anonymous
  • anonymous
What is the ordered pair of positive intgers (a,b) for which a/b is a reduced fraction and \[x = \frac{a \pi}{b}\] is the least positive solution of the equation: \[(2 \cos (8x) - 1)(2 \cos (4x) - 1)(2 \cos (2x) - 1)(2 \cos (x) - 1) = 1\]?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
0?
anonymous
  • anonymous
i don't know the solution
anonymous
  • anonymous
\( 2 \pi \) ?

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anonymous
  • anonymous
how do you get that?
Mertsj
  • Mertsj
What course are you taking moneybird that this problem came from?
anonymous
  • anonymous
Grade 10 math
Mertsj
  • Mertsj
ty
Mertsj
  • Mertsj
This equation will be true if each factor = 1. Each factor will equal 1 if x = 0. So a/b, which must be 2 positive integers is 2/1
anonymous
  • anonymous
how about 1 factor is 4, and 1 factor is 1/4
Mertsj
  • Mertsj
That could not be true. The largest value of the cos is 1
Mertsj
  • Mertsj
So the largest value of 2cos x is 2
anonymous
  • anonymous
The maximum of every parenthetical is 1, the minimum is -2. You would need multiplicative inverses and even factors of positive for this to work
Mertsj
  • Mertsj
Regardless of the value of x
anonymous
  • anonymous
Let me think about it
anonymous
  • anonymous
good work

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