Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Hannah_Ahn
Group Title
prove.
sin [(pi over 4)+x] + sin [(pi over 4)x] = sqrt{2} cosx
 2 years ago
 2 years ago
Hannah_Ahn Group Title
prove. sin [(pi over 4)+x] + sin [(pi over 4)x] = sqrt{2} cosx
 2 years ago
 2 years ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.3
i think expanding both of those things might help
 2 years ago

sam_unleashed Group TitleBest ResponseYou've already chosen the best response.1
use ... sin(a=b)= sin(a)cos(b) +cos(a)sin(b) and sin(ab)= sin(a)cos(b) cos(a)sin(b)
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
all i know is that i will have to use addition indentities.
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.3
\[[\sin(\frac{\pi}{4})\cos(x)+\sin(x)\cos(\frac{\pi}{4})]+[\sin(\frac{\pi}{4})\cos(x)\sin(x)\cos(\frac{\pi}{4})]\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.3
\[\frac{\sqrt{2}}{2} \cos(x)+\sin(x) \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\cos(x)\sin(x)\frac{\sqrt{2}}{2}\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.3
combine like terms and you will be done
 2 years ago

sam_unleashed Group TitleBest ResponseYou've already chosen the best response.1
its 2sin(a)cos(b)....now plug valus.....(2/\[\sqrt{2}\] ) sinx
 2 years ago

sam_unleashed Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{2}\] sin x
 2 years ago

Hannah_Ahn Group TitleBest ResponseYou've already chosen the best response.0
you rock myininaya!!! thank you so much!!! and i appreciate your work and help Sam_unleashed! :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.