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Hannah_Ahn
 4 years ago
prove.
sin [(pi over 4)+x] + sin [(pi over 4)x] = sqrt{2} cosx
Hannah_Ahn
 4 years ago
prove. sin [(pi over 4)+x] + sin [(pi over 4)x] = sqrt{2} cosx

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3i think expanding both of those things might help

sam_unleashed
 4 years ago
Best ResponseYou've already chosen the best response.1use ... sin(a=b)= sin(a)cos(b) +cos(a)sin(b) and sin(ab)= sin(a)cos(b) cos(a)sin(b)

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.0all i know is that i will have to use addition indentities.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[[\sin(\frac{\pi}{4})\cos(x)+\sin(x)\cos(\frac{\pi}{4})]+[\sin(\frac{\pi}{4})\cos(x)\sin(x)\cos(\frac{\pi}{4})]\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[\frac{\sqrt{2}}{2} \cos(x)+\sin(x) \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\cos(x)\sin(x)\frac{\sqrt{2}}{2}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3combine like terms and you will be done

sam_unleashed
 4 years ago
Best ResponseYou've already chosen the best response.1its 2sin(a)cos(b)....now plug valus.....(2/\[\sqrt{2}\] ) sinx

sam_unleashed
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{2}\] sin x

Hannah_Ahn
 4 years ago
Best ResponseYou've already chosen the best response.0you rock myininaya!!! thank you so much!!! and i appreciate your work and help Sam_unleashed! :)
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