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taranicolee

  • 2 years ago

log-5x=log (10-3x)

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  1. slaaibak
    • 2 years ago
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    \[\log (-5x) = \log(10 - 3x)\] Is that the question?

  2. taranicolee
    • 2 years ago
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    yeah haha my bad

  3. slaaibak
    • 2 years ago
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    Do you agree that -5x = 10 - 3x ?

  4. FoolForMath
    • 2 years ago
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    x=-5?

  5. taranicolee
    • 2 years ago
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    i understand that one now though. but another one of the questions is log a=og(4a-9) and the answer is supposed to be 3 but i'm getting 2.25

  6. taranicolee
    • 2 years ago
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    yeah -5 is what i got (:

  7. slaaibak
    • 2 years ago
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    I don't think you can have a negative log tho :/ so no real solutions?

  8. FoolForMath
    • 2 years ago
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    but RHS is imaginary!

  9. taranicolee
    • 2 years ago
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    true

  10. FoolForMath
    • 2 years ago
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    so,no real solution exists.

  11. slaaibak
    • 2 years ago
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    log a = log(4a - 9) Now: a = 4a - 9 -3a = -9 a = 3

  12. taranicolee
    • 2 years ago
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    OH dude. i'm dumb. for some reason i was moving it over and changing it to -4a -.- thank you so much !!!!

  13. FoolForMath
    • 2 years ago
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    you are not dumb,silly mistakes happens :-)

  14. taranicolee
    • 2 years ago
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    (: thanks !

  15. slaaibak
    • 2 years ago
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    haha, the mistakes I've made in math are far worse :) Hope this helped!

  16. taranicolee
    • 2 years ago
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    wait i'm sorry can i ask another question? ( i was absent when this was all being taught) but how would you solve -4log3-9m=-4? since there's no log on the right side of the equation?

  17. slaaibak
    • 2 years ago
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    \[-4\log(3-9m)=-4 \] ?

  18. taranicolee
    • 2 years ago
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    \[-4\log _{3}-9m=-4\] (:

  19. slaaibak
    • 2 years ago
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    wait, that doesn't make sense. \[-4\log_3(-9m)=-4 \]

  20. taranicolee
    • 2 years ago
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    maybe that's how it's supposed to be. it just doesn't show up like that on the worksheet.

  21. slaaibak
    • 2 years ago
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    Assuming that's the question: First divide both side by -4: \[\log_3(-9m) = 1\] Now, you need to know this property of logarithms: \[a^x = b\] \[\log_a b = x\] \[a^x = b\] Now your problem: \[\log_3(-9m) = 1 \rightarrow 3^1 = -9m\] \[m={-1 \over 3}\]

  22. taranicolee
    • 2 years ago
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    WOW. you're great.

  23. slaaibak
    • 2 years ago
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    :) Know the laws by heart, and it will be very very easy!

  24. taranicolee
    • 2 years ago
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    haha i hope so.

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