anonymous
  • anonymous
solve this in simplest form 14x2y3. <-- the 2 and 3 are exponents. over 35xy2 <-- exponent too. so 14x2y3/35xy2
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
14x^(2)y^(3)/35(x)y^(2) 1/35x(y)^(2) = x^(-1)y^(-2)/35
anonymous
  • anonymous
remember the rule that 1/x = x^(-1) and when multiplying variables with exponents you add them
anonymous
  • anonymous
so bring the variables to the numerator 14x^(2)y^(3)x^(-1)y^(-2)/35

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anonymous
  • anonymous
now add the exponents to simplify, you do the next step im lazy

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