4
now use what I told you to use. :)
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
aha! solved! :) gracias :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.