anonymous
  • anonymous
Solve algebraically. Express the roots in exact form. 2sinxcosx-1 = 0 the answer is pi over 4 + n pi and I don't know the steps please help, thanks :)
Mathematics
schrodinger
  • schrodinger
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myininaya
  • myininaya
sin(2x)-1=0 sin(2x)=1
myininaya
  • myininaya
when is sin(u), 1?
myininaya
  • myininaya
when u=pi/2+2npi u=3pi/2+2npi so that means 2x=pi/2+2npi 2x=3pi/2+2npi

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anonymous
  • anonymous
pi over 2
myininaya
  • myininaya
to solve for x just divide both sides by 2
anonymous
  • anonymous
lovely! thanks. have a wonderful night :)
myininaya
  • myininaya
np

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