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repetition?

You know, practising something you have learned

Oh maybe thats not a word xd

revision

factor\[x^2y^4-x^4y^2\]

Ohhh, im thinking of the swedish word..

repetition is a word, just not the right one

Again??

yes that should work :)
and yes, /again/ GT lol
continue Inopeki.

x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)=-x^4*y^4?

x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)=(-x^4)*y^4?

who who you got much closer with
x^2*y^2(y^2-x^2)
but is there something familiar here?

x^2*y^2(y-x)(y+x)?

yes :)
good job, tricky one!

Thanks :DDD

one step closer to quantum mechanics

:D baby steps are still steps, right?

Yes, if i remember right.

ok
(1,4) (6,12)
what is the slope between the points?

Well
12+4
----- Doing alright?
6+1

- actually

No wait

12-4
----- =8/5
6-1

\[\Delta y \div \Delta x\]

|dw:1326067972678:dw|

I need to get x first then substitute to get y?

Wait,
12-4=8/5(6-1)?

Oh, y-12=8/5(x-6)?

y=8/5(x-6)-12?

it would be +12 right?
but distribute 8/5 to the parentheses as well to get slope-intercept form.

y=12+(8/5)*(x-6)?

yes now distribute the 8/5...

in order to get rid of the parentheses...

y=12+(8/5)x-6?

you forgot to distribute to the 6...

y=12+(8/5)x-(6)?

(8/5)(x-6)
distribute the 8/5 to each term, that is how distribution always works.

a(b+c)=ab+ac

But i did that before!

and what did you get?

Aw man, i need some sleep. school starts tomorrow and its 1:30am XD Im screwed!

lol
Thought so...
goodnight, good work :)

Goognight! Thanks again for teaching me all this :)