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ameryn.love17

  • 2 years ago

Three vertices of a parallelogram are (-3,4),(-5,8),(1,-6) what the fourth vertex

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  1. sasogeek
    • 2 years ago
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    have you done vectors?

  2. ameryn.love17
    • 2 years ago
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    nope

  3. agdgdgdgwngo
    • 2 years ago
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    You can plot the points in the graph to visualize the problem better. One way to solve this problem is to compute the different slopes of the lines joining two vertices, using the point-slope formula \( slope = \frac{y_2-y_1}{x_2-x_1}\) and then look for the one which does share a slope with other points.

  4. sasogeek
    • 2 years ago
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    |dw:1326156907260:dw| A(-3,4) B(-5,8) C(1,-6) find D

  5. agdgdgdgwngo
    • 2 years ago
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    Ultimately there will be three possible parallelograms you can make.

  6. sasogeek
    • 2 years ago
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    how?

  7. agdgdgdgwngo
    • 2 years ago
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    You can flip the triangle formed by the 3 given points in 3 different ways to get three different paralellograms.

  8. sasogeek
    • 2 years ago
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    there's actually only one if 3 points are given... 2 lines will be made from the 3 points, u only need parallel lines to intersect to find the forth point

  9. sasogeek
    • 2 years ago
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    why would u flip it? it points remain where they are i suppose...

  10. sasogeek
    • 2 years ago
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    i was going to use vectors to solve this though but you've got no idea about vectors.... hmmm :/

  11. agdgdgdgwngo
    • 2 years ago
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    You can make a paralellogram by drawing the reflection of the triangle across one of its sides.

  12. agdgdgdgwngo
    • 2 years ago
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    like in vector addition!

  13. sasogeek
    • 2 years ago
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    reflection? ... i'm not sure why you're talking about reflections, why don't u just go ahead and find the parallel lines with respect to the initial triangle formed...

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