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slaaibak Group TitleBest ResponseYou've already chosen the best response.3
\[\log (5x) = \log(10  3x)\] Is that the question?
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
yeah haha my bad
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
Do you agree that 5x = 10  3x ?
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
i understand that one now though. but another one of the questions is log a=og(4a9) and the answer is supposed to be 3 but i'm getting 2.25
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
yeah 5 is what i got (:
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
I don't think you can have a negative log tho :/ so no real solutions?
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
but RHS is imaginary!
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
so,no real solution exists.
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
log a = log(4a  9) Now: a = 4a  9 3a = 9 a = 3
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
OH dude. i'm dumb. for some reason i was moving it over and changing it to 4a . thank you so much !!!!
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
you are not dumb,silly mistakes happens :)
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
(: thanks !
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
haha, the mistakes I've made in math are far worse :) Hope this helped!
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
wait i'm sorry can i ask another question? ( i was absent when this was all being taught) but how would you solve 4log39m=4? since there's no log on the right side of the equation?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
\[4\log(39m)=4 \] ?
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
\[4\log _{3}9m=4\] (:
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
wait, that doesn't make sense. \[4\log_3(9m)=4 \]
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
maybe that's how it's supposed to be. it just doesn't show up like that on the worksheet.
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
Assuming that's the question: First divide both side by 4: \[\log_3(9m) = 1\] Now, you need to know this property of logarithms: \[a^x = b\] \[\log_a b = x\] \[a^x = b\] Now your problem: \[\log_3(9m) = 1 \rightarrow 3^1 = 9m\] \[m={1 \over 3}\]
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
WOW. you're great.
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.3
:) Know the laws by heart, and it will be very very easy!
 2 years ago

taranicolee Group TitleBest ResponseYou've already chosen the best response.0
haha i hope so.
 2 years ago
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