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Hannah_Ahn
Group Title
Solve algebraically. Express the roots in exact form. 2sinxcosx1 = 0
the answer is pi over 4 + n pi
and I don't know the steps
please help,
thanks :)
 2 years ago
 2 years ago
Hannah_Ahn Group Title
Solve algebraically. Express the roots in exact form. 2sinxcosx1 = 0 the answer is pi over 4 + n pi and I don't know the steps please help, thanks :)
 2 years ago
 2 years ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.2
sin(2x)1=0 sin(2x)=1
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
when is sin(u), 1?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
when u=pi/2+2npi u=3pi/2+2npi so that means 2x=pi/2+2npi 2x=3pi/2+2npi
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
pi over 2
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
to solve for x just divide both sides by 2
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
lovely! thanks. have a wonderful night :)
 2 years ago
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