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taranicolee
 3 years ago
log5x=log (103x)
taranicolee
 3 years ago
log5x=log (103x)

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slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3\[\log (5x) = \log(10  3x)\] Is that the question?

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3Do you agree that 5x = 10  3x ?

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0i understand that one now though. but another one of the questions is log a=og(4a9) and the answer is supposed to be 3 but i'm getting 2.25

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0yeah 5 is what i got (:

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3I don't think you can have a negative log tho :/ so no real solutions?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.1but RHS is imaginary!

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.1so,no real solution exists.

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3log a = log(4a  9) Now: a = 4a  9 3a = 9 a = 3

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0OH dude. i'm dumb. for some reason i was moving it over and changing it to 4a . thank you so much !!!!

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.1you are not dumb,silly mistakes happens :)

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3haha, the mistakes I've made in math are far worse :) Hope this helped!

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0wait i'm sorry can i ask another question? ( i was absent when this was all being taught) but how would you solve 4log39m=4? since there's no log on the right side of the equation?

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3\[4\log(39m)=4 \] ?

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0\[4\log _{3}9m=4\] (:

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3wait, that doesn't make sense. \[4\log_3(9m)=4 \]

taranicolee
 3 years ago
Best ResponseYou've already chosen the best response.0maybe that's how it's supposed to be. it just doesn't show up like that on the worksheet.

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3Assuming that's the question: First divide both side by 4: \[\log_3(9m) = 1\] Now, you need to know this property of logarithms: \[a^x = b\] \[\log_a b = x\] \[a^x = b\] Now your problem: \[\log_3(9m) = 1 \rightarrow 3^1 = 9m\] \[m={1 \over 3}\]

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.3:) Know the laws by heart, and it will be very very easy!
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