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Could somebody please help me study for a pre-algebra test? I have some questions.

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We will be here to answer your questions :)
Okay thanks! I really appreciate it.
Okay. sooo, this is really broad, but I don't understand negative exponents.... At all.

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Other answers:

So you got some specific questions or do you want me or us to explain you negative exponents from scratch?
Ummmmmmm. Why does a negative exponent make a fraction? I don't understand the basic concept.
Negative exponents simply means this: \[a^{-x} = {1 \over a^x}\]
yea slaaibak got it
Yes but why are they defined that way?
it is simple
do you know \[a^x \times a^y= a^{x+y}\]
now say we want \[a^x \times a^y = 1\]
Well yeah I do sorry.
You'd made one negative!!! AHHH I GET IT!
so when we solve that we get \[a^{x+y}= 1 = a^0\]
thats good! You get it :D
Teehee! Wow that just clicked. My math teacher didn't explain it that way.......
its my pleasure helping you click it :D
So another thing, how do you deal with #s with exponents in a fraction?
Give an example please?
Ummmm. How do you make fractions with this equation thing?
type over
3 over 4 \[3 \over 4\]
Use this code: {1 over 2} would be \[{1 \over 2}\]
... Um can I just say it?
yea what is your doubt? i do not comprehend it
yeah sure
Okay so if you had y^-5 times 2^3 over y^4 times x^2.
Or something to that effect.
\[ y^-5 \times 2^3 \over y^4 \times x^2.\]
\[{ y^{-5} * 2^3 \over y^4 * x^2}\]
is that your query?
Lol yeah.
You're faster than me xD
i am not lol
If there's multiplication, you can take y^-5 and but it below the line, \[y^{-5} = {1 \over y^5}\] You can immediately write 2^3 as 8. So now you have: \[{1 \over y^5} * {8 \over x^2 * y^4}\]
put*, not but
Then, you can multiply similar variables with eachother and add the powers. it becomes: \[8 \over y^9 * x^2\]
What are you talking about?
about the question you asked
I made a spelling mistake in my post.
Yeah but how did you get y^9?
I know you have to add... Or subtract the exponents or something.
\[y^4 * y^5 = y^{5 + 4}\]
OH okay.
the main aim of such questions is to convert your negative exponents into positive by taking its reciprocal
Um one more thing. How would you get {1 over 9} % of 90. Or something like that.
Aw shoot. I messed up the thing.
\[{1 \over 9}\]
percent is always divided by 100
so 1/9 percent is \[(1/9 ) \over 100 = 1\over900\]
of 90 is 1/900 of 90.. of implies multiplication
so it is 1/900 times 90 = 90/900 = 1/10
Yes yes I get it.
That makes sense! Okay that's all! And I have to go. Thank you so much. ^.^
it is my pleasure

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