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 2 years ago
Three vertices of a parallelogram are (3,4),(5,8),(1,6) what the fourth vertex
 2 years ago
Three vertices of a parallelogram are (3,4),(5,8),(1,6) what the fourth vertex

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sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0have you done vectors?

agdgdgdgwngo
 2 years ago
Best ResponseYou've already chosen the best response.0You can plot the points in the graph to visualize the problem better. One way to solve this problem is to compute the different slopes of the lines joining two vertices, using the pointslope formula \( slope = \frac{y_2y_1}{x_2x_1}\) and then look for the one which does share a slope with other points.

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1326156907260:dw A(3,4) B(5,8) C(1,6) find D

agdgdgdgwngo
 2 years ago
Best ResponseYou've already chosen the best response.0Ultimately there will be three possible parallelograms you can make.

agdgdgdgwngo
 2 years ago
Best ResponseYou've already chosen the best response.0You can flip the triangle formed by the 3 given points in 3 different ways to get three different paralellograms.

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0there's actually only one if 3 points are given... 2 lines will be made from the 3 points, u only need parallel lines to intersect to find the forth point

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0why would u flip it? it points remain where they are i suppose...

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0i was going to use vectors to solve this though but you've got no idea about vectors.... hmmm :/

agdgdgdgwngo
 2 years ago
Best ResponseYou've already chosen the best response.0You can make a paralellogram by drawing the reflection of the triangle across one of its sides.

agdgdgdgwngo
 2 years ago
Best ResponseYou've already chosen the best response.0like in vector addition!

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.0reflection? ... i'm not sure why you're talking about reflections, why don't u just go ahead and find the parallel lines with respect to the initial triangle formed...
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