Here's the question you clicked on:
ameryn.love17
Three vertices of a parallelogram are (-3,4),(-5,8),(1,-6) what the fourth vertex
have you done vectors?
You can plot the points in the graph to visualize the problem better. One way to solve this problem is to compute the different slopes of the lines joining two vertices, using the point-slope formula \( slope = \frac{y_2-y_1}{x_2-x_1}\) and then look for the one which does share a slope with other points.
|dw:1326156907260:dw| A(-3,4) B(-5,8) C(1,-6) find D
Ultimately there will be three possible parallelograms you can make.
You can flip the triangle formed by the 3 given points in 3 different ways to get three different paralellograms.
there's actually only one if 3 points are given... 2 lines will be made from the 3 points, u only need parallel lines to intersect to find the forth point
why would u flip it? it points remain where they are i suppose...
i was going to use vectors to solve this though but you've got no idea about vectors.... hmmm :/
You can make a paralellogram by drawing the reflection of the triangle across one of its sides.
like in vector addition!
reflection? ... i'm not sure why you're talking about reflections, why don't u just go ahead and find the parallel lines with respect to the initial triangle formed...